\(a,=\left(2x-1\right)^2\\ b,=2\left(8y^3-x^3-3x^2-3x-1\right)\\ =2\left[8y^3-\left(x+1\right)^3\right]\\ =2\left(2y-x-1\right)\left[4y^2+2y\left(x+1\right)+\left(x+1\right)^2\right]\\ =2\left(2y-x-1\right)\left(4y^2+2xy+2y+x^2+2x+1\right)\\ c,=2x^2+2x+5x+5=\left(x+1\right)\left(2x+5\right)\\ d,=\left(x-3y\right)^2-25z^2=\left(x-3y-5z\right)\left(x-3y+5z\right)\)

Mình cảm ơn :D

bài nào?

bài đâu

`#3107.101107`

`4.`

`a.`

m_Zn + m_HCl = m_{ZnCl\(_2\)} + m_{H\(_2\)}

`b.`

`@` Theo định luật bảo toàn khối lượng

\(m_{Zn}+m_{HCl}=m_{ZnCl_2}+m_{H_2}\)

`=>`\(26+\text{HCl}=54,4+0,8\)

`=>`\(\text{HCl}=54,4+0,8-26\)

`=>`\(\text{HCl}=55,2-26\)

`=>`\(\text{HCl}=29,2\left(g\right)\)

Vậy, khối lượng của HCl trong pứ trên là `29,2` g.

i)\(\left\{{}\begin{matrix}ab=2\\a^3+b^3=9\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}ab=2\\\left(a+b\right)^3-3ab\left(a+b\right)=9\end{matrix}\right.\)

\(\Rightarrow\left(a+b\right)^3-6\left(a+b\right)-9=0\)

\(\Leftrightarrow\left(a+b\right)^3-3\left(a+b\right)^2+3\left(a+b\right)^2-9\left(a+b\right)+3\left(a+b\right)-9=0\)

\(\Leftrightarrow\left(a+b-3\right)\left[\left(a+b\right)^2+3\left(a+b\right)+3\right]=0\)

\(\Leftrightarrow a+b=3\)( \(\left(a+b\right)^2+3\left(a+b\right)+3>0;\forall a,b\)

ii) \(\left\{{}\begin{matrix}a+b+ab=23\\a^2+b^2=34\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}ab=23-\left(a+b\right)\\\left(a+b\right)^2-2ab=34\end{matrix}\right.\)

\(\Rightarrow\left(a+b\right)^2-2\left[23-\left(a+b\right)\right]=34\)

\(\Leftrightarrow\left(a+b\right)^2+2\left(a+b\right)-80=0\)

\(\Leftrightarrow\left(a+b-8\right)\left(a+b+10\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}a+b=8\\a+b=-10\end{matrix}\right.\)

bài nào

Bài nìu

bài 35 nhưng mà là sách nào ????

Sách "Kết Nối Tri Thức" á !!!

duy khoa oi ban khong biet a hahahahahahahahahahahahahahah

Ôi trời de vai

2:

a: A(x)=0

=>-5x+3=0

=>-5x=-3

=>x=3/5

b: B(x)=0

=>2x^3-18x=0

=>2x(x^2-9)=0

=>x(x-3)(x+3)=0

=>x=0;x=3;x=-3

c: C(x)=0

=>-x(-x-5)=0

=>x(x+5)=0

=>x=0 hoặc x=-5

d: D(x)=0

=>3x-3+2x^2-2x-x^2+2x-1=0

=>x^2+3x-4=0

=>x=-4 hoặc x=1

e: E(x)=0

=>2x^3-2x-x^2+1=0

=>2x(x^2-1)-(x^2-1)=0

=>(2x-1)(x-1)(x+1)=0

=>x=1/2;x=-1;x=1