Biểu thức 1

$3\dfrac12\cdot\dfrac4{49}-\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{8}\right)$

$=\dfrac72\cdot\dfrac4{49}-\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\left(-\dfrac4{21}\right)$

$=\dfrac27-6\cdot\left(-\dfrac4{21}\right)$

$=\dfrac27+\dfrac87$

$=\dfrac{10}{7}.$

Biểu thức 2

$\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot3\dfrac13\right):\dfrac43$

$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac{10}{3}\right):\dfrac43$

$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac43\cdot\dfrac34$

$=\dfrac{10}{81}\cdot\dfrac{99}{250}-1$

$=\dfrac{11}{225}-1$

$=-\dfrac{214}{225}.$

Biểu thức 1

$A=3\dfrac12\cdot\dfrac4{49}\cdot\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{5}\right)$

$=\dfrac72\cdot\dfrac4{49}\cdot\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\dfrac5{-42}$

$=\dfrac72\cdot\dfrac4{49}\cdot6\cdot\dfrac5{-42}$

$=\dfrac{12}{7}\cdot\dfrac5{-42}$

$=\dfrac{60}{-294}$

$=-\dfrac{10}{49}.$

Biểu thức 2

$B=\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot1\dfrac13\right):\dfrac43$

$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac43\right):\dfrac43$

$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac{8}{15}\cdot\dfrac34$

$=\dfrac{10}{81}\cdot\dfrac{99}{250}-\dfrac25$

$=\dfrac{11}{225}-\dfrac{90}{225}$

$=-\dfrac{79}{225}.$

bn đổi ngược hai vế cho nhau là ra 1 bài toán bình thường thôi

Bài nỳ tuy rất dài nhưng cũng dễ

Chí cần cậu cuyển VT sang VP rồi tìm x bình thường

Chúc cậu học tốt

\(\left(5-\frac{43}{10}\right)-\left(\frac{42}{19}-\left(\frac{7}{2}-\frac{59}{10}\right)\right)+\frac{42}{19}+\frac{59}{10}+\frac{4}{5}\)

\(=5-\frac{43}{10}-\left(\frac{42}{19}-\frac{7}{2}+\frac{59}{10}\right)+\frac{42}{19}+\frac{59}{10}+\frac{4}{5}\)

\(=5-\frac{43}{10}-\frac{42}{19}+\frac{7}{2}-\frac{59}{10}+\frac{42}{19}+\frac{59}{10}+\frac{4}{5}\)

\(=5-\frac{43}{10}+\frac{7}{2}+\frac{4}{5}\)

\(=5+\frac{35}{10}+\frac{8}{10}-\frac{43}{10}=5\)

Đúng rùi bn

BN mún hỏi j vậy, đây k phải câu hỏi, mà có thì phải là toán lớp 6