3: 

\(=\dfrac{1}{7}\cdot\dfrac{3}{5}\cdot\dfrac{5}{6}\cdot\dfrac{5}{8}=\dfrac{1}{7}\cdot\dfrac{1}{2}\cdot\dfrac{5}{8}=\dfrac{5}{112}\)

4:

=>2/3:x=-2-1/3=-7/3

=>x=-2/3:7/3=-2/7

5:

AC=CB=12/2=6cm

IB=6/2=3cm

a. x - (17 - 8) = 5 + (10 - 3x)

=> x - 9 = 5 + 10 - 3x

=> x + 3x = 15 + 9

=> 4x = 24

=> x = 6

b. 25 - (30 + x) = x - (27 - 8)

=> 25 - 30 - x = x - 19

=> -x -x = -19 + 30 - 25

=> -2x = -14

=> x = 7

c. (x - 12) - 15 = (20 - 7) - (18 + x)

=> x - 12 - 15 = 13 - 18 - x

=> x + x = 13 - 18 + 12 + 15

=> 2x = 22

=> x = 11

Cảm ơn nhé bạn Minh Hiền!

a,x-(20-3x)=x+7

=>x-20+3x=x+7

=>x-20+3x-x=7

=>x+3x-x=7+20

=>3x=27

=>x=27:3

=>x=9

bai toan lop 6 nay kho qua ?

a) 3x -(-5)=20

3x+5=20

3x=20-5

3x=15

x=15/3

x=5

b) 4-7x =(-3).8

4-7x =(-24)

7x=4-(-24)

7x=28

x=28/7

x=4

c) Các số nguyên x thỏa mãn |x|<3 là -2;-1;0;1;2

d) Các số nguyên x thỏa mãn -5<x<1 là -4;-3;-2;-1;0;1

tick nha

\(\frac{x-1}{x^2-9x+20}+\frac{2x-2}{x^2-6x+8}+\frac{3x-3}{x^2-x-2}+\frac{4x-4}{x^2+6x+5}=0\)

\(\Leftrightarrow\frac{x-1}{\left(x-5\right)\left(x-4\right)}+\frac{2\left(x-1\right)}{\left(x-4\right)\left(x-2\right)}+\frac{3\left(x-1\right)}{\left(x-2\right)\left(x+1\right)}+\frac{4\left(x-1\right)}{\left(x+1\right)\left(x+5\right)}=0\)

\(\Leftrightarrow\left(x-1\right)\left(\frac{10}{x^2-25}\right)=0\)

\(\Leftrightarrow x-1=0\)

\(\Leftrightarrow x=1\)  

PS: Điều kiện xác đinh bạn tự làm nhé 

=> 3x - 12 = 4x - 20

=> 3x = 4x - 20 + 12 = 4x - 8

=> 8 = 4x - 3x

=> x = 8

Tk mk nha

Ta có: \(\left|3x-5\right|\ge0\forall x\)

\(\left(2y+5\right)^{20}\ge0\forall y\)

\(\left(4z-3\right)^{206}\ge0\forall z\)

Do đó: \(\left|3x-5\right|+\left(2y+5\right)^{20}+\left(4z-3\right)^{206}\ge0\forall x,y,z\)

Dấu '=' xảy ra khi \(x=\dfrac{5}{3};y=-\dfrac{5}{2};z=\dfrac{3}{4}\)

a)

3x(8x-4)-6x(4x-3)=30

=> 6x(4x-2)-6x(4x-3)=30

=> 6x(4x-2-4x+3)=30

=> 6x=30

=> x=5

b)

3x(5-2x)+2x(3x-5)=20

\(15x-6x^2+6x^2-10x=20\)

\(5x=20\)

\(x=4\)

3 nhân x hay 3x thế bạn

\(\frac{3x}{2.5}+\frac{3x}{5.8}+\frac{3x}{8.11}+\frac{3x}{11.14}=\frac{1}{21}\)

=> \(x\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}\right)=\frac{1}{21}\)

=> \(x\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}\right)=\frac{1}{21}\)

=> \(x\left(\frac{1}{2}-\frac{1}{14}\right)=\frac{1}{21}\)

=> \(x.\frac{3}{7}=21\)

=> x = 49 

Vậy x = 49

Xin lỗi bạn nhé x = 1/9 bước cuối mình ghi sót