a: \(4^8\cdot2^{20}=\left(2^2\right)^8\cdot2^{20}=2^{16}\cdot2^{20}=2^{16+20}=2^{36}\)

\(9^{12}\cdot27^5\cdot81^4=\left(3^2\right)^{12}\cdot\left(3^3\right)^5\cdot\left(3^4\right)^4\)

\(=3^{24}\cdot3^{15}\cdot3^{16}=3^{24+15+16}=3^{55}\)

\(64^3\cdot4^5\cdot16^2=\left(4^3\right)^3\cdot4^5\cdot\left(4^2\right)^2=4^9\cdot4^5\cdot4^4=4^{9+5+4}=4^{18}\)

b: \(25^{20}\cdot125^4=\left(5^2\right)^{20}\cdot\left(5^3\right)^4=5^{40}\cdot5^{12}=5^{52}\)

\(x^7\cdot x^4\cdot x^3=x^{7+4+3}=x^{14}\)

\(3^6\cdot4^6=\left(3\cdot4\right)^6=12^6\)

c: \(8^4\cdot2^3\cdot16^2=\left(2^3\right)^4\cdot2^3\cdot\left(2^4\right)^2\)

\(=2^{12}\cdot2^3\cdot2^8=2^{23}\)

\(y\cdot y^7=y^{1+7}=y^8\)

\(2^3\cdot2^2\cdot8^3=2^5\cdot\left(2^3\right)^3=2^5\cdot2^9=2^{5+9}=2^{14}\)

Chọn B

b

a, 3⁴.27⁵.(3²)³ = 3⁴.(3³)⁵.3⁶ = 3⁴.3¹⁵.3⁶ = 3²⁵

b, (2³)⁴.4⁶.32 = 2¹².2¹².2⁵ = 2²⁹

c, 3²⁰¹⁹.6²⁰¹⁹: 2²⁰¹⁹ = 3²⁰¹⁹.3²⁰¹⁹.2²⁰¹⁹:2²⁰¹⁹ = (3.3)²⁰¹⁹= 9²⁰¹⁹

d, 125⁸.(5²)⁴ = (5³)⁸.5⁸ = 5³²

a) \(2^{36}\)

b) \(3^{30}\)

c) \(3^9\)

d) \(2^{18}\)

a) 4⁸.2²⁰=(2²)⁸.2²⁰=2¹⁶.2²⁰=2³⁶

b) 9¹².27²=(3²)¹².(3³)²=3²⁴.3⁶=3³⁰

c) 3⁶.3².3=3⁹

d) 4⁵.16²=(2²)⁵.(2⁴)²=2¹⁰.2⁸=2¹⁸

`A=1+2+2^2+2^3+2^4+...+2^{200}`

`=>2A=2+2^2+2^3+2^4+2^5+...+2^{201}`

`=>2A-A=(2+2^2+2^3+2^4+2^5+...+2^{201})-(1+2+2^2+2^3+2^4+...+2^{200})`

`=>A=2^{201}-1`

`=>A+1=2^{201}`

câu hỏi là j ạ

Bài 1: 

a) \(4^8\cdot2^{20}=\left(2^2\right)^8\cdot2^{20}=2^{36}\)

 \(64^3\cdot4^5=\left(2^6\right)^3\cdot\left(2^2\right)^5=2^{18}\cdot2^{10}=2^{28}\)

\(y\cdot y^7=y^{1+7}=y^8\)

\(a^n\cdot a^2=a^{n+2}\)

Bài 1:

b) \(10^8:2^8=5^8\)

\(17^8:17^5=17^3\)

\(2^{25}:32^4=2^{25}:2^{20}=2^5\)

\(19^4:9^4=\left(\dfrac{19}{9}\right)^4\)

A

A

\(a,23\cdot24\cdot2=2^4\cdot3\cdot23\)

\(b,52\cdot57\cdot53=2^3\cdot3\cdot13\cdot19\cdot53\)

\(c,30\cdot35\cdot37=2\cdot3\cdot5^2\cdot7\cdot37\)

ko vieets dưới dạng lũy thừa nha em

a}23.24.2

=552.2

=1104

b)52.57.53

=2964.53

=157092

c)30.35.37

=1050.37

=38850