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câu hỏi tương tự

a) x = - 4.

b) x = -5.

\(x\times2\dfrac{2}{3}=3\dfrac{4}{8}+6\dfrac{5}{12}\) 

\(x\times\dfrac{8}{3}=\dfrac{28}{8}+\dfrac{77}{12}\) 

\(x\times\dfrac{8}{3}=\dfrac{119}{12}\) 

\(x=\dfrac{119}{12}:\dfrac{8}{3}\) 

\(x=\dfrac{119}{32}\)

\(x\) x 8/3 = 7/2 + 77/12

\(x\) x 8/3 = 119/12

\(x\) = 119/12 : 8/3 

x = 119/32

a) x × 5 = 35 – 5

x × 5 = 30

x = 30 : 5

x = 6

b) x : 4 = 12 – 8

x : 4 = 4

x = 4 × 4

x = 16

c) 4 × x = 6 × 2

4 × x = 12

x = 12 : 4

x = 3

d) x : 3 = 16 : 4

x : 3 = 4

x = 4 × 3

x = 12

\(a,5\left(3x+5\right)-4\left(2x-3\right)=5x+8\left(2x+12\right)+1\)

\(\Rightarrow5\left(3x+5\right)-4\left(2x-3\right)-5x-8\left(2x+12\right)-1=0\)

\(\Rightarrow15x+25-8x+12-5x-16x-96-1=0\)

\(\Rightarrow-14x-60=0\)

\(\Rightarrow-14x=60\) \(\Rightarrow x=-\frac{60}{14}=\frac{-30}{7}\)

\(b,\left(2x+3\right)\left(x-4\right)-\left(3x-5\right)\left(x-4\right)=\left(5-x\right)\left(x-2\right)\)

\(\Rightarrow2x^2+3x-8x-12-3x^2+5x+12x-20=5x-x^2-10+2x\)

\(\Rightarrow-x^2+12x-32=7x-x^2-10\)

\(\Rightarrow-x^2+12x-32-7x+x^2+10=0\)

\(\Rightarrow5x-22=0\)

\(\Rightarrow5x=22\Rightarrow x=\frac{22}{5}\)

a) 5(3x+5)-4(2x-3) = 5x+8(2x+12)+1

15x + 25 - 8x + 12 = 5x + 16x + 96 + 1

15x - 8x - 5x - 16x = 96 + 1 - 25 - 12

-14x = 60

x = \(\frac{60}{-14}\)

x = \(-\frac{30}{7}\)

b) (2x+3)(x-4)-(3x-5)(x-4) = (5-x).(x-2)

(x - 4)(2x + 3 - 3x +5) = 5x - 10 - x² + 2x

(x - 4)[(2x - 3x) + (3 + 5)] = 5x - 10 - x² + 2x

(x - 4)(-x + 8) = 5x - 10 - x² + 2x

-x² + 8x + 4x - 32 = 5x - 10 - x² + 2x

(-x² + x²) + (8x + 4x - 5x - 2x) = -10 + 32

5x = 22

x = \(\frac{22}{5}\) 

\(a,3.\left(x-4\right)-\left(8-x\right)=12\)

             \(3x-12-8+x=12\)

                              \(4x-20=12\)

                                         \(4x=12+20\)

                                         \(4x=32\)

                                            \(x=32:4\)

                                            \(x=8\)

\(b,4.\left(x-5\right)-\left(x+7\right)=-19\)

              \(4x-20-x-7=-19\)

                               \(3x-27=-19\)

                                          \(3x=-19+27\)

                                          \(3x=8\)

                                             \(x=\frac{8}{3}\)

\(c,7.\left(x-3\right)-5.\left(3-x\right)=11x-5\)

            \(7x-21-15+5x=11x-5\)

                               \(12x-36=11x-5\)

                             \(12x-11x=-5+36\)

                                               \(x=31\)

\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)

\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)

\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)

\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)

`x/8=4/(-32)`

`(4x)/32=(-4)/32`

`4x=-4`

`x=-1`

Vậy `x=-1`.

`b)x-7/18=3 5/12`

`x-7/18=41/12`

`x=41/12+7/18`

`x=137/36`

Vậy `x=137/36`

`c)-3/8. 2/5+(-3)/8. 9/5-(-3)/8. 6/5`

`=-3/8. 2/5-3/8. 9/5+3/8. 6/5`

`=3/8(-2/5-9/5+6/5)`

`=3/8.(-1)`

`=-3/8`