giúp tui câu này \(\frac{11}{30}+\frac{18}{35}\times\left(\frac{35}{54}-\frac{49}{18}-\frac{28}{48}\right)\) đi mà
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1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50=1275
b: \(=\dfrac{3}{7}\cdot\dfrac{5}{7}\cdot\dfrac{6}{7}=\dfrac{90}{343}\)
c: \(=\dfrac{4}{9}\cdot\dfrac{5}{9}\cdot\dfrac{3}{7}=\dfrac{20}{189}\)
d: \(=\dfrac{1}{3}\cdot\dfrac{5}{12}\cdot\dfrac{5}{12}=\dfrac{25}{432}\)
1 + 2 + 3 +...+ 50
Dãy trên có số số hạng là:
\(\left(50-1\right)+1=50\) (số)
Tổng của chúng là:
\(\frac{\left(50+1\right)\cdot50}{2}=1275\)
Vậy tổng của chúng là 1275
~Học tốt~
A=\(\frac{1}{3}\)+\(\frac{1}{8}\)+\(\frac{1}{15}\)+\(\frac{1}{24}\)+\(\frac{1}{35}\)+\(\frac{1}{48}\)+\(\frac{1}{63}\)+\(\frac{1}{80}\)
A=\(\frac{1}{2}\)(\(\frac{1}{1\cdot3}\)+\(\frac{1}{2\cdot4}\)+\(\frac{1}{3\cdot5}\)+\(\frac{1}{4.6}\)+\(\frac{1}{5.7}\)+\(\frac{1}{6.8}\)+\(\frac{1}{7.9}\)+\(\frac{2}{8.10}\))
A=\(\frac{1}{2}\)(1-1/3 +1/2-1/4 + 1/3 -1/5 +1/4-1/6 +1/5 - 1/7 +1/6 -1/8 +1/7 - 1/9 +1/8 - 1/10)
A= \(\frac{1}{2}\)(1 + 1/2 -1/9 -1/10)
A=\(\frac{29}{45}\)
a: \(-\frac{10}{3}+\frac{13}{10}-\frac16+\frac{7}{10}\)
\(=\left(-\frac{10}{3}-\frac16\right)+\left(\frac{13}{10}+\frac{7}{10}\right)\)
\(=-\frac{21}{6}+\frac{20}{10}=-\frac72+2=-\frac32\)
b: \(1-\frac{20}{6}+\frac{39}{30}-\frac{4}{24}+\frac{34}{50}\)
\(=1-\frac{20}{6}+\frac16+1,3+0,68\)
\(=1-\frac{19}{6}+1,98=2,98-\frac{19}{6}=\frac{298}{100}-\frac{19}{6}=\frac{-56}{300}=\frac{-14}{75}\)
c: \(\frac{15}{24}-\frac{6}{26}+\frac{28}{48}-\frac{30}{39}+\frac{10}{24}\)
\(=\left(\frac{15}{24}+\frac{10}{24}+\frac{28}{48}\right)-\left(\frac{3}{13}+\frac{10}{13}\right)\)
\(=\left(\frac{25}{24}+\frac{14}{24}\right)-1=\frac{39}{24}-1=\frac{15}{24}=\frac58\)
d: \(-\frac{5}{10}+\frac{12}{28}-\frac{3}{27}-\frac{7}{18}+\frac{20}{35}\)
\(=-\frac12+\frac37-\frac19-\frac{7}{18}+\frac47\)
\(=\left(-\frac12-\frac19-\frac{7}{18}\right)+\left(\frac37+\frac47\right)=-1+1=0\)
\(\frac{11}{30}\) + \(\frac{18}{35}\) x (\(\frac{35}{54}\) - \(\frac{49}{18}\) - \(\frac{28}{48}\))
= \(\frac{11}{30}\) + \(\frac{18}{35}\) x \(\frac{35}{54}\) - \(\frac{18}{35}\) x \(\frac{49}{18}\) - \(\frac{18}{35}\) x \(\frac{28}{48}\)
= \(\frac{11}{30}\) + \(\frac13\) - \(\frac75\) - \(\frac{3}{10}\)
= \(\frac{11}{30}\) + \(\frac{1\times10}{3\times10}\) - \(\frac{7\times6}{5\times6}\) - \(\frac{3\times3}{10\times3}\)
= \(\frac{11}{30}\) + \(\frac{10}{30}\) - \(\frac{42}{30}\) - \(\frac{9}{30}\)
= \(\frac{21}{30}\) - \(\frac{42}{30}\) - \(\frac{9}{30}\)
= \(\frac{-21}{30}\) - \(\frac{9}{30}\)
= \(\frac{-30}{30}\)
= 1
=1