\(x\in N\) hay \(x\in Z\) bạn ?

x thuộc Z

a)=210

b)=8100

c)=3900

d)=49000

e)=100000

a ) 2 x 3 x 5 x 7

= ( 2 x 5 ) x 3 x 7

= 10 x 21

= 210

b ) 50 x 9 x 9 x 2

= ( 50 x 2 ) x 9 x 9

= 100 x 81

= 8100

c ) 13 x 25 x 3 x 4

= ( 25 x 4 ) x 13 x 3

= 100 x 39

= 3900

d ) 7 x 125 x 7 x 8

= ( 125 x 8 ) x 7 x 7

= 1000 x 49

= 49000

e ) 25 x 32 x 125

= 800 x 125

= 100000

Bài 10:

a: x-5=-1

=>x=-1+5

=>x=4

b: x+30=-4

=>x=-4-30

=>x=-34

c: x-(-24)=3

=>x+24=3

=>x=3-24

=>x=-21

d: 22-(-x)=12

=>22+x=12

=>x=12-22

=>x=-10

e: (x+5)+(x-9)=x+2

=>x+5+x-9=x+2

=>2x-4=x+2

=>2x-x=4+2

=>x=6

f: (27-x)+(15+x)=x-24

=>x-24=27-x+15+x=42

=>x=42+24

=>x=66

Bài 9:

a: 15-(4-x)=6

=>4-x=15-6=9

=>x=4-9=-5

b: -30+(25-x)=-1

=>-30+25-x=-1

=>-5-x=-1

=>x+5=1

=>x=1-5

=>x=-4

c: x-(12-25)=-8

=>x-(-13)=-8

=>x+13=-8

=>x=-8-13

=>x=-21

d: (x-29)-(17-38)=-9

=>x-29-(-21)=-9

=>x-29+21=-9

=>x-8=-9

=>x=-9+8

=>x=-1

Bài 8:

a: (17-229)+(17-25+229)

=17-229+17-25+229

=34-25

=9

b: (125-679+145)-(125-679)

=125-679+145-125+679

=145

(2x+1)^2=5^2

2x+1=5

x=2

(x-1)^3=-125

x-1=-5

x=-4

a)

(2x+1)²=25

^=> \(\left[\begin{array}{nghiempt}2x+1=5\\2x+1=-5\end{array}\right.\)

=>\(\left[\begin{array}{nghiempt}2x=4\\2x=-6\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=2\\x=-3\end{array}\right.\)

d)

(x-1)³=-125

=> x-1=-5

=> x=-4

còn câu b và c bạn viết đề rõ hơn nha

\(\left(x+5\right)+\left(x+10\right)+...+\left(x+25\right)-125=150\)
\(\Leftrightarrow x+5+x+10+...+x+25-125=150\)
\(\Leftrightarrow5x-50=150\)
\(\Leftrightarrow5x=100\)
\(\Leftrightarrow x=\dfrac{100}{5}=20\)
Vậy \(x=20\)

x = 20

\(x\times125-x\times25=37800\\ \Rightarrow x\times\left(125-25\right)=37800\\ \Rightarrow x\times100=37800\\ x=378\)

Cảm ơn bạn nhiều nha :3

\(x^3\) + 125 + (\(x\) + 5)(\(x\) - 25) = 0

(\(x^3\) + 5³) + (\(x\) + 5)(\(x\) - 25) = 0

(\(x\) + 5)(\(x^2\) - 5\(x\) + 25) + (\(x\) + 5)(\(x\) - 25) =0

(\(x\) + 5)(\(x^2\) - 5\(x\) + 25 + \(x\) - 25) = 0

(\(x\) + 5)(\(x^2\) - 4\(x\)) = 0

\(x\)(\(x\) + 5)(\(x\) - 4) = 0

\(\left[{}\begin{matrix}x=0\\x+5=0\\x-4=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=0\\x=-5\\x=4\end{matrix}\right.\)

`x^3 + 125 + (x + 5)(x - 25) = 0`

`<=>(x + 5)(x^2 + 5x + 25) + (x + 5)(x - 25) = 0`

`<=>(x + 5)(x^2 + 6x) = 0`

`<=>x(x + 5)(x + 6) = 0`

`<=>x = 0` hoặc `x = -5` hoặc `x=-6`

\(...=25x4x\left(7x3+3x4x5+2\right)=100x\left(21+120+2\right)=100x143=14300\)

14300