=(1/2*6)+(1/38*60)

=3+30/19=87/19

Ta có: \(\frac{1}{2\times6}+\frac{1}{4\times9}+\frac{1}{6\times12}+\cdots+\frac{1}{36\times57}+\frac{1}{38\times60}\)

\(=\frac16\times\left(\frac12+\frac{1}{2\times3}+\frac{1}{3\times4}+\cdots+\frac{1}{18\times19}+\frac{1}{19\times20}\right)\)

\(=\frac16\times\left(1-\frac12+\frac12-\frac13+\cdots+\frac{1}{19}-\frac{1}{20}\right)\)

\(=\frac16\times\left(1-\frac{1}{20}\right)=\frac16\times\frac{19}{20}=\frac{19}{120}\)

\(\frac13+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)

GIÚP NHÉ

Np 3  và Sl 2 có cùng chung điểm Suy ra

a) (38 - 60) + (20 - 38)

= 38 - 60 + 20 - 38

= (38 - 38) + (-60 + 20)

= 0 - 40

= -40

b) 75 - (20 + 75)

= 75 - 20 - 75

= (75 - 75) - 20

= 0 - 20

= -20

c) 32 + (60 - 32)

= 32 + 60 - 32

= (32 - 32) + 60

= 0 + 60

= 60

d) (81 - 36) - (81 - 36)

= 81 - 36 - 81 + 36

= (81 - 81) + (-36 + 36)

= 0 + 0

= 0

e) (2 + 4 + 6 + 8) - (1 + 3 + 5 + 7)

= 2 + 4 + 6 + 8 - 1 - 3 - 5 - 7

= (2 - 1) + (4 - 3) + (6 - 5) + (8 - 7)

= 1 + 1 + 1 + 1

= 4

f) (1 + 3 + 5 + 7 + ... + 99) - (2 + 4 + 6 + 8 + ... + 100)

= 1 + 3 + 5 + 7 + ... + 99 - 2 - 4 - 6 - 8 - ... - 100

= (1 - 2) + (3 - 4) + (5 - 6) + (7 - 8) + ... + (99 - 100)

= -1 - 1 - 1 - 1 - ... - 1 (50 chữ số 1)

= -50

giúp mình với huhuhuhuhuhu

(dấu chấm là dấu nhân nha e)

 *\(\dfrac{1}{2}\). \(\dfrac{1}{4}\)+\(\dfrac{3}{4}\)

= \(\dfrac{1}{8}\)+\(\dfrac{3}{4}\)

= \(\dfrac{1}{8}\)+\(\dfrac{6}{8}\)= \(\dfrac{7}{8}\)

 *\(\dfrac{3}{4}\).\(\dfrac{5}{6}\).\(\dfrac{8}{15}\)

= \(\left(\dfrac{3}{4}.\dfrac{8}{15}\right)\).\(\dfrac{5}{6}\)

= \(\dfrac{2}{5}\).\(\dfrac{5}{6}\)

= \(\dfrac{1}{3}\)

 *\(\dfrac{12}{19}\): \(\dfrac{17}{38}\).\(\dfrac{16}{9}\)

= \(\dfrac{12}{19}\). \(\dfrac{38}{17}\).\(\dfrac{16}{9}\)= 2,5