5/7=5x9/7x9=45/63

4/9=4x7/9x7=28/63

=>đáp án B

C

a) x-28:7=16

    x-4=16

    x=16+4

    x=20

Vậy x=20

b)3x-63=9³⁰:9²⁸

   3(x-21)=81

   x-21=27

   x=21+27

  x=48

Vậy x=48

a, x-28:7=16

x-4=16

x=16+4

x=20

b, 3x-63=9^30:9^28

3x-63=9^2

3x-63=81

3x=81+63

3x=144

x=144:3

x=48

a) x - 28 : 7 = 16

x - 4 = 16

x = 16 + 4

x = 20

b) 3x - 63 = 9³⁰ : 9²⁸

3x - 63 = 9²

3x - 63 = 81

3x = 81 - 63

3x = 18

x = 18 : 3

x = 6

A = 1 + 3 + 5 + 7 +...+ 19

Dãy số trên là dãy số cách đều với khoảng cách là:  3 - 1 = 2

Số số hạng của dãy số trên là: ( 19 - 1): 2 + 1  = 10 

A = ( 19 + 1) \(\times\) 10 : 2 = 100

  52 - 42 + 37 + 28 - 38 + 63

= ( 52 + 28) - ( 42 + 38) + ( 37 + 63)

= 80 - 80 + 100

= 100 

 1 + 3 + 5 + 7 + 9+ 11 + 13 + 15 + 17 + 19

= (1+ 19) + (3 + 17) + (5 + 15) + (7 + 13) + (9 + 11)

= 20 + 20 + 20 + 20 + 20

= 100

 52 - 42 + 37 + 28 - 38 + 63

= (52 + 28) - ( 42 + 38) + (37 + 63)

= 80 - 80 + 100

= 100

Tick cho mình nhé!

Cgcr

bạn làm đúng rồi đấy

1: \(\sqrt{147}+\sqrt{54}-4\sqrt{27}\)

\(=7\cdot\sqrt3+3\sqrt6-4\cdot3\sqrt3\)

\(=3\sqrt6+7\sqrt3-12\sqrt3=3\sqrt6-5\sqrt3\)

2: \(\sqrt{28}-4\cdot\sqrt{63}+7\cdot\sqrt{112}\)

\(=2\sqrt7-4\cdot3\sqrt7+7\cdot4\sqrt7\)

\(=2\sqrt7-12\sqrt7+28\sqrt7=18\sqrt7\)

3: \(\sqrt{49}-5\cdot\sqrt{28}+\frac12\cdot\sqrt{63}\)

\(=7-5\cdot2\sqrt7+\frac12\cdot3\sqrt7=7-10\sqrt7+1,5\sqrt7=7-8,5\cdot\sqrt7\)

4: \(\left(2\sqrt6-4\sqrt3-\frac14\sqrt8\right)\cdot3\sqrt6\)

\(=6\cdot\sqrt{36}-12\sqrt{18}-\frac14\cdot2\cdot\sqrt2\cdot3\sqrt6\)

\(=36-36\sqrt2-\frac32\sqrt{12}=36-36\sqrt2-3\sqrt3\)

6: \(\left(\sqrt{48}-3\sqrt{27}-\sqrt{147}\right):\sqrt3=\sqrt{\frac{48}{3}}-3\cdot\sqrt{\frac{27}{3}}-\sqrt{\frac{147}{3}}\)

\(=\sqrt{16}-3\cdot\sqrt9-\sqrt{49}=4-3\cdot3-7\)

=-3-9

=-12

5: \(\left(2\cdot\sqrt{1\frac{9}{16}}-5\cdot\sqrt{5\frac{1}{16}}\right):\sqrt{16}\)

\(=\left(2\cdot\sqrt{\frac{25}{16}}-5\cdot\sqrt{\frac{81}{16}}\right):\sqrt{16}\)

\(=\left(2\cdot\frac54-5\cdot\frac94\right):4=\frac{10-45}{4\cdot4}=\frac{-35}{16}\)

7: \(\left(\sqrt{50}-3\sqrt{49}\right):\sqrt2-\sqrt{162}:\sqrt2\)

\(=\left(5\sqrt2-21\right):\sqrt2-9\sqrt2:\sqrt2\)

\(=5-\frac{21}{\sqrt2}-9=-4-\frac{21\sqrt2}{2}=\frac{-8-21\sqrt2}{2}\)

8: \(\left(2\cdot\sqrt{1\frac{9}{10}}-\sqrt{5\frac{1}{10}}\right):\sqrt{10}=\left(2\cdot\sqrt{\frac{19}{10}}-\sqrt{\frac{51}{10}}:\sqrt{10}\right)\)

\(=2\cdot\frac{\sqrt{19}}{10}-\frac{\sqrt{51}}{10}=\frac{2\sqrt{19}-\sqrt{51}}{10}\)

9: \(2\cdot\sqrt{\frac{16}{3}}-3\cdot\sqrt{\frac{1}{27}}-6\cdot\sqrt{\frac{4}{75}}\)

\(=2\cdot\frac{4}{\sqrt3}-3\cdot\frac{1}{3\sqrt3}-6\cdot\frac{2}{5\sqrt3}\)

\(=\frac{8}{\sqrt3}-\frac{1}{\sqrt3}-\frac{12}{5\sqrt3}=\frac{7}{\sqrt3}-\frac{12}{5\sqrt3}=\frac{7\sqrt3}{3}-\frac{12\sqrt3}{15}=\frac{35\sqrt3-12\sqrt3}{15}=\frac{23\sqrt3}{15}\)

10: \(2\sqrt{27}-6\cdot\sqrt{\frac43}+\frac35\cdot\sqrt{75}\)

\(=2\cdot3\sqrt3-6\cdot\frac{2}{\sqrt3}+\frac35\cdot5\sqrt3\)

\(=6\sqrt3-4\sqrt3+3\sqrt3=5\sqrt3\)

11: \(\frac{\sqrt{18}}{\sqrt2}-\frac{\sqrt{12}}{\sqrt3}=\sqrt9-\sqrt4=3-2=1\)

a) 1+2+3+4+5+6+7+8+9

= (1+9)+(2+8)+(3+7)+(4+6)+5

= 10+10+10+10=5

= 45

b) 19+28+37+46+81+72+63+54

= (19+81)+(28+72)+(46+54)+(63+37)

= 100+100+100+100

= 400

3/4x = -6/7

=> x = -6/7 : 3/4

=> x = -8/7

7/9 - 2/3x = -5/6

=> 2/3x = 7/9 - ( - 5/6 )

=> 2/3x = 19/18

=> x = 19/18 : 2/3

=> x = 19/12