\(\frac{125^2.25^3}{5^4}\)
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\(\frac{27^2.15^3.125^{17}.10^{10}.3^8.512+1024.25^{28}.12^6.15^7}{125.6^{17}+625^{12}.6^{13}.125^2.25^5.16}\)
=\(\frac{3^6.3^3.5^3.5^{34}.2^{10}.5^{10}.3^8.2^9+2^{10}.5^{56}.3^6.2^{12}.3^7.5^7}{5^{63}.6^{17}+5^{48}.6^{13}.5^6.2^4}\)=\(\frac{3^{17}.5^{47}.2^{19}+2^{22}.5^{63}.3^{13}}{5^{63}.6^{17}+5^{48}.6^{13}.5^6.2^4}=\frac{3^{13}.5^{47}.2^{19}.3^4+2^{19}.5^{47}.3^{13}.2^3.5^{16}}{5^{54}.6^{13}.5^9+5^{54}.6^{13}.2^4}\)
=\(\frac{3^{13}.5^{47}.2^{19}\left(3^4+2^3.5^{16}\right)}{5^{54}.6^{13}\left(5^9+2^4\right)}=\frac{6^{13}.2^6.5^{47}\left(3^4+2^3.5^{16}\right)}{5^7.5^{47}.6^{13}\left(5^9+2^4\right)}=\frac{2^6\left(3^4+2^3.5^{16}\right)}{5^7\left(5^9+2^4\right)}\)
Bạn hãy tự giải nốt
a) -23 + 176 - (2176 - 23)
= -23 + 176 - 2176 + 23
= (-23 + 23) + (176 - 2176)
= 0 + (-2000)
= -2000
b) 125 . (-24) + 24 . 225
= (-125) . 24 + 24 . 225
= 24 . (-125 + 225)
= 24 . 100
= 2400
\(\frac{5^2.25^{40}}{125^{10}}=\frac{5^2.5^{80}}{5^{30}}=\frac{5^{82}}{5^{30}}=5^{82-30}=5^{52}\)
\(\frac{5^2.25^{40}}{125^{10}}\)
\(=\frac{5^2.5^{80}}{5^{30}}\)
\(=\frac{5^{82}}{5^{30}}\)
\(=5^{52}\)
\(\frac{5}{9}+\left(\frac{-2}{3}\right)^2.25\%-1\frac{1}{3}\) =\(\frac{5}{9}+\frac{4}{9}.\frac{1}{4}-\frac{4}{3}\)=\(\frac{5}{9}+\frac{1}{9}-\frac{4}{3}\)=\(\frac{2}{3}-\frac{4}{3}\)=\(\frac{-2}{3}\)
\(\frac{5}{9}+\left(\frac{-2}{3}\right)^2.25\%-1\frac{1}{3}\)
\(=\frac{5}{9}+\frac{4}{9}.\frac{1}{4}-\frac{4}{3}\)
\(=\frac{5}{9}+\frac{1}{9}-\frac{4}{3}\)
\(=\frac{2}{3}-\frac{4}{3}=\frac{-2}{3}.\)
\(\frac{\left(5^4-5^3\right)}{125^4}-\frac{64}{125}\)
\(=\frac{\left(625-125\right)}{500}-\frac{64}{125}\)
\(=\frac{500}{500}-\frac{64}{125}\)
\(=0-0,51\)
\(=-0,51\)
\(\frac{125^2\cdot25^3}{5^4}\)
\(=\frac{\left(5^3\right)^2\cdot\left(5^2\right)^3}{5^4}\)
\(=\frac{5^6\cdot5^6}{5^4}\)
\(=\frac{5^{36}}{5^4}=5^{32}\)