\(\frac{7}{10}\)< \(\frac{9}{10}\)

\(\frac{92}{100}\)> \(\frac{87}{100}\)

\(\frac{5}{10}\)= \(\frac{50}{100}\)

\(\frac{8}{10}\)> \(\frac{29}{100}\)

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a: \(=\dfrac{2^9\cdot5^9\cdot3^{40}}{2^{12}\cdot5^{10}\cdot3^{20}}=\dfrac{3^{20}}{5\cdot2^3}\)

b: \(=\dfrac{-3^8\cdot2^{10}\cdot5^6}{2^9\cdot\left(-1\right)\cdot3^6\cdot5^7}=\dfrac{-2}{5}\cdot3^2=-\dfrac{18}{5}\)

c: \(=\dfrac{3^{186}\cdot5^{100}}{5^{100}\cdot3^{187}}=\dfrac{1}{3}\)

a, 2¹⁰⁰ và 1024⁹

    1024⁹ = (2¹⁰)⁹ = 2⁹⁰

     2¹⁰⁰   > 2⁹⁰

Vậy 2¹⁰⁰ > 2⁹⁰

b, 5³⁰ và 6.5²⁹

    6.5²⁹  > 5.5²⁹  = 5³⁰ 

     vậy 5³⁰  < 6.5²⁹

 c, 2⁹⁸ và 9⁴⁹

    (2²)⁴⁹ = 4⁴⁹ < 9⁴⁹ 

     vậy: 2⁹⁸ < 9⁴⁹

d, 10³⁰ và 2¹⁰⁰

    (10³)¹⁰ = 1000¹⁰ 

      2¹⁰⁰ = (2¹⁰)¹⁰ = 1024¹⁰

     Vì 1000¹⁰ < 1024¹⁰ 

     Nên 10³⁰ < 2¹⁰⁰

7/10 < 9/10

5/10 = 50/100 = 50/100

92/100 > 87/100

8/10 = 80/100 > 29/100

7/10<9/10       92/100>87/100       5/10=50/100       8/10>29/100

Chúc bạn học tốt ^^

(11 / 29 + 2 / 29 + 16 / 29 ) . 9 / 10

1 . 9/10 = 9/10

\(\dfrac{9}{10}\times\left(\dfrac{11}{29}+\dfrac{2}{29}+\dfrac{16}{29}\right)=\dfrac{9}{10}\times\dfrac{29}{29}=\dfrac{9}{10}\times1=\dfrac{9}{10}\)

a) \(0,5\)Và \(\frac{51}{100}\)

\(0,5=\frac{5}{10}=\frac{50}{100}\)

\(\frac{50}{100}< \frac{51}{100}\)

\(\Rightarrow0,5< \frac{51}{100}\)

b) ko rõ đề

c) \(\frac{15}{37}\)Và \(\frac{10}{29}\)

\(\Leftrightarrow\frac{435}{1073}>\frac{370}{1073}\)

\(\Rightarrow\frac{15}{37}>\frac{10}{29}\)

d) \(\frac{295}{118}\)Và \(\frac{280}{133}\)

\(\frac{39235}{15694}>\frac{33040}{15694}\)

\(\Rightarrow\frac{295}{118}>\frac{280}{133}\)

Dấu cần điền vào ô trống là =

a/[25-(-75)]+32-(32+55)

=[25+75]+32-(32+55)

=25+75+32-32-55

=[25+75]+[32-32]-55

=100+0-55

=100-55

=45