a: =>x-22=9

hay x=31

c.\(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)

\(\dfrac{5}{7}:x=\dfrac{1}{3}-\dfrac{3}{7}\)

\(\dfrac{5}{7}:x=-\dfrac{2}{21}\)

\(x=\dfrac{5}{7}:-\dfrac{2}{21}\)

\(x=-\dfrac{15}{2}\)

d.\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)

\(\left|2x-\dfrac{5}{12}\right|=3\dfrac{1}{4}:\dfrac{39}{16}\)

\(\left|2x-\dfrac{5}{12}\right|=\dfrac{4}{3}\)

\(\rightarrow\left[{}\begin{matrix}2x-\dfrac{5}{12}=\dfrac{4}{3}\\2x-\dfrac{4}{12}=-\dfrac{4}{3}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{4}\\2x=-\dfrac{11}{12}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}x=\dfrac{7}{8}\\x=-\dfrac{11}{24}\end{matrix}\right.\)

A, \(\dfrac{4}{9}+x=\dfrac{5}{3}\)

\(x\)\(=\dfrac{5}{3}-\dfrac{4}{9}\)

\(x\)\(=\dfrac{11}{9}\)

B,\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)

\(x=\dfrac{-1}{2}:\dfrac{3}{4}\)

\(x=\)\(\dfrac{-2}{3}\)

\(2\left(x-5\right)+3\left(2-3x\right)=5x+7\)

\(\Leftrightarrow2x-10+6-9x=5x+7\)

\(\Leftrightarrow\left(2x-9x\right)+\left(6-10\right)=5x+7\)

\(\Leftrightarrow-7x-4=5x+7\)

\(\Leftrightarrow-7x-5x=4+7\)

\(\Leftrightarrow-12x=11\)

\(\Leftrightarrow x=\frac{-11}{12}\)

\(3x-5\left(x-2\right)+7=4x-12\)

\(\Leftrightarrow3x-5x-10+7=4x-12\)

\(\Leftrightarrow\left(3x-5x\right)-\left(10-7\right)=4x-12\)

\(\Leftrightarrow-2x-3=4x-12\)

\(\Leftrightarrow-2x-4x=3-12\)

\(\Leftrightarrow-6x=-15\)

\(\Leftrightarrow x=\frac{-15}{-6}=\frac{5}{2}\)

Ta có: \(\left\lbrace\left\lbrack\left(x^3-17\right)^2-98\right\rbrack^3-6\right\rbrace^5=32\)

=>\(\left\lbrack\left(x^3-17\right)^2-98\right\rbrack^3-6=2\)

=>\(\left\lbrack\left(x^3-17\right)^2-98\right\rbrack^3=2+6=8=2^3\)

=>\(\left(x^3-17\right)^2-98=2\)

=>\(\left(x^3-17\right)^2=100\)

=>\(\left[\begin{array}{l}x^3-17=10\\ x^3-17=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x^3=27\\ x^3=7\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\left(nhận\right)\\ x=\sqrt[3]{7}\left(loại\right)\end{array}\right.\)

Tổng A có số số hạng là: (2019-1):2+1= 1010 số

Tổng A là: 1010.(2019+1):2=1020100

:))

số số hạng dãy trên là 

\(\left(2019-1\right):2+1=1010\)

tổng dãy trên là 

\(\left(2019+1\right).1010:2=1020100\)

vậy \(A=1+3+5+7+9+...+2017+2019=1020100\)

\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)

\(\frac{1}{3}:\left(2x-1\right)=-5-\frac{1}{4}\)

\(\frac{1}{3}:\left(2x-1\right)=-\frac{20}{4}-\frac{1}{4}\)

\(\frac{1}{3}:\left(2x-1\right)=-\frac{21}{4}\)

\(\left(2x-1\right)=\frac{1}{3}:-\frac{21}{4}\)

\(\left(2x-1\right)=\frac{1}{3}.-\frac{4}{21}\)

\(\left(2x-1\right)=-\frac{4}{63}\)

2x= -4/63 + 1

2x = 59/63

x = 59/63 : 2

x = 59/126

1/3:(2.x-1)=-5-1/4

1/3:(2.x-1)=-21/4

2.x-1=1/3:-21/4

2.x-1=-4/63

2.x=-4/63+1

2.x=\(3\frac{59}{63}\)

x=\(3\frac{59}{63}\):2

x=\(1\frac{61}{63}\)

em khong biet lam vi em chi moi lop4

bài này lớp mấy vậy

a) \(x+\frac{4}{5}=\frac{3}{2}\)

\(\Rightarrow x=\frac{3}{2}-\frac{4}{5}\)

\(\Rightarrow x=\frac{7}{10}\)

Vậy \(x=\frac{7}{10}.\)

b) \(x-\frac{3}{2}=\frac{11}{4}\)

\(\Rightarrow x=\frac{11}{4}+\frac{3}{2}\)

\(\Rightarrow x=\frac{17}{4}\)

Vậy \(x=\frac{17}{4}.\)

c) \(\frac{25}{3-x}=\frac{5}{6}\)

\(\Rightarrow\left(3-x\right)5=25.6\)

\(\Rightarrow15-5x=150\)

\(\Rightarrow5x=15-150\)

\(\Rightarrow5x=-135\)

\(\Rightarrow x=-135:5\)

\(\Rightarrow x=-27\)

Vậy \(x=-27.\)

ai giúp mình câu c đi