a: \(\Leftrightarrow\left(\dfrac{x+2001}{5}+1\right)+\left(\dfrac{x+1999}{7}+1\right)+\left(\dfrac{x+1997}{9}+1\right)+\left(\dfrac{x+1995}{11}+1\right)=0\)

=>x+2006=0

=>x=-2006

b: \(\Leftrightarrow\left(\dfrac{x-15}{100}-1\right)+\left(\dfrac{x-10}{105}-1\right)+\left(\dfrac{x-100}{5}-1\right)=\left(\dfrac{x-100}{15}-1\right)+\left(\dfrac{x-105}{10}-1\right)+\left(\dfrac{x-110}{5}-1\right)\)

=>x-105=0

=>x=105

52,5

999-x+500-100=105

999-x+500=105+100

999-x+500=205

999-x=205-500

999-x=295

x=999-295

x=704

k mik mik k lai

704

tk mình nha

105+(75-105)-(-100+75)
=105+75-105+100-75
=(105-105)+(75-75)+100
=0+0+100
=100

= 105 +(75 -105 ) - (100 + 75)

=105 + 75 - 105  + 100 - 75

= (105 - 105 ) + (75 -75) +100

=0 + 0 + 100

=100

                                CHÚC BN HOK TỐT NHỚ K VHO MIK NHÉ~~~~

=4,7*\(\left(1+105\right)\)0+4,7: 0,25 -4,7: 1/10

=4,7*1060+4,7: 0,25 -4,7: 1/10

=4,7*1060+4,7: 1/4 - 4,7: 1/10

=4,7*1060+4,7* 4/1 - 4,7 *10/1

=4,7*\(\left(1060+4\right)\)- 4,7 *10/1

=4,7*1064 - 4,7 *10

=4,7*\(\left(1064-10\right)\)

=4,7*1054

=4953,8

a, 100 - 7 x ( x - 5 ) = 58

7 x ( x - 5 ) = 100 - 58

7 x ( x - 5 ) = 42

( x - 5 ) = 42 : 7

x - 5 = 6

x = 6 + 5

x = 11

b, 24 + 5 * x = 49

5 * x = 49 - 24

5 * x = 25

x = 25 : 5

x = 5

c, x - 105 : 21 = 15

x - 5 = 15

x = 15 + 5

x = 20

d, ( x - 105 ) : 21 = 15

( x - 105 ) = 15 x 21

x - 105 = 315

x = 315 + 105

x = 420

458 x 105 + 324 x 105 + 217 x 105 +105

= 105 x ( 458 + 324 + 217 + 1 )

= 105 x 1000

= 105000

Đây bạn nhé. Nhớ k cho mk nha

a: Bảng thu gọn:

b: Trung bình mẫu là:

\(\overline{x} = \frac{\sum x_i n_i}{N} = \frac{100 \cdot 4 + 101 \cdot 3 + 102 \cdot 4 + 103 \cdot 3 + 104 \cdot 3 + 105 \cdot 3}{20} = \frac{2048}{20} = 102{,}4\text{ cm}\)

\(\sum x_i^2 n_i = 100^2 \cdot 4 + 101^2 \cdot 3 + 102^2 \cdot 4 + 103^2 \cdot 3 + 104^2 \cdot 3 + 105^2 \cdot 3 = 209762\)

Phương sai của mẫu là:

\(s^2 = \frac{1}{N} \sum x_i^2 n_i - \overline{x}^2 = \frac{209762}{20} - (102{,}4)^2 = 10488{,}1 - 10485{,}76 = 2{,}34\)

Phương sai mẫu hiệu chỉnh là:

\(s^2_{hc} = \frac{N}{N - 1} s^2 = \frac{20}{19} \cdot 2{,}34 \approx 2{,}463\)

a: Bảng thu gọn:

b: Trung bình mẫu là:

\(\overline{x} = \frac{\sum x_i n_i}{N} = \frac{100 \cdot 4 + 101 \cdot 3 + 102 \cdot 4 + 103 \cdot 3 + 104 \cdot 3 + 105 \cdot 3}{20} = \frac{2048}{20} = 102{,}4\text{ cm}\)

\(\sum x_i^2 n_i = 100^2 \cdot 4 + 101^2 \cdot 3 + 102^2 \cdot 4 + 103^2 \cdot 3 + 104^2 \cdot 3 + 105^2 \cdot 3 = 209762\)

Phương sai của mẫu là:

\(s^2 = \frac{1}{N} \sum x_i^2 n_i - \overline{x}^2 = \frac{209762}{20} - (102{,}4)^2 = 10488{,}1 - 10485{,}76 = 2{,}34\)

Phương sai mẫu hiệu chỉnh là:

\(s^2_{hc} = \frac{N}{N - 1} s^2 = \frac{20}{19} \cdot 2{,}34 \approx 2{,}463\)