a, (4568 + 3759) - (4563 + 3764)

 = 4568 + 3759 - 4563 - 3764

= ( 4568 - 4563) + 3759 - 3764

= 5 + 3759 - 3764

= 3764 - 3764

= 0

b, 25.16 - 25.12

= 25. (16 - 12)

= 25. 4

= 100

c, 930 : 15 - 310: 5 + 196

= 930 : 3 : 5 - 310 : 5 + 196

= 310 : 5 - 310 : 5 + 196

= 196

d, 572 : 26 - 156 : 13

= 572 : 2 : 13 - 156 : 13

=  286 : 13 - 156 : 13

= ( 286 - 156) : 13

= 130 : 13

= 10 

Em cảm ơn cô rất nhiều a

5

930:15-310*5+196

=62-1550+196

=-1292

a, 24.36-24.(-64)

= 24. [36-(-64)]

= 24.100

= 2400

b, 98.15-49.(-70)

= 49.2.15 - 49.(-70)

= 49.30 - 49.(-70)

= 49.[30-(-70)]

= 49.100

= 4900

a)       \(24.36-24.\left(-64\right)\)

\(=24.36+24.64\)

\(=24.\left(36+64\right)\)

\(=24.100\)\(=2400\)

b)      \(98.15-49.\left(-70\right)\)

\(=49.2.15+49.70\)

\(=49.30+49.70\)

\(=49.\left(30+70\right)\)

\(=49.100\)\(=4900\)

3/2-5/6+7/12-9/20+11/30-13/42+15/56-17/72

=1.5-0.8(3)+0.58(3)-0.3(6)-0.3(095238)+0.267(857142)-0236(1)

=0.(8)

a) 930 : 15 - 310 : 5 + 196 =930:15-930:15+196=62-62+196=0+196=196

b)572:26-156:13=572:26-312:26=(572-312):26=260:26=10

cảm ơn nha

dấu . là nhân hay là phần ngăn cách ở hàng phần nghìn thế

a) \(28400:\left(100\times311-310\times100\right)\)
\(=28400:\left[\left(311-310\right)\times100\right]\)
\(=28400:100\)
\(=284\)
b) \(\dfrac{5}{11}+\dfrac{19}{15}+\dfrac{6}{11}+\dfrac{11}{16}+\dfrac{6}{15}+\dfrac{5}{16}\)
\(=\left(\dfrac{5}{11}+\dfrac{6}{11}\right)+\left(\dfrac{19}{15}+\dfrac{6}{15}\right)+\left(\dfrac{11}{16}+\dfrac{5}{16}\right)\)
\(=1+\dfrac{5}{3}+1\)
\(=\dfrac{8}{3}+1\)
\(=\dfrac{11}{3}\)

\(-23.63+23.21-58.23\\ =23.\left(-63\right)+23.21-58.23\\ =23\left(-63+21-58\right)\\ =23.\left(-100\right)=-2300\)

-23 . 63 + 23 . 21 - 58 . 23

= 23 . (-63 + 21 - 58) = 23 . (-100) = -2300