A:

\(Cu\left(OH\right)_2--to->CuO+H_2O\)

\(CuO+2HCl-->CuCl_2+H_2O\)

\(CuCl_2+2NaOH-->Cu\left(OH\right)_2+2NaCl\)

\(Cu\left(OH\right)_2+H_2SO_4-->CuSO_4+2H_2O\)

B:

\(Mg\left(OH\right)_2--to->MgO+H_2O\)

\(MgO+2HCl-->MgCl_2+H_2O\)

\(MgCl_2+2NaOH-->Mg\left(OH\right)_2+2NaCl\)

\(Mg\left(OH\right)_2+H_2SO_4-->MgSO_4+2H_2O\)

A: Cu(OH)₂ \(\underrightarrow{t^o}\) CuO + H₂O

CuO + 2HCl \(\rightarrow\) CuCl₂ + H₂O

CuCl₂ +2 NaOH \(\rightarrow\) Cu(OH)₂ + NaCl

Cu(OH)₂ + H₂SO₄ \(\rightarrow\) CuSO₄ + 2H₂O

B: Mg(OH)₂ \(\underrightarrow{t^o}\) 2MgO + H₂O

MgO + 2HCl \(\rightarrow\) MgCl₂ + H₂O

MgCl₂ + 2NaOH \(\rightarrow\) Mg(OH)₂ + NaCl

Mg(OH)₂ + H₂SO₄ \(\rightarrow\) MgSO₄ + 2H₂O

Giải được câu A rồi thì câu B làm tương tự thôi

\(\text{CuO+2HCl(dung dịch pha loãng)=CuCl2+H2O}\)

\(\text{Ca(OH)2+CuCl2→Cu(OH)2↓+CaCl2}\)

\(\text{Cu(OH)2 → CuO + H2O}\)

\(\text{CuO + H2SO4 → H2O + CuSO4}\)

\(\text{CuSO4(dung dịch pha loãng)+H2=Cu↓+H2SO4}\)

PT cuối sai

\(CuO+2HCl->CuCl_2+H_2O\)

\(CuCl_2+2NaOH->Cu\left(OH\right)_2+2NaCl\)

\(Cu\left(OH\right)_2->CuO+H_2O\) (Nhiệt độ nữa nha bạn)

\(CuO+H_2SO_4->CuSO_4+H_2O\)

\(CuSO_4\:+Fe->FeSO_4+Cu\)

\(Cu+2AgNO_3->Cu\left(NO_3\right)_2+2Ag\)

Cu + Cl₂ --t^o--> CuCl₂

CuCl₂ + NaOH ----> NaCl + Cu(OH)₂

Cu(OH)₂ + H₂SO₄ ---->CuSO₄ + 2H₂O

CuSO₄ + Fe ----> FeSO₄ + Cu

A: Cu(OH)2 \(\underrightarrow{t^o}\) CuO + H2O

CuO + 2HCl CuCl2 + H2O

CuCl2 +2 NaOH Cu(OH)2 + NaCl

Cu(OH)2 + H2SO4 CuSO4 + 2H2O

B: Mg(OH)2 \(\underrightarrow{t^o}\) 2MgO + H2O

MgO + 2HCl MgCl2 + H2O

MgCl2 + 2NaOH Mg(OH)2 + NaCl

Mg(OH)2 + H2SO4 MgSO4 + 2H2O

Na hóa trị I mà

a) 2Ca + O₂ => 2CaO

CaO + H₂O => Ca(OH)₂

Ca(OH)₂ + CuCl₂ => CaCl₂ + Cu(OH)₂↓

b) 4FeS₂ + 11O₂ => 2Fe₂O₃ + 8SO₂↑

2SO₂ + O₂ => 2SO₃

_{xt V2O5}

SO₃ + H₂O => H₂SO₄

H₂SO₄ + Ba(NO₃)₂ => 2HNO₃ + BaSO₄↓

c) 3Fe + 2O₂ => Fe₃O₄

Fe₃O₄ + 4H₂SO₄ => FeSO₄ + Fe₂(SO₄)₃ + 4H₂O

Fe₂(SO₄)₃ + 3Ba(OH)₂ => 2Fe(OH)₃↓ + 3BaSO₄↓

d) 4FeS₂ + 11O₂ => 2Fe₂O₃ + 8SO₂↑ ( M : SO₂)

2SO₂ + O₂ => 2SO₃ (N : SO₃)

_{xt V2O5}

SO₃ + H₂O => H₂SO₄ (D : H₂SO₄)

H₂SO₄ + CuO => CuSO₄ + H₂O

e) CuSO₄ + BaCl₂ => CuCl₂ + BaSO4↓ (X : CuCl2)

CuCl₂ + 2NaOH => 2NaCl + Cu(OH)₂↓ (Y : Cu(OH)₂)

Cu(OH)₂ => CuO + H₂O (Z : CuO)

CuO + H₂ => Cu + H₂O

a) 2Ca + O2 => 2CaO

CaO + H2O => Ca(OH)2

Ca(OH)2 + CuCl2 => CaCl2 + Cu(OH)2

b) 4FeS2 + 11O2 => 2Fe2O3 + 8SO2

2SO2 + O2 => 2SO3

SO3 + H2O => H2SO4

H2SO4 + Ba(NO3)2 => 2HNO3 + BaSO4

c) 3Fe + 2O2 => Fe3O4

Fe3O4 + 4H2SO4 => FeSO4 + Fe2(SO4)3 + 4H2O

Fe2(SO4)3 + 3Ba(OH)2 => 2Fe(OH)3 + 3BaSO4

d) 4FeS2 + 11O2 => 2Fe2O3 + 8SO2↑

2SO2 + O2 => 2SO3

SO3 + H2O => H2SO4

H2SO4 + CuO => CuSO4 + H2O

e) CuSO4 + BaCl2 => CuCl2 + BaSO4

CuCl2 + 2NaOH => 2NaCl + Cu(OH)2

Cu(OH)2 => CuO + H2O

CuO + H2 => Cu + H2O

CuSO₄ + BaCl₂ → CuCl₂ + BaSO₄↓

CuCl₂ + 2NaOH → 2NaCl + Cu(OH)₂↓

Cu(OH)₂ \(\underrightarrow{to}\) CuO + H₂O

CuO + 2HNO₃ → Cu(NO₃)₂ + H₂O

c) 4FeS2+ 11O2--->8SO2 +2Fe2O3

Fe2O3+3H2--->2Fe+3H2O

2Fe +6HCl--->2FeCl3 +3H2

FeCl3+3NaOH--->Fe(OH)3+ 3NaCl

2Fe(OH)3 +3H2SO4---->Fe2(SO4)3 +3H2O

d)2 Fe +6HCl-->2FeCl3+3H2

FeCl3 + 3NaOH--->Fe(OH)3 +3NaCl

2Fe(OH)3 --->Fe2O3 +3H2O

e) Fe +2HCl---.FeCl2 +H2

FeCl2+2NaOH---->Fe(OH)2 +2NaCl

Fe(OH)2 +2AgNO3---> Fe(NO3)2 +2AgOH

Chúc bạn học tốt

Nhớ tích cho mình nhé

a) 4K+ O2--->2K2O

K2O+H2O-------->.2KOH

KOH+ NaCO3--->K2CO3+NaOH

K2CO3+2HCl---->2KCl+H20+CO2

B) 2Cu+O2---->2CuO

CuO+H2SO4---->CuSO4+ H2O

CuSO4+ 2NaOH--->Cu(OH)2 +Na2SO4

Cu(OH)2----->CuO+H2O

2CuO--->2Cu+O2

Chúc bn học tốt