\(=\sqrt{3}-1+\sqrt{\left(6-\sqrt{3}\right)^2}=\sqrt{3}-1+6-\sqrt{3}=5\)

\(\sqrt{\left(\sqrt{3}-1\right)^2}+\sqrt{39-2\sqrt{108}}\)

\(=\sqrt{3}-1+6-\sqrt{3}\)

=5

a) \(\dfrac{-3}{5}\)

b) \(\dfrac{1}{3}\)

c) \(\dfrac{28}{95}\)

d) \(\dfrac{7}{5}\)

e) \(\dfrac{4}{7}\)

a,-3/5

b,5/9

c,28/95

d,7/5

e,4/7

D. \(\dfrac{1}{2}\)

1/2

\(a) \frac{1}{4};\frac{3}{7};\frac{101}{131}\)

\(15\div\frac{15}{45}\div15=\frac{1}{3}\)
 

\(\frac{72}{90}=72\div\frac{18}{90}\div18=\frac{4}{5}\)
 

\(50\div\frac{10}{120}\div10=\frac{5}{12}\)

1000000000000% đúng nha

20/50 + 5/15                72/90 + 7/28             32/96 + 8/28

= 2/5 + 1/3                 = 4/5 + 1/4               = 1/3 + 2/7

= 11/15                       = 21/20                    = 13/21

 \(\frac{20}{50}+\frac{5}{15}\\ =\frac{2}{5}+\frac{1}{3}\\ =\frac{6}{15}+\frac{5}{15}=\frac{11}{15}\)

A, x=65*3/39=5

B, x=108*8/72=12

\(\frac{72^3\times54^2}{108^4}\)

\(=\frac{\left(2^3\times3^2\right)^3\times\left(2\times3^3\right)^2}{\left(2^2\times3^3\right)^4}\)

\(=\frac{2^9\times3^6\times2^2\times3^6}{2^8\times3^{12}}\)

\(=\frac{2^{11}\times3^{12}}{2^8\times3^{12}}\)

\(=\frac{2^3}{1}\)

\(=\frac{8}{1}=8\)

1. 2^36.2^45=2^81

2. 2^30.5^30=10^30

\(4^{18}.8^{15}=\left(2^2\right)^{18}.\left(2^3\right)^{15}\)

\(=2^{36}.2^{45}\)

\(=2^{81}\)

\(4^{15}.5^{30}=\left(2^2\right)^{15}.5^{30}\)

\(=2^{30}.5^{30}\)

\(=\left(2.5\right)^{30}\)

\(=10^{30}\)

\(\frac{3.72^2.54^2}{108^4}=\frac{3.\left(3^2.2^3\right)^2.\left(3^3.2\right)^2}{\left(3^3.2^2\right)^4}\)

\(=\frac{3.3^4.2^6.3^6.2^2}{3^{12}.2^8}\)

\(=\frac{3^{11}.2^8}{3^{12}.2^8}\)

\(=\frac{1}{3}\)

a: \(=6\sqrt{2}-12\sqrt{3}-10\sqrt{2}+12\sqrt{3}=-4\sqrt{2}\)

b: \(=\sqrt{\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)}=\sqrt{4-3}=1\)