a) 1919/2020 + 3/8 + 5/8 x 19/20 b) 1/2 : 2/4 :3 /6 : 4/8 : 5/10 : 6/12
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a)= 2021.2021-2020.(2021+1)
= 2021.(2020+1)-2020.(2021+1)
= (2021.2020)+2021-(2020.2021)-2020
= 1
b) B= (1+2-3-4)+(5+6-7-8)+(9+10-11-12)...........+(2017+2018-2019-2020)+2021
B= -4+(-4)+....................(-4)+2021
B= -4x505+2021
B= -2020 + 2021
B = 1
Câu b:
1/5 : 1/10 - 1/3.(6/5 - 9/4)
= 1/5 x 10 - 1/3.(24/20 - 45/20)
= 2 - 1/3.(-21/20)
= 2 + 7/20
= 40/20 + 7/20
= 47/20
Câu a:
1/2.(4/3 + 2/5) - 3/4(8/9 + 13/3)
= 1/2. 4/3 + 1/2.2/5 - 3/4.8/9 - 3/4.13/3
= 2/3 + 1/5 - 2/3 - 13/4
= (2/3 - 2/3) + (1/5 - 13/4)
= 0 + 1/5 - 13/4
= 4/20 - 65/20
= - 61/20
1/5 : 1/10 - 1/3.(6/5 - 9/4)
= 1/5 x 10 - 1/3.(24/20 - 45/20)
= 2 - 1/3.(-21/20)
= 2 + 7/20
= 40/20 + 7/20
= 47/20
a,
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Rightarrow5^{x+3}\left(5-3\right)=2.5^{11}\)
\(\Rightarrow5^{x+3}2=2.5^{11}\)
\(\Rightarrow5^{x+3}=5^{11}\)
\(\Rightarrow x+3=11\)
\(\Rightarrow x=8\)
b, (Check lai xem de sai o dau khong nhe)
\(3.5^{x+2}+4.5^{x+3}=19.5^{10}\)
Dat 5x ra ben ngoai
\(\Rightarrow5^x.5^23+5^x:5^{-3}.4\)
\(\Rightarrow5^x\left(5^2.3+5^{-3}.4\right)\)
\(\Rightarrow5^x\left(5^{-3}.5^5.3+5^{-3}.4\right)\)
\(\Rightarrow5^x[5^{-3}\left(5^53+4\right)\)
\(\Rightarrow5^x[5^{-3}\left(3125.3+4\right)\)
\(\Rightarrow5^x\left(5^{-3}\right).9379\)
=> Khong tim duoc gia tri cua x \(\Rightarrow x\in\varnothing\)
b) Ta có: \(5^{x+4}-3\cdot5^{x+3}=2\cdot5^{11}\)
\(\Leftrightarrow2\cdot5^{x+3}=2\cdot5^{11}\)
\(\Leftrightarrow x+3=11\)
hay x=8
c) Ta có: \(2\cdot3^{x+2}+4\cdot3^{x+1}=10\cdot3^6\)
\(\Leftrightarrow18\cdot3^x+12\cdot3^x=10\cdot3^6\)
\(\Leftrightarrow30\cdot3^x=30\cdot3^5\)
Suy ra: x=5
d) Ta có: \(6\cdot8^{x-1}+8^{x+1}=6\cdot8^{19}+8^{21}\)
\(\Leftrightarrow6\cdot\dfrac{8^x}{8}+8^x\cdot8=6\cdot8^{19}+64\cdot8^{19}\)
\(\Leftrightarrow8^x\cdot\dfrac{35}{4}=70\cdot8^{19}\)
\(\Leftrightarrow8^x=8^{20}\)
Suy ra: x=20
1: =72/90+65/90=137/90
2: =24/56-77/56=-53/56
3: =-7/10+4/5=1/10
4: =15/100-4/100=11/100
5: =4/6-5/6=-1/6
6: =10/40-15/40-76/40=-81/40
7: =-9/10+7/18
=-81/90+35/90=-46/90=-23/45
8: =27/90-55/90=-28/90=-14/45
9: =36/60-50/60-35/60=-49/60
10: =-4/9+5/6-3/8
=-32/72+60/72-27/72
=1/72
a)\(\left(x+3\right)\times5+1=20\Leftrightarrow5x+15=19\)
\(\Leftrightarrow5x=4\Leftrightarrow x=\frac{4}{5}\)
b)sai đề
c)\(2\frac{3}{7}\times x+1\frac{5}{4}=5\frac{3}{42}\)\(\Leftrightarrow\frac{17}{7}\times x+\frac{9}{4}=\frac{71}{14}\) \(\Leftrightarrow\frac{17}{7}\times x+\frac{63}{28}=\frac{142}{28}\)
\(\Leftrightarrow\frac{17}{7}\times x=\frac{79}{28}\Leftrightarrow x=\frac{17}{7}:\frac{79}{28}\) \(\Leftrightarrow x=\frac{17}{7}\times\frac{28}{79}\Leftrightarrow x=\frac{476}{553}=\frac{68}{79}\)
