2|5x−3|−2x=14 
Xét 5x−3≥0 <=> x≥35
 => 2(5x−3)−2x=14
<=> 10x−6−2x=14
<=> 8x=20
<=> x=208=52 (thoả mãn)
Xét 5x−3<0 => x<35
 => 2(3−5x)−2x=14
<=> 6−10x−2x=14
<=> −12x=8
<=> x=−812=−23 (thoả mãn)

èo... bạn ko viết dấu nhân,mãi mk mới hiểu !!

a) x+3=12

x=12-3

x=9

b)(x-3):2=5¹⁴:5¹²

=>(x-3):2=5²

=>(x-3):2=25

=>x-3=25.2

=>x-3=50

=>x=50+3

=>x=53

c)4x+3x=30-20:10

=>x(4+3)=30-2

=>7x=28

=>x=28:7

=>x=4

d)2x-138=2³.3²

=>2x-138=8.9

=>2x-138=72

=>2x=72+138

=>2x=210

=>x=210:2

=>x=105

a) x + 3 = 12

x = 12 - 3

x = 9

b) ( x - 3 ) : 2 = 5¹⁴ : 5¹²

( x - 3 ) : 2 = 5^14-12

( x - 3 ) : 2 = 5²

( x - 3 ) : 2 = 25

x - 3 = 50

x = 53

c) 4x + 3x = 30 - 20 : 10

7x = 28

x = 4

d) 2x - 138 = 2³ x 3²

2x - 138 = 8 x 9

2x - 138 = 72

2x = 210

x = 105

1/2=2/4 , 1/14=2/28 , 1/35=2/70

ta có: 2/4=2/1.4 , 2/28=2/4.7 , 2/70=2/7.10 ................

thay vào ta có:  2/1.4+2/4.7+2/7.10+........+2/x(x+3)=1340/2011

2.(1/1.4+1/4.7+1/7.10+....+1/x(x+3)=1340/2011

2.3.(1/1.4+1/4.7+1/7.10+....+1/x(x+3)=(1340/2011).3

2.(3/1.4+3/4.7+3/7.10+......+3/x(x+3)=4020/2011

2.(1- 1/4 + 1/4- 1/7 + 1/7- 1/10 +.......+1/x - 1/x+3)=4020/2011

1-1/x+3 =4020/2011 :2= 2010/2011

1- 2010/2011=1/x+3

1/2011=1/x+3

x+3= 2011

x=2008

1, 3n + 14 chia hết cho n + 1

Mà n + 1 chia hết cho n + 1 => 3(n + 1) chia hết cho n + 1

Từ 2 điều trên => (3n + 14) - 3(n + 1) chia hết cho n + 1

=> 3n + 14 - 3n - 3 chia hết cho n + 1

=> (3n - 3n) + (14 - 3) chia hết cho n + 1

=> 11 chia hết cho n + 1

=>n + 1 E Ư(11)

=> n + 1 E {-1; 1; -11; 11}

=> n E {-2; 0; -12; 10}

Vậy...

   thấy hay thì tick nhé mọi người 

\(1,x^2+4x+4=0\\ \Rightarrow\left(x+2\right)^2=0\\ \Rightarrow x+2=0\\ \Rightarrow x=-2\\ 2,x^2+4x+4=0\\ \Rightarrow\left(x+2\right)^2=0\\ \Rightarrow x+2=0\\ \Rightarrow x=-2\\ 3,\left(x+1\right)^2+2\left(x+1\right)=0\\ \Rightarrow\left(x+1\right)\left(x+1+2\right)=0\\ \Rightarrow\left(x+1\right)\left(x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\x+3=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=-3\end{matrix}\right.\)

x²+4x+4=0
(x+2)²=0
x+2=0
x=+-2
câu 1 giống câu 2
(x+1)²+2(x+1)=0
(x+1+2)(x+1)=0
Th1: x+3=0           Th2: x+1=0
            x=-3                      x=-1
vậy ...

(x+3)(x-2)+3x=4(x+3/4)

x(x+3)-2(x+3)+3x=4x+3

x²+3x-2x-6+3x-4x=3

x²+(3x-2x+3x-4x)-6=3

x²-6=3

x²=9

x²=3²

=>x=|3|

x=3 hoặc x=-3

\(\left(x+3\right)\left(x-2\right)+3x=4\left(x+\frac{3}{4}\right)\)

\(\Rightarrow x^2-2x+3x-6+3x=4x+3\)

\(\Rightarrow x^2+4x-6=4x+3\)

\(\Rightarrow x^2-6=3\)

\(\Rightarrow x^2=3+6=9\)

\(\Rightarrow x=-3\)hoặc \(x=3\)

\(\Leftrightarrow2\sqrt{x-4}=5\left(x\ge4\right)\\ \Leftrightarrow\sqrt{x-4}=\dfrac{5}{2}\\ \Leftrightarrow x-4=\dfrac{25}{4}\\ \Leftrightarrow x=\dfrac{41}{4}\left(tm\right)\)

cảm ơn nha