Tính
a)\(10-\frac{9}{16}\)
b)\(\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)\)
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Câu 1:
A = (4/9 + 5/6) : (7/8 - 7/12)
A = (8/18 + 15/18) :(21/24 - 14/24)
A = 23/18 : 7/24
A = 23/18 x 24/7
A = 92/21
Câu B = 3/4.8/9.15/16...9999/10000
B = \(\frac{1.3}{2.2}\).\(\frac{2.4}{3.3}\)....\(\frac{99.101}{100.100}\)
B = \(\frac{1.2.3\ldots99}{2.3\ldots100}\). \(\frac{3.4.\ldots101}{2.3\ldots100}\)
B = \(\frac{1}{100}\) x \(\frac{101}{2}\)
B = \(\frac{101}{200}\)
\(a,\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
\(=\frac{\left(2^4\right)^3.3^{10}+2^3.3.5.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{11}}\)
\(=\frac{2^{12}.3^{10}+2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(2.3+1\right)}\)
\(=\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.7}=\frac{2.6}{3.7}=\frac{4}{7}\)
a) \(\frac{\left(-1\right)}{4}^2+\frac{3}{8}.\left(\frac{-1}{6}\right)-\frac{3}{16}:\left(\frac{-1}{2}\right)=\left(\frac{-1}{4}\right)^2+\left(\frac{-3}{68}\right)-\left(\frac{-3}{8}\right)=\left(\frac{1}{16}\right)+\left(\frac{-3}{68}\right)-\left(\frac{-3}{8}\right)=\frac{5}{272}-\left(\frac{-3}{8}\right)=\frac{107}{272}\)
Câu a:
(4 5/37 - 3 4/5 + 8 15/29) - (3 5/37 - 6 14/29)
= (4 5/37 - 3 5/37) + (8 15/29 + 6 14/29) - 3 4/5
= 1 + 15 - 3 4/5
= 16 - 3 - 4/5
= 13 - 4/5
= 61/5
Câu b:
(2\(\frac56\) + 1\(\frac49\)) : (10\(\frac{1}{12}\) - 9\(\frac12\))
= (17/6 + 13/9) :(121/12 - 19/2)
= (51/18 + 26/18) :(121/12 - 114/2)
= 77/18 : 7/12
= 77/18 x 12/7
= 22/3
A= 7/8:(4/18-1/18)+7/8:(1/36-15/36)
=7/8:1/6+7/8:(-7/18)
=7/8:(1/6+-7/18)=7/8:(3/18+-7/18)=7/8:(-2/9)=-63/18=-7/2
a) \(10-\frac{9}{16}=\frac{160}{16}-\frac{9}{16}=\frac{151}{16}\)
b) \(\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)=\frac{2}{3}-\frac{1}{6}-\frac{1}{8}=\frac{16}{24}-\frac{4}{24}-\frac{3}{24}=\frac{9}{24}=\frac{3}{8}\)
a)10-\(\frac{9}{16}\)
=\(\frac{160}{16}-\frac{9}{16}\)
\(=\frac{151}{16}\)
b)\(\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)\)
=\(\frac{2}{3}-\left(\frac{4+3}{24}\right)\)
=\(\frac{2}{3}-\frac{7}{24}=\frac{16-7}{24}\)
=\(\frac{3}{8}\)