d)\(10\frac{2}{3}-x:\frac{6}{7}=8\frac{1}{3}-6\frac{2}{7}\Leftrightarrow\frac{32}{3}-x:\frac{6}{7}=\frac{25}{3}-\frac{44}{7}\) \(\Leftrightarrow\frac{224}{21}-x:\frac{6}{7}=\frac{75}{21}-\frac{132}{21}\Leftrightarrow-\frac{57}{21}-\frac{224}{21}\)
\(\Leftrightarrow-x:\frac{6}{7}=-\frac{281}{21}\Leftrightarrow-x=-\frac{281}{21}\times\frac{6}{7}\) \(\Leftrightarrow-x=-\frac{1686}{147}\Leftrightarrow x=\frac{562}{49}=11\frac{23}{49}\)
a) ( x + 3 ) × 5 + 1 = 20 ⇔ 5 x + 15 = 19 (x+3)×5+1=20⇔5x+15=19 ⇔ 5 x = 4 ⇔ x = 4 5 ⇔5x=4⇔x= 5 4 b)sai đề c) 2 3 7 × x + 1 5 4 = 5 3 42 2 7 3 ×x+1 4 5 =5 42 3 ⇔ 17 7 × x + 9 4 = 71 14 ⇔ 7 17 ×x+ 4 9 = 14 71 ⇔ 17 7 × x + 63 28 = 142 28 ⇔ 7 17 ×x+ 28 63 = 28 142 ⇔ 17 7 × x = 79 28 ⇔ x = 17 7 : 79 28 ⇔ 7 17 ×x= 28 79 ⇔x= 7 17 : 28 79 ⇔ x = 17 7 × 28 79 ⇔ x = 476 553 = 68 79 ⇔x= 7 17 × 79 28 ⇔x= 553 476 = 79 68 d) 10 2 3 − x : 6 7 = 8 1 3 − 6 2 7 ⇔ 32 3 − x : 6 7 = 25 3 − 44 7 10 3 2 −x: 7 6 =8 3 1 −6 7 2 ⇔ 3 32 −x: 7 6 = 3 25 − 7 44 ⇔ 224 21 − x : 6 7 = 75 21 − 132 21 ⇔ − 57 21 − 224 21 ⇔ 21 224 −x: 7 6 = 21 75 − 21 132 ⇔− 21 57 − 21 224 ⇔ − x : 6 7 = − 281 21 ⇔ − x = − 281 21 × 6 7 ⇔−x: 7 6 =− 21 281 ⇔−x=− 21 281 × 7 6 ⇔ − x = − 1686 147 ⇔ x = 562 49 = 11 23 49 ⇔−x=− 147 1686 ⇔x= 49 562 =11 49 23
a) Vì 4 < 5 nên \(\frac{3}{4}>\frac{3}{5}\)
b) Vì 4 < 5 nên \(\frac{4}{7}< \frac{5}{7}\)
c) Ta có :
\(\frac{2}{7}=\frac{2\times5}{7\times5}=\frac{10}{35}\)
\(\frac{4}{5}=\frac{4\times7}{5\times7}=\frac{28}{35}\)
Vì 10 < 28 nên \(\frac{10}{35}< \frac{28}{35}\)hay \(\frac{2}{7}< \frac{4}{5}\)
d) Ta có :
\(\frac{8}{9}=\frac{8\times10}{9\times10}=\frac{80}{90}\)
\(\frac{9}{10}=\frac{9\times9}{10\times9}=\frac{81}{90}\)
Vì 80 < 81 nên \(\frac{80}{90}< \frac{81}{90}\)hay \(\frac{8}{9}< \frac{9}{10}\)
e) Ta có :
\(\frac{10}{9}=\frac{10\times2}{9\times2}=\frac{20}{18}\)
Vì 19 < 20 nên \(\frac{19}{18}< \frac{20}{18}\)hay \(\frac{19}{18}< \frac{10}{9}\)
f) Ta có :
\(\frac{8}{3}=\frac{8\times4}{3\times4}=\frac{32}{12}\)
\(\frac{5}{6}=\frac{5\times2}{6\times2}=\frac{10}{12}\)
Vì 32 > 10 nên \(\frac{32}{12}>\frac{10}{12}\)hay \(\frac{8}{3}>\frac{5}{6}\)
a: Sửa đề: \(\dfrac{1919}{2020}\times\dfrac{3}{8}+\dfrac{5}{8}\times\dfrac{19}{20}\)
\(=\dfrac{19}{20}\times\dfrac{3}{8}+\dfrac{5}{8}\times\dfrac{19}{20}\)
\(=\dfrac{19}{20}\times\left(\dfrac{3}{8}+\dfrac{5}{8}\right)\)
\(=\dfrac{19}{20}\times\dfrac{8}{8}=\dfrac{19}{20}\)
b: \(\dfrac{1}{2}:\dfrac{2}{4}:\dfrac{3}{6}:\dfrac{4}{8}:\dfrac{5}{10}:\dfrac{6}{12}\)
\(=\dfrac{1}{2}:\dfrac{1}{2}:\dfrac{1}{2}:\dfrac{1}{2}:\dfrac{1}{2}:\dfrac{1}{2}\)
\(=\dfrac{1}{2}\times2\times2\times2\times2\times2\)
=2x2x2x2
=16
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