tìm y nha mn . giúp mình với . thanks
( 7 x 13 + 8x 13 ) : ( 9 2/3 - y ) = 39 .
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9/13 x 7/12 + 9/13 x 5/12 - 9/13
= 9/13 x (7/12 + 5/12 - 1)
= 9/13 x 0
= 0
4/13 x 5/12 + 4/13 x 7/12 - 4/3
= 4/13 x (5/12 + 7/12) - 4/3
= 4/13 x 1 - 4/3
= 4/13 - 4/3
= -40/39
a, =>-2x+12+6x-60=8
=>4x+48=8
=>4x=56
=>x=14
b,=>-8x-36-8x-3-x-13=0
=>-17x-52=0
=>-17x=52
=>x=-52/17
c,=>14x+7x^2-7x^2-21x=14
=>-7x=14
=>x=-2
a) \(y-6:2-\left(48-24.2:6-3\right)=0.\)
\(\Rightarrow y-3-\left(48-8-3\right)=0\)
\(\Rightarrow y-3-37=0\)
\(\Rightarrow y=0+37+3=40\)
Vậy y = 40
b) \(\left(7.13+8.13\right):\left(9\frac{2}{3}-y\right)=39\)
\(\Rightarrow195:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow\frac{29}{3}-y=195:39=5\)
\(\Rightarrow y=\frac{29}{3}-5=\frac{14}{3}\)
Vậy y=\(\frac{14}{3}\)
a) y - 6 : 2 - ( 48 - 24 x 2 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 48 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 8 - 3 ) = 0
y - 6 : 2 - 37 = 0
y - 3 = 0 + 37
y - 3 = 37
y = 37 + 3
y = 40
b) ( 7 x 13 + 8 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
( 15 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
195 : ( \(9\frac{2}{3}\) - y ) = 39
\(9\frac{2}{3}\) - y = 195 : 39
\(9\frac{2}{3}-y=5\)
\(y=9\frac{2}{3}-5\)
\(y=\frac{14}{3}\)
`(x+19)/3 +(x+13)/5 = (x+7)/7 + (x+1)/9`
`<=> x/3 + 19/3 +x/5 +13/5 = x/7 +1 +x/9 +1/9`
`<=> x/3 +x/5 -x/7 -x/9 = 1+1/9 -19/3 -13/5`
`<=> x (1/3 +1/5 -1/7 -1/9) = -118/45`
`<=> x * 88/315 = -352/45`
`<=> x = -28`
Vậy `S={-28}`
a: =-5/9-4/9+8/15+7/15-2/11=-2/11
b: =10/17+7/17-5/13-8/13+11/25
=11/25
c: =(9/12-2/12)*3/2=7/12*3/2=21/24=7/8
d: =(31/10-25/10)*3-2
=3/5*3-2
=9/5-2
=-1/5
(13x7+13x8):(29/3-y)=39
=>[13x(7+8)]:(29/3-y)=39
=>(13x15):(29/3-y)=39
=>195:(29/3-y)=39
=>29/3-y=195:39=5
=>y=29/3-5
=>y=29/3-15/3
=>y=13/3
(13 x 7 + 13 x 8) : (29/3 - y) = 39
=> [13 x (7 + 8)] : (29/3 - y) = 39
=> (13 x 15) : (29/3 - y) = 39
=>195 : (29/3 - y) = 39
=> 29/3 - y = 195 : 39 = 5
=> y = 29/3 - 5
=> y = 29/3 - 15/3
=> y = 13/3
`(7 xx 13 + 8 xx 13) : (9 2/3 - y) = 39`
`13 xx (8+7) : (29/3 - y)=39`
`13 xx 15 : (29/3-y)=39`
`195 : (29/3-y)=39`
`29/3 - y = 195:39`
`29/3-y=5`
`y=29/3-5`
`y=14/3`
Vậy: `y=14/3`
(7 x 13 + 8 x 13): (9\(\frac23\) - y) = 39
13 x (7 + 8): (\(\frac{29}{3}\) - y) = 39
13 x 15 : (\(\frac{29}{3}-y\)) = 39
195 x (\(\frac{29}{3}-y\)) = 39
\(\frac{29}{3}-y\) = 195 : 39
\(\frac{29}{3}\) - y = 5
y = \(\frac{29}{3}-5\)
y = \(\frac{14}{3}\)