7/13*-3/5-7/13*(-0,2)-7/13*8/5
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Lời giải:
$=(\frac{3}{5}+\frac{2}{5})+(\frac{5}{11}+\frac{16}{11})+(\frac{7}{13}+\frac{19}{13})$
$=\frac{5}{5}+\frac{22}{11}=\frac{26}{13}=1+2+2=5$
\(=\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{17}+\dfrac{1}{11}\right)}=\dfrac{3}{13}\)
\(\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\)
\(=\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}{13\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{11}\right)}\)
\(=\dfrac{3}{13}\)
4/7.(8/-13)+4/7(-2/13)+1 3/13(-4/7)
= 4/7(-8/13-2/13+1)
=4/7. 3/13 =12/91
\(M=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{13}{4}-\frac{13}{5}+\frac{13}{7}+\frac{13}{11}}\)
\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{11}\right)}{13.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}\)
\(=\frac{3}{13}\)
\(\frac{7}{13}\) x - \(\frac35\) - \(\frac{7}{13}\) x (-0,2) - \(\frac{7}{13}\) x \(\frac85\)
= \(\frac{7}{13}\) x (- \(\frac35\) + \(\frac15\) - \(\frac85\))
= \(\frac{7}{13}\) x (- \(\frac25\) - \(\frac85\))
= \(\frac{7}{13}\) x (- 2)
= - \(\frac{14}{13}\)