A=(-8)/5x5/4-(-8)/5x1/4-(-8)/5x5/4
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a) \(\dfrac{2}{5}\cdot\dfrac{1}{7}+\dfrac{2}{5}\cdot\dfrac{5}{7}+\dfrac{2}{5}\)
\(=\dfrac{2}{5}\left(\dfrac{1}{7}+\dfrac{5}{7}+1\right)\)
\(=\dfrac{2}{5}\cdot\dfrac{13}{7}=\dfrac{26}{35}\)
b) \(\dfrac{1}{5}+\dfrac{2}{8}+\dfrac{4}{5}+\dfrac{7}{8}-\dfrac{1}{8}\)
\(=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{2}{8}+\dfrac{7}{8}-\dfrac{1}{8}\right)\)
\(=1+1=2\)
c)\(\dfrac{24}{36}\cdot\dfrac{10}{12}\cdot36\)
\(=\dfrac{24\cdot10\cdot36}{36\cdot12}=\dfrac{12\cdot2\cdot10\cdot36}{12\cdot36}\)
\(=2\cdot10=20\)
\(\left(\dfrac{1}{5}\right)^5\cdot5^5+\dfrac{8^{13}}{4^{18}}\)
\(=1+\dfrac{2^{39}}{2^{36}}\)
=9
a: =9/11(7/4+5/4)=9/11x3=27/11
b: \(=\dfrac{28}{5}\cdot\dfrac{5}{8}\cdot\dfrac{5}{4}=\dfrac{28}{8}\cdot\dfrac{5}{4}=\dfrac{140}{32}=\dfrac{35}{8}\)
c: \(=\dfrac{2}{6}+\dfrac{4}{5}\cdot\dfrac{6}{5}-\dfrac{2}{5}=\dfrac{67}{75}\)
a,=(7/4+5/4):11/9
=3:11/9
=27/11
b,=28/5.5/4.5/8
=7.5/8
=35/8
c,=1/3+24/25-2/5
=97/75-2/5
=67/75
x=4
=>x+1=5
A=(x+1)x^5 -(x+1)x^4+(x+1)x^3-(x+1)x^2+(x+1)x-1
=x^6+x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2-x+1
=x^6-x-1
=4^6-4-1
=4091
\(a,A=5\cdot4^5-5\cdot4^4+5\cdot4^3-5\cdot4^2+5\cdot4+1\\ A=4^4\left(20-5\right)+4^2\left(20-5\right)+\left(20-5\right)\\ A=15\left(4^4+4^2+1\right)=15\cdot273=4095\)
\(b,x=7\Leftrightarrow x+1=8\\ \Leftrightarrow B=x^{2006}-\left(x+1\right)x^{2005}+\left(x+1\right)x^{2004}-...+\left(x+1\right)x^2-\left(x+1\right)x-5\\ B=x^{2006}-x^{2006}-x^{2005}+x^{2005}+x^{2004}-...+x^3+x^2-x^2-x-5\\ B=-x-5=-12\)
a) 197148:84=2347
101598:287=354
b)9/20-8/5x5/12= -13/60
2/3:4/5:7/12=10/7
4/9+11/8-5/6=71/72
tính :
a) 197148:84=2347
101598:287=354
b)9/20-8/5x5/12= -13/60
2/3:4/5:7/12=10/7
=4/9+11/8-5/6=71/72
B = \(\dfrac{2}{35}\) + \(\dfrac{4}{77}\) + \(\dfrac{2}{143}\) + \(\dfrac{4}{221}\) + \(\dfrac{2}{323}\) + \(\dfrac{4}{437}\) + \(\dfrac{2}{575}\) (như này mới đúng em ơi)
C = 8 : \(\dfrac{4}{5}\) - 7\(\dfrac{1}{5}\) x \(\dfrac{5}{4}\)
C = 8 x \(\dfrac{5}{4}\) - \(\dfrac{36}{5}\) x \(\dfrac{5}{4}\)
C = \(\dfrac{5}{4}\) x (8 - \(\dfrac{36}{5}\))
C = \(\dfrac{5}{4}\) x (\(\dfrac{40}{5}\) - \(\dfrac{36}{5}\))
C = \(\dfrac{5}{4}\) x \(\dfrac{4}{5}\)
C = 1
Câu 3:
Chiều rộng là 90x3/5=54(m)
Chu vi là (90+54)x2=288(m)
Câu 4:
Chiều rộng là 60x3/5=36(m)
Chu vi là (60+36)x2=192(m)
Diện tích là 60x36=2160(m2)

Để tính giá trị của biểu thức A, ta thực hiện các bước sau:
1. Rút gọn biểu thức:
A = (-8)/5 * (5/4 - 1/4 - 5/4)
2. Tính toán trong ngoặc:
5/4 - 1/4 - 5/4 = (5 - 1 - 5) / 4 = -1/4
3. Nhân với thừa số chung:
A = (-8)/5 * (-1/4) = 8/20
4. Rút gọn kết quả:
8/20 = 2/5
Kết quả:
\(A=\dfrac{-8}{5}\cdot\dfrac{5}{4}-\left(-\dfrac{8}{5}\right)\cdot\dfrac{1}{4}-\dfrac{-8}{5}\cdot\dfrac{5}{4}\)
\(=-\dfrac{8}{5}\cdot\dfrac{5}{4}+\dfrac{8}{5}\cdot\dfrac{5}{4}+\dfrac{8}{5}\cdot\dfrac{1}{4}\)
\(=\dfrac{8}{5}\cdot\dfrac{1}{4}=\dfrac{2}{5}\)