a)x=4-12=-8

b)x=19-0=19

c)x=-12+4:2=-4

d)x=6+(-2):2=2

Bài 15:

a: 2x+x=45

=>3x=45

=>\(x=\frac{45}{3}=15\)

b: 2x+7x=918

=>\(x\cdot\left(7+2\right)=918\)

=>9x=918

=>\(x=\frac{918}{9}=102\)

c: 2x+3x=60+5

=>5x=65

=>\(x=\frac{65}{5}=13\)

d: \(11x+22x=33\cdot2\)

=>33x=66

=>\(x=\frac{66}{33}=2\)

Bài 14:

a: (12-x)(2-x)=0

=>\(\left[\begin{array}{l}12-x=0\\ 2-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=12\\ x=2\end{array}\right.\)

b: (x-33)(11-x)=0

=>\(\left[\begin{array}{l}x-33=0\\ 11-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=33\\ x=11\end{array}\right.\)

c: (21-x)(12-x)=0

=>\(\left[\begin{array}{l}21-x=0\\ 12-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=21\\ x=12\end{array}\right.\)

d: (50-x)(x-150)=0

=>\(\left[\begin{array}{l}50-x=0\\ x-150=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=50\\ x=150\end{array}\right.\)

Bài 13:

a: (x-2)(x-3)=0

=>\(\left[\begin{array}{l}x-2=0\\ x-3=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=2\\ x=3\end{array}\right.\)

b: (x-3)(x-4)=0

=>\(\left[\begin{array}{l}x-3=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=4\end{array}\right.\)

c: (x-7)(6-x)=0

=>\(\left[\begin{array}{l}x-7=0\\ 6-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=7\\ x=6\end{array}\right.\)

d: (x-3)(x-13)=0

=>\(\left[\begin{array}{l}x-3=0\\ x-13=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=13\end{array}\right.\)

\(a,\left(x-3\right)^2-x\left(x-4\right)=5\\ \Rightarrow x^2-6x+9-x^2+4x=5\\ \Rightarrow-2x=-4\\ \Rightarrow x=2\\ b,x\left(x-6\right)+2x-12=0\\ \Rightarrow x\left(x-6\right)+2\left(x-6\right)=0\\ \Rightarrow\left(x+2\right)\left(x-6\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=-2\\x=6\end{matrix}\right.\)

a)(x+2).(x+3)-(x-2).(x+5)=10

  ( x^2 +3x+2x+6)-(x^2 +5x-2x-10)=10

 x^2 +3x+2x+6-x^2 -5x+2x+10-10=0

 2x+6=0

2x=-6

x=-3

b: \(3x^2-2x-1=0\)

=>\(3x^2-3x+x-1=0\)

=>\(\left(x-1\right)\left(3x+1\right)=0\)

=>\(\left[{}\begin{matrix}x-1=0\\3x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{3}\end{matrix}\right.\)

a: Bạn ghi lại đề đi bạn

|x - 4| + |6 - x| = 0

|x  - 4| ; |6 - x| \(\ge\) 0

=> |x - 4| = |6 - x| = 0

|x - 4| = 0 => x= 4

|6 - x| = 0 => x=  6

Vì \(4\ne6\) n ê n không có giá trị của x

Bạn làm các câu khác tương tự 

a) \(\frac{3}{4}-\left(\frac{1}{2}:x+\frac{1}{2}\right)=\frac{3}{5}\)

\(\Leftrightarrow\frac{1}{2}:x+\frac{1}{2}=\frac{3}{4}-\frac{3}{5}\)

\(\Leftrightarrow\frac{1}{2}:x+\frac{1}{2}=\frac{15}{20}-\frac{12}{20}\)

\(\Leftrightarrow\frac{1}{2}:x+\frac{1}{2}=\frac{13}{20}\)

\(\Leftrightarrow\frac{1}{2}:x=\frac{13}{20}-\frac{1}{2}\)

\(\Leftrightarrow\frac{1}{2}:x=\frac{13}{20}-\frac{10}{20}\)

\(\Leftrightarrow\frac{1}{2}:x=\frac{3}{20}\)

\(\Leftrightarrow x=\frac{1}{2}:\frac{3}{20}\)

\(\Leftrightarrow x=\frac{1}{2}.\frac{20}{3}=\frac{10}{3}\)

Vậy: \(x=\frac{10}{3}\)

b) \(3x.\left(\frac{1}{2}.x-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}3x=0\\\frac{1}{2}x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\\frac{1}{2}x=1\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\x=1:\frac{1}{2}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\x=2\end{cases}}}\)

Vậy: \(x\in\left\{0;2\right\}\)

c) \(\left(4-x\right)\left(2x+3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}4-x=0\\2x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\2x=3\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=4\\x=\frac{3}{2}\end{cases}}}\)

Vậy: \(x\in\left\{4;\frac{3}{2}\right\}\)

d) \(\frac{4}{-3}=\frac{-12}{x}\)

\(\Leftrightarrow4x=\left(-12\right).\left(-3\right)\)

\(\Leftrightarrow4x=36\)

\(\Leftrightarrow x=9\)

Vậy: \(x=9\)

e) \(\frac{4x}{-3}=\frac{12}{-x}\)

\(\Leftrightarrow4x.\left(-x\right)=12.\left(-3\right)\)

\(\Leftrightarrow-4x^2=-36\)

\(\Leftrightarrow x^2=9\)

\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)

Vậy: \(x\in\left\{3;-3\right\}\)

a,Ta có: 3/4-(1/2:x+1/2)=3/5

                  -(1/2:x+1/2)=3/5-3/4

                  -(1/2:x+1/2)=-3/20

                      1/2:x+1/2=3/20

                             1/2:x=3/20-1/2

                             1/2:x=-7/20

                                   x=1/2:-7/20

                                   x=-10/7

b,Ta có: 3x.(1/2x-1)=0

 Với 3x=0 =>x=0

vói1/2x-1=0

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