1/2+1/4+1/8 +.....+1/120+1/124+1/128
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a, 1+2+3+4+....+2001+2002=(2002+1).[(2002-1)+1] :2
=2003.1001
= 2005003
1: \(347\cdot2^2-2^2\cdot\left(216+184\right):8\)
\(=347\cdot4-4\cdot400:8\)
\(=347\cdot4-4\cdot50=4\cdot\left(347-50\right)=4\cdot297=1188\)
2: \(132-\left\lbrack116-\left(132-128\right)^2\right\rbrack\)
\(=132-\left\lbrack116-4^2\right\rbrack\)
=132-(116-16)
=132-100
=32
3: \(16:\left\lbrace400:\left\lbrack200-\left(37+46\cdot3\right)\right\rbrack\right\rbrace\)
=16:{400:[200-(37+138)]}
=16:{400:[200-175]}
=16:{400:25}
=16:16
=1
4: \(\left\lbrace184:\left\lbrack96-124:31\right\rbrack-2\right\rbrace\cdot3651\)
\(=\left\lbrace\frac{184}{96-4}-2\right\rbrace\cdot3651\)
=(184:92-2)*3651
=0
5: \(46-\left\lbrack\left(16+71\cdot4\right):15\right\rbrack-2\)
=46-[(16+284):15]-2
=46-300:15-2
=46-20-2
=46-22
=24
6: \(3^3\cdot18+72\cdot4^2-41\cdot18\)
\(=18\left(3^3-41\right)+72\cdot16\)
\(=18\cdot\left(27-41\right)+18\cdot64\)
=18(-14+64)
=18*50
=900
7: \(\left(56\cdot46-25\cdot23\right):23\)
\(=56\cdot\frac{46}{23}-25\)
=112-25
=87
8: \(\left(28\cdot54+56\cdot36\right):21:2\)
\(=18\cdot28\left(3+2\cdot2\right):42\)
\(=18\cdot\frac{28}{42}\cdot7=18\cdot\frac23\cdot7=12\cdot7=84\)
9: \(\left(76\cdot34-19\cdot64\right):\left(38\cdot9\right)\)
\(=\frac{19\cdot\left(4\cdot34-64\right)}{38\cdot9}=\frac{4\cdot34-64}{9\cdot2}=\frac{4\cdot\left(34-16\right)}{18}=4\)
10: \(\left(2+4+6+\cdots+100\right)\cdot\left(36\cdot333-108\cdot111\right)\)
\(=\left(2+4+6+\cdots+100\right)\cdot36\cdot111\left(3-3\right)\)
=0
11: \(\left(5\cdot4^{11}-3\cdot16^5\right):4^{10}\)
\(=\left(5\cdot4^{11}-3\cdot4^{10}\right):4^{10}\)
\(=5\cdot\frac{4^{11}}{4^{10}}-3\cdot\frac{4^{10}}{4^{10}}\)
=20-3
=17
12: \(\frac{7256\cdot4375-725}{3650+4375\cdot7255}=\frac{7255\cdot4375+4375-725}{7255\cdot4375+3650}\)
\(=\frac{7255\cdot4375+3650}{7255\cdot4375+3650}\)
=1
X x (1/2+1/4+1/8+1/16+1/32+1/64+1/128) = 127/128
X x 127/128 = 127/128
X = 127/128 : 127/128
X = 1
b: A=1/3+1/9+...+1/3^10
=>3A=1+1/3+...+1/3^9
=>A*2=1-1/3^10=(3^10-1)/3^10
=>A=(3^10-1)/(2*3^10)
c: C=3/2+3/8+3/32+3/128+3/512
=>4C=6+3/2+...+3/128
=>3C=6-3/512
=>C=1023/512
d: A=1/2+...+1/256
=>2A=1+1/2+...+1/128
=>A=1-1/256=255/256
`1/2+1/4+1/8+...+1/128`
`=1/2x2+1/4x2+1/8x2+...+1/128x2`
`=1+1/2+1/4+1/8+...+1/64`
`=1+1/2+1/4+1/8+...+1/64-1/2-1/4-1/8-...-1/128`
`=1-1/128`
`=127/128`
Sửa đề: \(\frac12+\frac14+\frac18+\cdots+\frac{1}{512}+\frac{1}{1024}+\frac{1}{2048}\)
Đặt \(A=\frac12+\frac14+\frac18+\cdots+\frac{1}{512}+\frac{1}{1024}+\frac{1}{2048}\)
=>\(2\times A=1+\frac12+\frac14+\cdots+\frac{1}{256}+\frac{1}{512}+\frac{1}{1024}\)
=>2A-A=\(1+\frac12+\frac14+\cdots+\frac{1}{1024}-\frac12-\frac14-\frac18-\cdots-\frac{1}{2048}\)
=>\(A=1-\frac{1}{2048}=\frac{2047}{2048}\)