( 51 x 52 - 49 x 48 ) x ( 45 x 128 ) x ( 45 x128 - 90 x 64) x ( 1995 x 1996 x 1997)

= ( 51 x 52 - 49 x 48 ) x ( 45 x 128 ) x ( 5760 - 5760 ) x ( 1995 x 1996 x 1997)

= ( 51 x 52 - 49 x 48 ) x ( 45 x 128 ) x 0 x ( 1995 x 1996 x 1997)

= 0.

#Y/n

a: 56:x+23=37-23

=>56:x+23=14

=>56:x=14-23=-9

=>\(x=-\frac{56}{9}\) (loại)

b: 122-4(x-1)=-34+64

=>122-4(x-1)=30

=>4(x-1)=122-30=92

=>x-1=23

=>x=23+1=24(nhận)

c: \(\left(2x+1\right)^2=108:4\)

=>\(\left(2x+1\right)^2=27\)

=>\(\left[\begin{array}{l}2x+1=3\sqrt3\\ 2x+1=-3\sqrt3\end{array}\right.\Rightarrow\left[\begin{array}{l}2x=3\sqrt3-1\\ 2x=-3\sqrt3-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac{3\sqrt3-1}{2}\left(loại\right)\\ x=\frac{-3\sqrt3-1}{2}\left(loại\right)\end{array}\right.\)

d: \(\frac{\left(\left|x\right|-3\right)}{2}=3^2+5^2\)

=>|x|-3=2(9+25)=2*34=68

=>|x|=71

=>x=71(nhận) hoặc x=-71(nhận)

\(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)

\(\Rightarrow\frac{27}{23}-\frac{4}{23}+\frac{1}{2}-\frac{4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)

\(\Rightarrow1+0< x< \frac{7}{3}+\frac{3}{3}\)

\(\Rightarrow1< x< \frac{10}{3}\)

\(\Rightarrow1< x< 3,333333333\)

\(\Rightarrow x\in\left\{2;3\right\}\)

Vậy : ....

ta co : \(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)

  =>  \(1< x< \frac{10}{3}\)

vi x la so nguyen => \(1< x\le3\)

con lai ban tu lam

\(4-24=x-9-23\)

\(\Rightarrow-20=x-32\)

\(\Rightarrow x=12\)
 

Bài làm :

\(4-\left(27-3\right)=x-\left(13-4\right)-23\)

\(\Leftrightarrow x-\left(13-4\right)-23=4-\left(27-3\right)\)

\(\Leftrightarrow x-9-23=4-24\)

\(\Leftrightarrow x=-20+23+9\)

\(\Leftrightarrow x=12\)

Học tốt

a: =>3(x+4)=115

=>x+4=115/3

hay x=103/3

b: =>\(8^3\cdot\left(12x-64\right)=4\cdot8^4\)

\(\Leftrightarrow12x-64=32\)

=>12x=96

hay x=8

c: \(\Leftrightarrow\left(4x+28\right)\cdot23+55=175\)

=>(4x+28)x23=120

=>4x+28=120/23

=>4x=-524/23

hay x=-131/23