5.2+x=-10

10+x=-10

x=-10-10

x=-20

x=10-5,2

x=4,8

k nhé

Answer:

\(5.2^2+(x+3)=5^2\)

\(⇒5.4+x+3=25\)

\(⇒20+x+3=25\)

\(⇒(20+3)+x=25\)

\(⇒23+x=25\)

\(⇒x=2\)

\(3^2.2+(x+5)^2=10^2\)

\(⇒9.2+x+25=100\)

\(⇒x+43=100\)

\(⇒x=57\)

ko biet

1/5.2^x+1/3.2^x.2=1/5.2^7+1/3.2^7.2

2x(1/5+1/3.2)=2^7(1/5+1/3.2)

=>2^x=2^7
=> x=7

a)\(51-\left(3+x\right)=26\\ \Leftrightarrow51-3-x=26\\ \Leftrightarrow x=51-3-26\\ \Leftrightarrow x=22\)

b)Ta có:\(Ư_{\left(24\right)}=\left\{1;2;3;4;6;8;12;24\right\}\)

mà x>10⇒x=\(\left\{12;24\right\}\)

c)\(5.2^2-\left(18:3+2021^0\right)=5.4-6=20-6=14\)

Thank

1; 5.2² + (\(x\) + 3) = 5²

   5.4  +  (\(x\) + 3) = 25

    20 + (\(x\) + 3) = 25

             \(x\) + 3 = 25 - 20

             \(x+3\) = 5

             \(x\)       = 5  - 3

            \(x\)        = 2

            Vậy \(x=2\)

2; 2³ + (\(x\) - 3²) = 5³ - 4³

   8 +  (\(x\) - 9)    = 125 - 64

   8 + (\(x\) - 9) = 61

         \(x\) - 9 = 61 - 8

         \(x\) - 9 = 53

        \(x\)        = 53  + 9

        \(x\)       = 62

        Vậy \(x\) = 62

Ta có: \(x=5\cdot2^{2020}-5\cdot2^{2018}+5\cdot2^{2016}-\cdots-5\cdot2^6+5\cdot2^4-5\cdot2^2+5\)

\(=5\left(2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\right)\)

Đặt \(A=2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\)

=>\(4A=2^{2022}-2^{2020}+2^{2018}-2^{2016}+\cdots+2^6-2^4+2^2\)

=>\(4A+A=2^{2022}-2^{2020}+2^{2018}-2^{2016}+\cdots+2^6-2^4+2^2+2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\)

=>\(5A=2^{2022}+1\)

TA có: \(x=5\left(2^{2020}-2^{2018}+2^{2016}-2^{2014}+\cdots+2^4-2^2+1\right)\)

=>x=5A

=>\(x=2^{2022}+1\)

=>\(x-y=2^{2022}+1-2^{2022}=1\)

=>x và y là hai số tự nhiên liên tiếp

Kết quả cuối cùng của S là 10