a)\(\frac{5}{9}\times x-1=\frac{8}{9}\)

\(\frac{5}{9}\times x=\frac{8}{9}+1\)

\(\frac{5}{9}\times x=\frac{17}{9}\)

\(x=\frac{17}{9}:\frac{5}{9}\)

\(x=\frac{17}{5}\)

b)\(x+x\times\frac{1}{3}:\frac{2}{9}+x:\frac{2}{7}=252\)

\(x+x\times\frac{3}{2}+x:\frac{2}{7}=252\)

\(x.1+x.\frac{3}{2}+x.\frac{7}{2}=252\)

\(x\left(1+\frac{3}{2}+\frac{7}{2}\right)=252\)

\(x\times6=252\)

\(x=252:6\)

\(x=42\)

\(\left(\frac{3}{9}.x-5\right)^2=\frac{9}{49}\)

\(\Rightarrow\orbr{\begin{cases}\frac{3}{9}x-5=\frac{3}{7}\\\frac{3}{9}x-5=-\frac{3}{7}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}\frac{3}{9}x=\frac{3}{7}+5\\\frac{3}{9}x=-\frac{3}{7}+5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}\frac{3}{9}x=\frac{38}{7}\\\frac{3}{9}x=\frac{32}{7}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{114}{7}\\x=\frac{96}{7}\end{cases}}\)

Vậy  \(\orbr{\begin{cases}x=\frac{114}{7}\\x=\frac{96}{7}\end{cases}}\)

Chúc bạn học tốt !!!! 

x²-x³-9y+9x=-x³+x²+9x-9-9y+9=(x-1)(-x²+9-9)=-x²(x-1).

x²(x-1)+16(x-1)=(x-1)(x²+16)

a: \(\Leftrightarrow3x+9=-2x+6\)

=>5x=-3

hay x=-3/5

b: =>3/x=y/35=3/7

=>x=7; y=15

c: =>9x/5=-3/5

=>9x=-3

hay x=-1/3

d: =>x+2/26=-1/4

=>x+2=-13/2

hay x=-17/2

a: \(x^2+6x+9=x^2+2\cdot x\cdot3+3^2=\left(x+3\right)^2\)

2: \(\frac{x}{x-2y}+\frac{x}{x+2y}+\frac{4xy}{4y^2-x^2}\)

\(=\frac{x\left(x+2y\right)+x\left(x-2y\right)-4xy}{\left(x-2y\right)\left(x+2y\right)}\)

\(=\frac{x^2+2xy+x^2-2xy-4xy}{\left(x-2y\right)\left(x+2y\right)}=\frac{2x^2-4xy}{\left(x-2y\right)\left(x+2y\right)}\)

\(=\frac{2x\left(x-2y\right)}{\left(x-2y\right)\left(x+2y\right)}=\frac{2x}{x+2y}\)

c: \(\frac{x}{5x+5}-\frac{x}{10x-10}\)

\(=\frac{x}{5\left(x+1\right)}-\frac{x}{10\left(x-1\right)}\)

\(=\frac{2x\left(x-1\right)-x\left(x+1\right)}{10\left(x+1\right)\left(x-1\right)}=\frac{2x^2-2x-x^2-x}{10\left(x+1\right)\left(x-1\right)}\)

\(=\frac{x^2-3x}{10\left(x+1\right)\left(x-1\right)}\)

xX là biến hả 

phải tìm x rồi giải nha bạN