2 mũ 4 - 4 mũ 2=16-16=0

( 2 mũ 17 + 17 mũ 2 ) . ( 9 mũ 15 - 3 mũ 15 ).0=0

đ/s: 0

AI NHANH MÌNH K

162-23+17^17/7^26+17^26/17^26

139+1/(17^9)+1

140+1/(17^9)

(2¹⁷+17²).(9¹⁵-3¹⁵).(2⁴-4²⁰)

   13⁵.17³.a⁹.(13.17².a³)

= 13⁵.17³.13.17².a⁹.a³

= (13⁵.13).(17³.17²).(a⁹.a³)

= 13⁶.17⁵.a¹²

bn viết thế khó hiểu lắm

viết lại đi mik giải cho

a)5*2^2-18:3=20-6=14

b)17*85+15*17-120=17*(120-85+15)=17*20=340

c2^3*17-2^3*14=2^3(17-14)=8*3=24

Ta có:

\(A=\frac{17^{18}+1}{17^{19}+1}\)

\(\Rightarrow17A=\frac{17^{19}+1+16}{17^{19}+1}\)

\(\Rightarrow17A=1+\frac{16}{17^{19}+1}\)

\(B=\frac{17^{17}+1}{17^{18}+1}\)

\(\Rightarrow17B=\frac{17^{18}+1+16}{17^{18}+1}\)

\(\Rightarrow17B=1+\frac{16}{17^{18}+1}\)

Vì \(\frac{16}{17^{19}+1}< \frac{16}{17^{18}+1}\Rightarrow17A< 17B\)

\(\Rightarrow A< B\)

Vậy \(A< B\)

17ⁿ⁺² - 17ⁿ

= 17ⁿ( 17² - 1 )

= 17ⁿ( 289 - 1 )

= 17ⁿ.288

= 17ⁿ.12.24 chia hết cho 12 ( đpcm )

=(2¹⁷+15⁴) x (3¹⁹-2¹⁷) x 0

= 0 (Vì số nào nhân với 0 cũng bằng 0)

0 mus

0 bit

0 so

0 sao

0 xep

Ta có: \(M=17+17^2+\cdots+17^{18}\)

\(=\left(17+17^2\right)+\left(17^3+17^4+17^5+17^6\right)+\left(17^7+17^8+17^9+17^{10}\right)+\left(17^{11}+17^{12}+17^{13}+17^{14}\right)+\left(17^{15}+17^{16}+17^{17}+17^{18}\right)\)

\(=\left(17+289\right)+17^3\left(1+17+17^2+17^3\right)+17^7\cdot\left(1+17+17^2+17^3\right)+17^{11}\cdot\left(1+17+17^2+17^3\right)+17^{15}\cdot\left(1+17+17^2+17^3\right)\)

\(=306+5220\cdot\left(17^3+17^7+17^{11}+17^{15}\right)\)

=6+300+5220\(\left(17^3+17^7+17^{11}+17^{15}\right)\)

=>M chia 10 dư 6