5x = 40 + (-15)

5x = 25

x = 25 : 5

x = 5

5-x-16=40+x

-x-x=40+16-5

(-x).2=51

-x=51/2=>x=51/2

1.x=40

2.x=10

3.x=

a) 2x - 16 = 40 + x

x - 2x = -16 - 40

-x = -56

x = 56

a) 2x - 16 = 40 + x

x - 2x = -16 - 40

-x = -56

x = 56

Nhìu quá bạn ơi

nhiều vậy ai mà làm dc bạn ơi

+) 5x - 16 = 40 + x

<=> 5x - x = 16 + 40

<=> 4x = 56

<=> x = 56 : 4

<=> x= 14

+) 3x - 6 = 5x + 2

<=> 3x - 5x = 6 + 2

<=> -2x = 8

<=> x =- 4

+) x + 15 = 20 - 4x

<=> x + 4x = 20 - 15

<=> 5x = 5

<=> x= 1 

+) -12 + x = 5x -20

<=> x - 5x = 12 - 20

<=> -4x = -8

<=> x= 2

T^T , T sai chỗ nào vậy

5x-16=40+x

=> 5x-16-x = 40

=> 5x-x -16=40

4x-16=40

4x= 40+16

4x=56

x= 56:4

x=14

Vậy...

4x-10=15-x

=> 4x-10+x= 15

4x+x -10=15

5x= 15+10

5x= 25

x= 25:5

x=5

Vậy....

a)11-(15+11)=x-(25-9)

11-26=x-16

-15=x-16

x=-15+16

x=1

vậy x=1

b)2-x=17-(-5)

2-x=22

x=2-22

x=-24

vậy x=-24

c)lxl-7=9

lxl=9+7

lxl=16

=>x=+-16

vậy x=+-16

d)3x-40=5x+32

3x-5x=40+32

(3-5)x=72

-2x=72

x=72:(-2)

x=-36

vậy x=-36

sao dễ zữ vậy

\

+ \(5x-16=40+x\)

⇒ \(5x-x=40+16\)

⇒ \(4x=56\)

⇒ \(x=\frac{56}{4}\)

⇒ \(x=16\)

+ \(4x-10=15-x\)

⇒ \(4x+x=15+10\)

⇒ \(5x=25\)

⇒ \(x=\frac{25}{5}\)

⇒ \(x=5\)

+ \(-12+x=5x-20\)

⇒ \(x-12=5x-20\)

⇒ \(x=5x-20+12\)

⇒ \(x=5x-32\)

⇒ \(5x-x=32\)

⇒ \(4x=32\)

⇒ \(x=\frac{32}{4}\)

⇒ \(x=8\)

+ \(7x-4=20+3x\)

⇒ \(7x-3x=20+4\)

⇒ \(4x=24\)

⇒ \(x=\frac{24}{4}\)

⇒ \(x=6\)

+ \(5x-7=-21-2x\)

⇒ \(5x+2x=-21+7\)

⇒ \(7x=14\)

⇒ \(x=\frac{14}{7}\)

⇒ \(x=2\)

+ \(x+15=7-6x\)

⇒ \(x+6x=7-15\)

⇒ \(7x=-8\)

⇒ \(x=-\frac{8}{7}\)

\(5x+40:2=45\)

\(5x+20=45\)

\(5x=45-20\)

\(5x=25\)

\(x=25:5\)

\(x=5\)

_______

\(x+30=40-2.5^2\)

\(x+30=40-2.25\)

\(x+30=40-50=-10\)

\(x=\left(-10\right)-30\)

\(x=-40\)

bạn tui làm đúng ghê!!!

@Phương

Áp dụng theo quy tắc chuyển vế

a) 5x - 16 = 40 + x

x - 5x = -16 - 40

-4x = -56

x = 14

b) 4x - 10 = 15 - x

-x - 4x = -10 - 15

-5x = -25

x = 5

c) x + 15 = 20 - 4x

-4x - x = 15 - 20

-5 x = -5

x= 1 

d) 17x = 7 - 6x

-6x - 17x = -7

-23x = -7

x = 7/23

Đúng rồi