7/23.5/29+7/29.18/23-7/29

=(7.5)/(23.29)+7/29.18/23-7/29

=7/29.5/23+7/29.18/23-7/29.1

=7/29.(5/23+18/23-1)

=7/29.(1-1)

=7/29.0

=0

\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)

\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)

\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)

\(=\frac{7}{29}\cdot0\)

\(=0\)

\(\frac{29}{9}.\frac{109}{7}-\frac{29}{9}.\frac{57}{7}+\frac{29}{9}.\frac{12}{7}-\frac{29}{9}.\frac{1}{7}\)

= \(\frac{29}{9}.\left(\frac{109}{7}-\frac{57}{7}+\frac{12}{7}-\frac{1}{7}\right)\)

= \(\frac{29}{9}.\frac{63}{7}\)

=\(\frac{29}{9}.9\)

=\(\frac{29.9}{9}\)

=\(\frac{261}{9}\)

= \(29\)

hứ 7 nộp rùi giải giúp mình à

Được cập nhật 10 giờ trước (09:01)

Toán lớp 6

Chau Nguyen Van 9 giờ trước (09:40)
 Báo cáo sai phạm

299 .1097 −299 .577 +299 .127 −299 .17 

= 299 .(1097 −577 +127 −17 )

= 299 .637 

=299 .9

=29.99 

=2619 

= 

\(\dfrac{8}{13}-\dfrac{7}{29}-\dfrac{8}{13}+\dfrac{7}{29}+\dfrac{2019}{2020}=\left(\dfrac{8}{13}-\dfrac{8}{13}\right)-\left(\dfrac{7}{29}+\dfrac{7}{29}\right)+\dfrac{2019}{2020}=0-0+\dfrac{2019}{2020}=\dfrac{2019}{2020}\)

(-8/13 + 8/13)+(-7/29 + 7/29)+2019/2020

=2019/2020

\(\dfrac{-7}{11}\cdot\dfrac{27}{29}+\dfrac{-7}{11}\cdot\dfrac{2}{29}+1\dfrac{1}{2}\)

\(=\dfrac{-7}{11}+\dfrac{3}{2}\)

\(=\dfrac{-14+33}{22}\)

\(=\dfrac{19}{22}\)

mình nghi thiếu dấu cộng sorry các bạn

4

4

Ta có: \(-\frac{7}{29}+2\frac14+73\frac{7}{29}+\frac59:\left(-4\frac17\right)\)

\(=-\frac{7}{29}+73+\frac{7}{29}+2+\frac14+\frac59:\frac{-29}{7}\)
\(=75+\frac14+\frac59\cdot\frac{-7}{29}=75+\frac14-\frac{35}{261}=75+\frac{261-140}{4\cdot261}=75+\frac{121}{1044}\)

\(=\frac{75\cdot1044+121}{1044}=\frac{78421}{1044}\)

 -29.(85-47)-85.(47-29)

=-29.38-85.18

=-1102-1503

=-2605

-15.(23-29)+23-(15-29)

=-15.(-6)+23-(-14)

=90+23+14

=113+14

=127

 -13.(55-29)+23.(15-29)

=-13.26+23.(-14)

=-338+(-322)

=-660

-10.(2+4)-5.(4-3)

=-10.6-5.1

=-60-5

=-65