a: 29+131+237+763

=160+1000

=1160

b: 65+327+15+73

=65+15+327+73

=80+400

=480

c: \(12+54:8-8\)

=12+3-8

=15-8

=7

d: \(45\cdot58+45\cdot42\)

\(=45\cdot\left(58+42\right)\)

\(=45\cdot100=4500\)

e: \(35\cdot34+35\cdot26+40\cdot35\)

\(=35\cdot\left(34+26+40\right)\)

\(=35\cdot100=3500\)

f: \(65\cdot25+65\cdot45+30\cdot65\)

\(=65\cdot\left(25+45+30\right)\)

\(=65\cdot100=6500\)

g: \(750:\left\lbrace32-\left\lbrack2^2+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace+100\)

\(=\frac{750}{32-\left\lbrack4+5\cdot9-42\right\rbrack}+100=\frac{750}{32-4-45+42}+100\)

\(=\frac{750}{28-3}+100\)

=750:25+100

=30+100

=130

h: \(\left\lbrace630:\left\lbrack16+3\cdot\left(6+3\cdot4\right)\right\rbrack\right\rbrace-1\)

\(=\frac{630}{16+3\cdot\left(6+12\right)}-1=\frac{630}{16+3\cdot18}-1\)

\(=\frac{630}{70}-1\)

=9-1=8

i: \(5871:\left\lbrack928-\left(247-82\right)\cdot5\right\rbrack+2175^0\)

\(=\frac{5871}{928-165\cdot5}+1\)

\(=\frac{5871}{928-825}+1=\frac{5871}{103}+1=57+1=58\)

k: \(375:\left\lbrace32-\left\lbrack4+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace-14\)

\(=\frac{375}{32-\left\lbrack4+5\cdot9-42\right\rbrack}-14\)

\(=\frac{375}{32-\left\lbrack4+45-42\right\rbrack}-14=\frac{375}{32-\left(4+3\right)}-14=\frac{375}{32-7}-14\)

\(=\frac{375}{25}-14\)

=15-14

=1

a)x=37

b)x=-28

c)x=-48

d)x=15

áp dụng kiến thức tính nhanh ý

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50=1275

=1275

=1245

1 + 2 + 3 +...+ 50

Dãy trên có số số hạng là:

\(\left(50-1\right)+1=50\) (số)

Tổng của chúng là:

\(\frac{\left(50+1\right)\cdot50}{2}=1275\)

Vậy tổng của chúng là 1275

~Học tốt~

=1275

a: \(A=3^{100}-3^{99}+3^{98}-...+3^2-3\)

=>\(3A=3^{101}-3^{100}+3^{99}-...+3^3-3^2\)

=>\(4A=3^{101}-3\)

=>\(A=\dfrac{3^{101}-3}{4}\)

b: \(B=\left(-2\right)^0+\left(-2\right)^1+...+\left(-2\right)^{2024}\)

=>\(B\cdot\left(-2\right)=\left(-2\right)^1+\left(-2\right)^2+...+\left(-2\right)^{2025}\)

=>\(-2B-B=\left(-2\right)^1+\left(-2\right)^2+...+\left(-2\right)^{2025}-\left(-2\right)^0-\left(-2\right)^1-...-\left(-2\right)^{2024}\)

=>\(-3B=-2^{2025}-1\)

=>\(B=\dfrac{2^{2025}+1}{3}\)

c: \(C=\left(-\dfrac{1}{5}\right)^0+\left(-\dfrac{1}{5}\right)^1+...+\left(-\dfrac{1}{5}\right)^{2023}\)

=>\(\left(-\dfrac{1}{5}\right)\cdot C=\left(-\dfrac{1}{5}\right)^1+\left(-\dfrac{1}{5}\right)^2+...+\left(-\dfrac{1}{5}\right)^{2024}\)

=>\(\left(-\dfrac{6}{5}\right)\cdot C=\left(-\dfrac{1}{5}\right)^{2024}-\left(-\dfrac{1}{5}\right)^0\)

=>\(C\cdot\dfrac{-6}{5}=\dfrac{1}{5^{2024}}-1=\dfrac{1-5^{2024}}{5^{2024}}\)

=>\(C\cdot\dfrac{6}{5}=\dfrac{5^{2024}-1}{5^{2024}}\)

=>\(C=\dfrac{5^{2024}-1}{5^{2024}}:\dfrac{6}{5}=\dfrac{5^{2024}-1}{6\cdot5^{2023}}\)

Các số có căn bậc hai:

a = 0              c = 1              d = 16 + 9

e = 32 + 42              h = (2-11)2              i = (-5)2

l = √16              m = 34              n = 52 - 32

Căn bậc hai không âm của các số đó là:

a ) 25 - ( - 75 ) + 32 - ( 32 + 75

= 25 + 75 + 32 - 32 - 75

= 100 + 0 - 75

= 25

b ) 24 . ( 16 - 5 ) - 16 . ( 24 - 15 )

= 24 . 11 - 16 . 9

= 264 - 144

= 120

c ) 29 . ( 19 - 13 ) - 19 - ( 29 - 13 )

29 . 6 - 19 - 29 + 13

= 174 - 19 - 29 + 13

= 126 + 13

= 139

d ) ( 55 + 45 15 ) - ( 15 - 55 + 45 )

= 4570 - 15 + 10

= 4555 + 10

= 4565

- Cái này dùng Quy Tắc Phá Ngoặc