ta có

(1/3+1/6+1/36) +(1/10+1/15+1/45)+(1/21+1/28)

=(\(\frac{12+6+1}{36}\)+\(\frac{9+6+2}{90}\)+\(\frac{4+3}{84}\)

19/36+17/90+1/12

=(19/36+1/12)+17/90

=7/12+17/90

=105/180+34/180

=139/180

1/3 +1/6+1/10+1/15+1/21+1/28+1/36+1/45

=1/1x3+1/3x2+1/2x5+1/3x5+1/3x7+1/7x4+1/4x9+1/9x5

=1/1-1/3+1/3-1/2....+1/9-1/5

=1/1

0

0

\(\dfrac{-5}{10}+\dfrac{12}{28}-\dfrac{3}{27}-\dfrac{7}{18}+\dfrac{20}{35}\\ =\left(\dfrac{-1}{2}-\dfrac{1}{9}-\dfrac{7}{18}\right)+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\\ =\left(\dfrac{-9}{18}-\dfrac{2}{18}-\dfrac{7}{18}\right)+\dfrac{7}{7}\\ =\dfrac{-18}{18}+1\\ =\left(-1\right)+1\\ =0\)

8757577

3/4+1/2+5/8=15/8

5/9+9/8-15/28=577/504

11/30-9/25x15/27=1/6

3/4:5/8:3/10=4

a) ( 2011 - 125 x 8 : 4 ) x ( ( 48 : 8 x 6 )

= ( 2011 - 1000 : 4 ) x ( 6 x 6 )

= ( 2011 - 250 ) x 36

= 1761 x 36

= 63396

b) B = Không hiểu

c) C = 

Áp dụng định lý Pi-ta-go ta có:
\(AB^2+AC^2=BC^2\\ \Rightarrow21^2+28^2=BC^2\\ \Rightarrow BC=\sqrt{21^2+28^2}\\ \Rightarrow BC=35\left(cm\right)\)

\(BC=\sqrt{AB^2+AC^2}=35\left(cm\right)\)

\(\frac{8}{15}\)+\(\frac{2}{3}\)=\(\frac{8}{15}\)+\(\frac{10}{15}\)=\(\frac{18}{15}\)=\(\frac{6}{5}\)

KHUM PÉ ƠI MIK HIN NHỖI MIK KO GẢNH ĐỂ GẢI CHO BẠN GÒI

Giúp 

a) \(\dfrac{2}{9}+\dfrac{3}{5}-\dfrac{1}{15}=\dfrac{37}{45}-\dfrac{1}{15}=\dfrac{37}{45}-\dfrac{3}{45}=\dfrac{34}{45}\)

b) \(\dfrac{5}{12}\times\dfrac{4}{5}\div4=\dfrac{1}{3}\div4=\dfrac{1}{12}\)

c) \(\dfrac{8}{9}-\dfrac{4}{15}\div\dfrac{2}{5}=\dfrac{8}{9}-\dfrac{2}{3}=\dfrac{8}{9}-\dfrac{6}{9}=\dfrac{2}{9}\)