a/ 

14536 – x  = 3928

x            = 14536 - 3928

x            = 10608

b/ x : 255 = 203

x       = 203 × 255

x    = 51765

c

C

14536  -  X   =   3928   

       X   = 14536 – 3928          

 X    =  10608         

bậc của đơn thức 7^2 xy^4 z562 là B 6 có 2+4

a:abc=305

b:acb=325

325

305

acb trước đáy nhé

B

B

a: \(\frac{3^{10}\cdot\left(-5\right)^{21}}{\left(-5\right)^{20}\cdot3^{12}}=\frac{-3^{10}\cdot5^{21}}{3^{12}\cdot5^{20}}=\frac{-5}{3^2}=-\frac59\)

b: \(\frac{-11^5\cdot13^7}{11^5\cdot13^8}=\frac{-11^5}{11^5}\cdot\frac{13^7}{13^8}=-\frac{1}{13}\)

c: \(2^{10}\cdot3^{10}-2^{10}\cdot3^9\)

\(=2^{10}\cdot3^9\cdot\left(3-1\right)\)

\(=2^{11}\cdot3^9\)

Ta có: \(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}\)

\(=\frac{2^{11}\cdot3^9}{2^{10}\cdot3^9}=2\)

d: \(5^{11}\cdot7^{12}+5^{11}\cdot7^{11}\)

\(=5^{11}\cdot7^{11}\left(7+1\right)=5^{11}\cdot7^{11}\cdot8\)

\(5^{12}\cdot7^{12}+9\cdot5^{11}\cdot7^{11}\)

\(=5^{11}\cdot7^{11}\left(5\cdot7+9\right)\)

\(=5^{11}\cdot7^{11}\left(35+9\right)=5^{11}\cdot7^{11}\cdot44\)

Ta có: \(\frac{5^{11}\cdot7^{12}+5^{11}\cdot7^{11}}{5^{12}\cdot7^{12}+9\cdot5^{11}\cdot7^{11}}\)

\(=\frac{5^{11}\cdot7^{11}\cdot8}{5^{11}\cdot7^{11}\cdot44}=\frac{8}{44}=\frac{2}{11}\)

A. 2/5 + 3/10 = 7/10 

B. 9/2 - 3/8 = 33/8

C. 4*7/20 (dấu * là gì thế?)

a,=4/10+3/10=7/10

b,36/8-3/8=33/8

c,4.7/20=7/5

(x+3728):2 = 3928

x+3728 = 3928x2

x+3728 = 7856

x = 7856 - 3728

x=4128

tong cua x va 3728 la 3928x2=7856

=>x=7856-3728=4128

tick nha!