Bài 1: Nối hai phân số bằng nhau 2/3
4/7 48/100 45/81 28/49 5/9 12/25 36/54Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 1:
a: Cách 1: \(\frac37=\frac{3\cdot9}{7\cdot9}=\frac{27}{63};\frac59=\frac{5\cdot7}{9\cdot7}=\frac{35}{63}\)
mà 27<35
nên \(\frac37<\frac59\)
Cách 2: Ta có: \(\frac37=\frac{3\cdot5}{7\cdot5}=\frac{15}{35}\)
\(\frac59=\frac{5\cdot3}{9\cdot3}=\frac{15}{27}\)
mà \(\frac{15}{35}<\frac{15}{27}\left(35>27\right)\)
nên \(\frac37<\frac59\)
b: Cách 1: \(\frac{6}{12}=\frac{6\cdot3}{12\cdot3}=\frac{18}{36};\frac49=\frac{4\cdot4}{9\cdot4}=\frac{16}{36}\)
mà 18>16
nên \(\frac{6}{12}>\frac49\)
Cách 2: \(\frac{6}{12}=\frac{6\cdot2}{12\cdot2}=\frac{12}{24};\frac49=\frac{4\cdot3}{9\cdot3}=\frac{12}{27}\)
mà \(\frac{12}{24}>\frac{12}{27}\left(24<27\right)\)
nên \(\frac{6}{12}>\frac49\)
c: Cách 1: \(\frac{15}{25}=\frac{15\cdot18}{25\cdot18}=\frac{270}{450};\frac{54}{90}=\frac{54\cdot5}{90\cdot5}=\frac{270}{450}\)
Do đó: \(\frac{15}{25}=\frac{54}{90}\)
Cách 2: \(\frac{15}{25}=\frac{15:5}{25:5}=\frac35;\frac{54}{90}=\frac{54:18}{90:18}=\frac35\)
do đó: \(\frac{15}{25}=\frac{54}{90}\)
d: Cách 1: \(\frac{25}{30}=\frac{25\cdot3}{30\cdot3}=\frac{75}{90};\frac{75}{28}=\frac{75\cdot1}{28\cdot1}=\frac{75}{28}\)
mà \(\frac{75}{90}<\frac{75}{28}\left(90>28\right)\)
nên \(\frac{25}{30}<\frac{75}{28}\)
Cách 2: \(\frac{25}{30}=\frac{25\cdot14}{30\cdot14}=\frac{350}{420}\)
\(\frac{75}{28}=\frac{75\cdot15}{28\cdot15}=\frac{1125}{420}\)
mà 350<1125
nên \(\frac{25}{30}<\frac{75}{28}\)
e: cách 1: \(\frac{27}{45}=\frac{27\cdot4}{45\cdot4}=\frac{108}{180};\frac{18}{36}=\frac{18\cdot5}{36\cdot5}=\frac{90}{180}\)
mà 108>90
nên \(\frac{27}{45}>\frac{18}{36}\)
Cách 2: \(\frac{27}{45}=\frac{27\cdot2}{45\cdot2}=\frac{54}{90}\)
\(\frac{18}{36}=\frac{18\cdot3}{36\cdot3}=\frac{54}{108}\)
mà \(\frac{54}{90}>\frac{54}{108}\left(90<108\right)\)
nên \(\frac{27}{45}>\frac{18}{36}\)
\(\frac{2}{3}=\frac{36}{54}\)
\(\frac{4}{7}=\frac{28}{49}\)
\(\frac{48}{100}=\frac{12}{25}\)
\(\frac{45}{81}=\frac{5}{9}\)
\(\dfrac{5}{6}=\dfrac{15}{18}\)
\(\dfrac{9}{11}=\dfrac{27}{33}\)
\(\dfrac{5}{8}=\dfrac{25}{40}\)
\(\dfrac{12}{16}=\dfrac{36}{48}\)
\(\dfrac{8}{12}=\dfrac{40}{60}\)
\(\dfrac{4}{7}-\dfrac{1}{3}< \dfrac{1}{2}-\dfrac{2}{9}\)
\(\dfrac{125}{100}-\dfrac{48}{64}< \dfrac{6}{7}-\dfrac{14}{28}\)
\(\dfrac{7}{5}-\dfrac{22}{25}=\dfrac{1}{5}+\dfrac{4}{10}\)\(\dfrac{45}{75}+\dfrac{22}{33}>\dfrac{4}{5}+\dfrac{4}{6}\)
a) 3/7 + 4/9 + 4/7 + 5/9
= ( 3/7 + 4/7 ) + ( 4/9 + 5/9 )
= 7/7 + 9/9
= 1 + 1
= 2
b)1/5 + 4/10 + 9/15 + 16/20 + 25/25 + 36/30 + 49/35 + 64/40 + 81/45
= 1/5 + 2/5 + 3/5 + 4/5 + 5/5 + 6/5 + 7/5 + 8/5 + 9/5
= ( 1/5 + 9/5 ) + ( 2/5 + 8/5 ) + (7/5 + 3/5 ) + ( 4/5 + 6/5 ) + 5/5
= 2 + 2 + 2 + 2 + 1
= 2 x 4 + 1
= 8 +1
= 9
c) 1/8 + 1/12 + 3/8 + 5/12
= ( 1/8 + 3/8 ) + ( 1/12 + 5/12)
= 4/8 + 6/12
= 1/2 + 1/2
= 2/4 = 1/2
mỏi tay rồi
d; (1 - \(\dfrac{1}{2}\)) x (1 - \(\dfrac{1}{3}\)) x (1 - \(\dfrac{1}{4}\)) x ... x ( 1 - \(\dfrac{1}{100}\))
= \(\dfrac{1}{2}\) x \(\dfrac{2}{3}\) x \(\dfrac{3}{4}\) x \(\dfrac{3}{4}\) x ... x \(\dfrac{99}{100}\)
= \(\dfrac{1}{100}\)

\(\dfrac{36}{54}\) = \(\dfrac{36:18}{54:18}\) = \(\dfrac{2}{3}\)
\(\dfrac{28}{49}\) = \(\dfrac{28:7}{49:7}\) = \(\dfrac{4}{7}\)
\(\dfrac{48}{100}\) = \(\dfrac{48:4}{100:4}\) \(\dfrac{12}{25}\)
\(\dfrac{45}{81}\) = \(\dfrac{45:9}{81:9}\) = \(\dfrac{5}{9}\)