1: \(VP=\left(ac+bd\right)^2+\left(ad-bc\right)^2\)

\(=a^2c^2+b^2d^2+2acbd+a^2d^2+b^2c^2-2bacd\)

\(=a^2c^2+b^2d^2+a^2d^2+b^2c^2\)

\(=c^2\left(a^2+b^2\right)+d^2\left(a^2+b^2\right)\)

\(=\left(a^2+b^2\right)\left(c^2+d^2\right)=VT\)

2: \(\left(a+b+c\right)^3-a^3-b^3-c^3\)

\(=\left(a+b+c-a\right)\left[\left(a+b+c\right)^2+a\left(a+b+c\right)+a^2\right]-\left(b^3+c^3\right)\)

\(=\left(b+c\right)\left(a^2+b^2+c^2+2ab+2ac+2bc+a^2+ab+ac+a^2\right)-\left(b+c\right)\left(b^2-bc+c^2\right)\)

\(=\left(b+c\right)\left(3a^2+b^2+c^2+3ab+2ac+2bc-b^2+bc-c^2\right)\)

\(=\left(b+c\right)\left(3a^2+3ab+3ac+3bc\right)\)

\(=3\left(b+c\right)\left[a\left(a+b\right)+c\left(a+b\right)\right]\)

\(=3\left(b+c\right)\left(a+c\right)\left(a+b\right)\)

=>\(\left(a+b+c\right)^3=a^3+b^3+c^3+3\left(a+b\right)\left(b+c\right)\left(c+a\right)\)

1: $VP={\left(ac+bd\right)}^2+{\left(ad-bc\right)}^2$

$=a^2{c}^2+b^2{d}^2+2acbd+a^2{d}^2+b^2{c}^2-2bacd$

$=a^2{c}^2+b^2{d}^2+a^2{d}^2+b^2{c}^2$

$=c^2(a^2+$

g: =4/9(-3/4+27/4)-14/3

=4/9*6-14/3

=8/3-14/3

=-6/3=-2

h: =11/7-3/5-4/9-4/7+8/5-5/9

=8/5

k: =-9/4(2/7-16/7)-2/3

=-9/4*(-2)-2/3

=9/2-2/3

=27/6-4/6

=23/6

m: =9/17*3/11-9/17*12/11-9/17*13/11

=9/17(3/11-12/11-13/11)

=9/17*(-2)=-18/17

1 Life in the country is not as good as life in the city

2 These room are cleaned every evening

3 Would you mind decorating the christmas tree

4 It's the first time I have talked to the headmaster

V

1 have ever met

2 worked

3 reading

4 are looking - seeing

5 was

VI

1A

2A

3D

4D

5B

IV/

1. is not as good as life in the city

2. are cleaned every evening

3. decorating the Christmas tree?

4. the first time I have (ever) talked to the headmaster

V/

1. have ever met

2. worked

3. reading

4. are looking - seeing

5. was

VI/

1a 2a 3d 4d 5b

hình thì đăng 1 câu thôi:)

Giúp ik

1: \(\left(-5\right)+8-7=8+\left(-5-7\right)\)

=-12+8

=-4

2: \(\left(-8\right)+2+8=\left(-8+8\right)+2=0+2=2\)

3: \(\left(-1\right)+3+1\)

\(=\left(-1+1\right)+3\)

=0+3

=3

4: \(\left(-6\right)+8-14\)

\(=\left(-6-14\right)+8\)

=-20+8

=-12

5: \(\left(-4\right)+3-7\)

\(=\left(-4-7\right)+3\)

=-11+3

=-8

6: \(\left(-4\right)+5-2\)

\(=\left(-4-2\right)+5\)

=-6+5

=-1

1.

a) \(2^x=128\)

\(2^x=2^7\)

\(=>x=7\)

b) \(8^{x-1}=64\)

\(8^{x-1}=8^2\)

\(=>x-1=2\)

\(x=2+1\)

\(=>x=3\)

c) \(3+3^x=30\)

\(3^x=30-3\)

\(3^x=27=3^3\)

\(=>x=3\)

d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?

e) \(3^2.x=3^5\)

\(x=3^5:3^2\)

\(=>x=3^3=27\)

f) \(\left(2x-1\right)^3=343\)

\(\left(2x-1\right)^3=7^3\)

\(=>2x-1=7\)

\(2x=7+1\)

\(2x=8\)

\(x=8:2\)

\(=>x=4\)

\(#Wendy.Dang\) 

a,\(2^x\)=128           b,\(8^{x-1}\)=64              c,3+\(3^x\)=30           d,x+2=64

\(2^7\)=128               \(8^{x-1}\)=\(8^2\)                 \(3^x\)=30-3                  x=64-2

=>x=7              =>x-1=2                  \(3^x\)=27                      x=62

                         x=2+1=3                \(3^x\)=\(3^3\)

                                                     =>x=3

e,\(3^2\).x=\(3^5\)                             f,(2x-\(1^3\))=343

x=\(3^5\):\(3^2\)                                 2x=1+343

x=27                                     2x=344

                                               x=344:2

                                               x=172

Gọi số ngày cả ba gặp lại nhau cần tìm là x ( ngày) ( x thuộc n sao) Theo đề bài ta có: x chia hết cho 15,20,12 và x ít nhất => x = BCNN ( 15, 20,12). Ta có:

15 = 3.5

20= 2 mũ 2 . 5

12= 2 mũ 2 . 3

=> BCNN ( 15, 20, 12) = 2 mũ 2 . 3. 5 = 60

Vậy số này ít nhất cả 3 tàu gặp lại nhau là 60 ngày