Bài 1 : 

A ) 3 < x < 5

=> x thuộc  { 4 }

Vậy x = 4

Câu b và câu c cứ theo vậy mà làm .

Bài 2 : 

| x + 7 | = 0 

  x         = 0 - 7 

  x         = -7

Vậy x = -7

Bài 1:

a, 3<x<5 => x=4

b, -4 < x - 1 < 5

=> x-1 thuộc {-3;-2;-1;0;1;2;3;4}

=> x thuộc {-2;-1;0;1;2;3;4;5}

c, -8 < x+2 < -3

=> x+2 thuộc {-7;-6;-5;-4}

=> x thuộc {-9;-8;-7;-6}

\(a)\)\(\left[\left(8.x-12\right)\div4\right].3^3=3^6\)

\(\left[\left(8.x-12\right)\div4\right]=3^6\div3^3\)

\(\left[\left(8.x-12\right)\div4\right]=3^3\)

\(\left(8.x-12\right)\div4=27\)

\(\left(8.x-12\right)=27.4\)

\(8.x-12=108\)

\(8.x=108+12\)

\(8.x=120\)

\(x=120\div8\)

\(x=15\)

\(b)\)\(3^{2.x-4}-x^0=8\)

\(3^{2.x-4}-1=8\)

\(3^{2.x-4}=8+1\)

\(3^{2.x-4}=9\)

\(3^{2.x-4}=3^2\)

\(2.x-4=2\)

\(2.x=2+4\)

\(2.x=6\)

\(x=3\)

i) 58:252=58:(52)2=58:52.2=58:54=58−4=54

k) 49:642=49:(43)2=49:43.2=49:46=49−6=43

l) 225:324=225:(25)4=225:25.4=225:220=225−20=25

m) 1253:254=(53)3:(52)4=53.3:52.4=59:58=5

e) 38:36=38−6=32

f)  210:83=210:(23)3=210:23.3=210:29=210−9=2

g) 127:67=(12:6)7=27

h_ 215:813kết quả là số dư nên không tính ( đề sai )

a) 410.230=(22)10.230=22.10.230=220.230=220+30=250

b) 925.274.813=(32)25.(33)4.(34)3=33.25.33.4.34.3=375.312.312=375+12+12=399

c) 2550.1255=(52)50.(53)5=52.50.53.5=5100.515=5100+15=5115

d) 643.48.164=(43)3.48.(42)4=43.3.48.42.4=49.48.48=49+8+8=425

có quà nhé

QUA GI VAY

a.\(x^{10}\div x^0=x^{10}\div1=x^{10}\)

b.\(\left(x^7\times x^2\right)\div x=x^9\div x^1=x^8\)

Sai

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a)\(\frac{2x}{3}=\frac{3y}{4}=\frac{4z}{5}\Leftrightarrow\frac{x}{\frac{3}{2}}=\frac{y}{\frac{4}{3}}=\frac{z}{\frac{5}{4}}\)

Áp dụng tc dãy tỉ 

\(\frac{x}{\frac{3}{2}}=\frac{y}{\frac{4}{3}}=\frac{z}{\frac{5}{4}}=\frac{x+y+z}{\frac{3}{2}+\frac{4}{3}+\frac{5}{4}}=\frac{49}{\frac{49}{12}}=12\)

Với \(\frac{x}{\frac{3}{2}}=12\Rightarrow x=18\)

Với \(\frac{y}{\frac{4}{3}}=12\Rightarrow y=16\)

Với \(\frac{z}{\frac{5}{4}}=12\Rightarrow z=15\)

b)\(\frac{a}{2}=\frac{b}{3}=\frac{c}{4}\Leftrightarrow\frac{a^2}{4}=\frac{b^2}{9}=\frac{2c^2}{32}\)

Áp dụng tc dãy tỉ

\(\frac{a^2}{4}=\frac{b^2}{9}=\frac{2c^2}{32}=\frac{a^2-b^2+2c^2}{4-9+32}=\frac{108}{27}=4\)

Với \(\frac{a^2}{4}=4\Rightarrow a=4\)

Với \(\frac{b^2}{9}=4\Rightarrow b=6\)

Với \(\frac{2c^2}{32}=4\Rightarrow c=8\)

n sẽ bằng -16 chuc ban manh khoe

\(x^2-6^2=8^2\)

\(\Rightarrow\left(x-6\right)\left(x+6\right)=8^2\)

\(\Rightarrow\left(x-6\right)\left(x+6\right)=64\)

Tìm x biết

a,(x+1)⁴ =(x+1)²

            x= 0

a)F(x)+G(x)-H(x)=(x^3-2x^2+3x+1)+(x^3+x-1)-(2x^2-1)

=x^3-2x^2+3x+1+x^3+x-1-2x^2+1

=(x^3+x^3)+(-2x^2-2x^2)+3x+(1-1+1)

=2x^3+(-4x^2)+3x+1