\(\dfrac{2}{5}+\dfrac{3}{7}=\dfrac{14}{35}+\dfrac{15}{35}=\dfrac{29}{35}\)

\(\dfrac{1}{7}+\dfrac{3}{7}+\dfrac{4}{7}=\left(\dfrac{1}{7}+\dfrac{3}{7}\right)+\dfrac{4}{7}=\dfrac{1}{7}+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\left(\dfrac{1}{7}+\dfrac{4}{7}\right)+\dfrac{3}{7}\)

a

A

a: \(B=\frac12-\left\lbrack\frac38+\left(-\frac74\right)\right\rbrack\)

\(=\frac12-\frac38+\frac74\)

\(=\frac48-\frac38+\frac{14}{8}=\frac{15}{8}\)

b: \(-\frac{4}{12}-\left(-\frac{13}{39}-0,25\right)+0,75\)

\(=-\frac13+\frac13+0,25+0,75\)

=0,25+0,75

=1

c: \(\frac12-\frac13+\frac{1}{23}+\frac16\)

\(=\left(\frac12-\frac13+\frac16\right)+\frac{1}{23}\)

\(=\left(\frac16+\frac16\right)+\frac{1}{23}=\frac13+\frac{1}{23}=\frac{26}{69}\)

d: \(\left(-\frac{13}{7}-\frac49\right)-\left(-\frac{10}{7}-\frac49\right)\)

\(=-\frac{13}{7}-\frac49+\frac{10}{7}+\frac49\)

\(=-\frac{13}{7}+\frac{10}{7}=-\frac37\)

e: \(\left(\frac78-\frac52+\frac47\right)-\left(-\frac37+1-\frac{13}{8}\right)\)

\(=\frac78-\frac52+\frac47+\frac37-1+\frac{13}{8}\)

\(=\frac{20}{8}-\frac52=0\)

f: \(-\frac37+\left(3-\frac34\right)-\left(2,25-\frac{10}{7}\right)\)

\(=-\frac37+3-\frac34-2,25+\frac{10}{7}\)

\(=\frac77+0,75-\frac34\)

=1
g: \(\left(\frac53-\frac37+9\right)-\left(2+\frac57-\frac23\right)+\left(\frac87-\frac43-10\right)\)

\(=\frac53-\frac37+9-2-\frac57+\frac23+\frac87-\frac43-10\)

\(=\left(\frac53+\frac23-\frac43\right)+\left(-\frac37-\frac57+\frac87\right)+\left(9-2-10\right)\)

\(=\frac33+7-10=1-3=-2\)

Lời giải chi tiết:

\(A=1+7+7^2+7^3+...+7^{2007}\)

\(7A=7+7^2+7^3+7^4+...+7^{2008}\)

\(7A-A=\left(7+7^2+7^3+7^4+...+7^{2008}\right)-\left(1+7+7^2+7^3+...+7^{2007}\right)\)

\(6A=7^{2008}-1\)

\(A=\frac{7^{2008}-1}{6}\)

Tương tự, \(B=\frac{4^{101}-1}{3},C=\frac{3^{101}-1}{2}\).

\(D=7+7^3+7^5+7^7+...+7^{99}\)

\(7^2.D=7^3+7^5+7^7+7^9+...+7^{101}\)

\(\left(7^2-1\right)D=\left(7^3+7^5+7^7+7^9+...+7^{101}\right)-\left(7+7^3+7^5+7^7+...+7^{99}\right)\)

\(48D=7^{101}-7\)

\(D=\frac{7^{101}-7}{48}\)

Tương tự, \(E=\frac{2^{9011}-2}{3}\)

\(\dfrac{2}{7}:\dfrac{1}{4}-\dfrac{1}{7}=\dfrac{2}{7}x\dfrac{4}{1}-\dfrac{1}{7}=\dfrac{8}{7}-\dfrac{1}{7}=\dfrac{7}{7}=1\)

\(\dfrac{7}{11}x0+\dfrac{5}{9}:\dfrac{1}{2}=0+\dfrac{5}{9}x\dfrac{2}{1}=\dfrac{10}{9}\)

\(\left(\dfrac{3}{7}+\dfrac{1}{4}\right):\dfrac{3}{4}=\left(\dfrac{12}{28}+\dfrac{7}{28}\right)x\dfrac{4}{3}=\dfrac{19}{28}x\dfrac{4}{3}=\dfrac{19}{21}\)

\(\dfrac{4}{3}x\dfrac{1}{2}+\dfrac{7}{2}:\dfrac{1}{4}=\dfrac{4}{6}+\dfrac{7}{2}x\dfrac{4}{1}=\dfrac{2}{3}+\dfrac{14}{1}=\dfrac{2}{3}+14=14\dfrac{2}{3}=\dfrac{44}{3}\)

cảm ơn nhé

Câu 22: Hãy sắp xếp số sau theo thứ tự tăng dần: -3; +4; 7; -7; 0; -1.
A. – 7; - 3 ; - 1; 0 ; + 4 ; 7.     B. 7; +4; 0; -1; -3; -7.
C.7; -7; +4; -3; -1; 0.              D. 0; -1; -3; +4; - 7; 7.
Câu 23: Liệt kê các phần tử của mỗi tập hợp: P = { x ε Z ǀ -2 ≤ x < 4}
A. P = { -2; -1; 0; 1; 2; 3; 4}.          B. P = {-1; 0; 1; 2; 3; 4}.
C. P = {-1; 0; 1; 2; 3}.                      D. P = {-2; -1; 0; 1; 2; 3}.

22-a

23-a

6 + 1 = 7     5 + 2 = 7     4 + 3 = 7

1 + 6 = 7     2 + 5 = 7     3 + 4 = 7

7 - 6 = 1     7 - 5 = 2     7 - 4 = 3

7 - 1 = 6     7 - 2 = 5     7 - 3 = 4

6+1=7

1+6=7

7-6=1

7-1=6

5+2=7

2+5=7

7-5=2

7-2=5

4+3=7

3+4=7

7-4=3

7-3=4

Lời giải chi tiết: