Cái gì mà tùm lum thế

de gi ma dai, ghi lon xon, chang hieu gi ca??

a: \(=15x^3-6x^2-3x\)

e: \(=x^2-12x+35\)

       \(\frac{5.2^{30}.3^{18}-4.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{5.2^{28}.2^2.3^{18}-4.3^{18}.3^2.2^{27}}{5.2^{28}.3^{18}.3-7.2^{27}.2^2.3^{18}}\)

\(=\frac{3^{18}.\left(5.2^{28}.4-4.9.2^{27}\right)}{3^{18}.\left(5.3.2^{28}-7.2^{27}.4\right)}\)

\(=\frac{20.2^{28}-9.2.2.2^{27}}{15.2^{28}-14.2.2^{27}}\)

\(=\frac{2^{28}.20-18.2^{28}}{15.2^{28}-14.2^{28}}\)

\(=\frac{2^{28}.\left(20-18\right)}{2^{28}.\left(15-14\right)}\)

\(=\frac{2^{28}.2}{2^{28}1}\)

\(=2\)

=2/1 = 2

6: \(\left(2x^3-5x^2+6x-15\right):\left(2x-5\right)\)

\(=\frac{x^2\left(2x-5\right)+3\left(2x-5\right)}{2x-5}\)

\(=\frac{\left(2x-5\right)\left(x^2+3\right)}{2x-5}=x^2+3\)

2: \(\frac{2x^4-5x^2+x^3-3-3x}{x^2-3}\)

\(=\frac{2x^4-6x^2+x^3-3x+x^2-3}{x^2-3}\)

\(=\frac{2x^2\left(x^2-3\right)+x\cdot\left(x^2-3\right)+\left(x^2-3\right)}{x^2-3}=2x^2+x+1\)

5: \(\left(2x^3+5x^2-2x+3\right):\left(2x^2-x+1\right)\)

\(=\frac{2x^3-x^2+x+6x^2-3x+3}{2x^2-x+1}=\frac{\left(2x^2-x+1\right)\left(x+3\right)}{2x^2-x+1}\)

=x+3

3: \(\left(x-y-z\right)^5:\left(x-y-z\right)^3=\left(x-y-z\right)^{5-3}=\left(x-y-z\right)^2\)

1: \(\left(x^3-3x^2+x-3\right):\left(x-3\right)\)

\(=\frac{x^2\left(x-3\right)+\left(x-3\right)}{x-3}=x^2+1\)

\(a,=\left(2x^3-x^2+x+4x^2-2x+2-x+1\right):\left(2x^2-x+1\right)\\ =\left[x\left(2x^2-x+1\right)+2\left(2x^2-x+1\right)-x+1\right]:\left(2x^2-x+1\right)\\ =x+2\left(\text{dư }-x+1\right)\\ b,=\left[x^2\left(2x-5\right)+3\left(2x-5\right)\right]:\left(2x-5\right)\\ =x^2+3\)

1: \(=x^2+1\)

3: \(=\left(x-y-z\right)^2\)

a: P(x)=6x^3-4x^2+4x-2

Q(x)=-5x^3-10x^2+6x+11

M(x)=x^3-14x^2+10x+9

b: \(C\left(x\right)=7x^4-4x^3-6x+9+3x^4-7x^3-5x^2-9x+12\)

=10x^4-11x^3-5x^2-15x+21

Ta có

+ Trường hợp 1: x = 4 : Thay x = 4 vào biểu thức ta có:

5 . 4 2   -   2 . 4   -   18   =   5 . 16   -   8   -   18   =   80   -   8   -   18   =   54

Vậy B = 54 tại x = 4

+ Trường hợp 2: x = -4 : Thay x = -4 vào biểu thức ta có:

5 . - 4 2   - 2 . ( - 4 )   -   18   =   5 . 16   +   8   -   18   =   80   +   8   -   18   =   70

Vậy B = 70 tại x = -4

Với |x| = 4 thì B = 54 hoặc B = 70

Chọn đáp án C