làm rồi :

b: =12+5/14-3-5/7-5-5/14

=4-5/7

=28/7-5/7=23/7

c: =(-2/5-11/10)+(7/11-7/11)

=-4/10-11/10=-15/10=-3/2

\(a,\dfrac{5}{9}\cdot\dfrac{7}{13}+\dfrac{5}{9}\cdot\dfrac{8}{13}-\dfrac{5}{13}\cdot\dfrac{2}{9}\)

\(=\dfrac{5}{9}\cdot\dfrac{7}{13}+\dfrac{5}{9}\cdot\dfrac{8}{13}-\dfrac{2}{13}\cdot\dfrac{5}{9}\)

\(=\dfrac{5}{9}\cdot\left(\dfrac{7}{13}+\dfrac{8}{13}-\dfrac{2}{13}\right)\)

\(=\dfrac{5}{9}\cdot\dfrac{14}{13}\)

\(=\dfrac{70}{117}\)

\(d,\dfrac{1}{2}+\dfrac{-2}{3}+\dfrac{1}{6}+\dfrac{-2}{5}\)

\(=\left(\dfrac{1}{2}+\dfrac{-2}{3}+\dfrac{1}{6}\right)+\dfrac{-2}{5}\)

\(=0+\dfrac{-2}{5}\)

\(=\dfrac{-2}{5}\)

\(E=\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{5751}{25}+\dfrac{187}{4}}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)}\)

\(=\dfrac{\dfrac{25}{108}.\dfrac{5751}{25}+\dfrac{187}{4}}{\dfrac{100}{21}:\left(\dfrac{-44}{21}\right)}\)

\(=\dfrac{53,25+\dfrac{187}{4}}{\dfrac{-25}{11}}\)

\(=\dfrac{100}{\dfrac{-25}{11}}\)

\(=-44\)

thiếu dấu kìa bạn

ở chỗ 10 và 5/6 ấy

tính giúp mình với

Ta có: \(\left(13\frac14-2\frac{5}{27}-10\frac56\right)\cdot230\frac{1}{25}+46\frac34\)

\(=\left(13+\frac14-2-\frac{5}{27}-10-\frac56\right)\cdot230,04+46,75\)

\(=\left(1+\frac14-\frac{5}{27}-\frac56\right)\cdot230,04+46.75\)

\(=\left(\frac{108}{108}+\frac{27}{108}-\frac{20}{108}-\frac{90}{108}\right)\cdot230,04+46,75\)

\(=\frac{25}{108}\cdot230,04+46,75=53,25+46,75=100\)

Ta có: \(\left(1\frac37+\frac{10}{3}\right):\left(12\frac13-14\frac27\right)\)

\(=\left(\frac{10}{7}+\frac{10}{3}\right):\left(12+\frac13-14-\frac27\right)\)

\(=\left(\frac{30}{21}+\frac{70}{21}\right):\left(-2+\frac13-\frac27\right)\)

\(=\frac{100}{21}:\left(-2+\frac{7}{21}-\frac{6}{21}\right)=\frac{100}{21}:\left(-2+\frac{1}{21}\right)=\frac{100}{21}:\frac{-41}{21}=\frac{-100}{41}\)

Ta có: \(\frac{\left(13\frac14-2\frac{5}{27}-10\frac56\right)\cdot230\frac{1}{25}+46\frac34}{\left(1\frac37+\frac{10}{3}\right):\left(12\frac13-14\frac27\right)}\)

\(=100:\frac{-100}{41}=-41\)

a) \(\dfrac{-12}{15}+\dfrac{-4}{26}=\dfrac{-4}{5}+\dfrac{-2}{13}=\dfrac{-52-10}{65}=\dfrac{-62}{65}\)

b) \(5\dfrac{1}{3}-2\dfrac{4}{5}=\dfrac{16}{3}-\dfrac{14}{5}=\dfrac{80}{15}-\dfrac{42}{15}=\dfrac{38}{15}\)

c) \(\dfrac{4}{5}-\left(-\dfrac{2}{7}\right)+\dfrac{-5}{10}=\dfrac{4}{5}+\dfrac{2}{7}-\dfrac{1}{2}=\dfrac{56}{70}+\dfrac{20}{70}-\dfrac{35}{70}=\dfrac{41}{70}\)

d) \(-1\dfrac{2}{7}+\dfrac{3}{14}-\dfrac{5}{21}=\dfrac{-9}{7}+\dfrac{3}{14}-\dfrac{5}{21}=\dfrac{-54}{42}+\dfrac{9}{42}-\dfrac{10}{42}=\dfrac{-55}{42}\)

e) \(12-\dfrac{11}{121}+\left(\dfrac{-8}{9}\right)-\left(-\dfrac{3}{7}\right)\)

\(=12-\dfrac{11}{121}-\dfrac{8}{9}+\dfrac{3}{7}\)

\(=\dfrac{91476}{7623}-\dfrac{693}{7623}-\dfrac{6776}{7623}+\dfrac{3267}{7623}\)

\(=\dfrac{7934}{693}\)

Ta có: \(1\frac{11}{31}\cdot4\frac37-\left(15-6\frac13\cdot\frac{2}{19}\right)\)

\(=\frac{42}{31}\cdot\frac{31}{7}-\left(15-\frac{19}{3}\cdot\frac{2}{19}\right)\)

\(=\frac{42}{7}-\left(15-\frac23\right)=6-15+\frac23=-9+\frac23=-\frac{25}{3}\)

Ta có: \(4\frac56+\frac16\cdot\left(12-5\frac13\right)\)

\(=4+\frac56+\frac16\cdot\left(12-5-\frac13\right)\)

\(=4+\frac56+\frac16\cdot\left(7-\frac13\right)=4+\frac56+\frac16\cdot\frac{20}{3}=4+\frac56+\frac{20}{18}\)

\(=\frac{72}{18}+\frac{15}{18}+\frac{20}{18}=\frac{87+20}{18}=\frac{107}{18}\)

Ta có: \(A=\frac{1\frac{11}{31}\cdot4\frac37-\left(15-6\frac13\cdot\frac{2}{19}\right)}{4\frac56+\frac16\cdot\left(12-5\frac13\right)}\cdot\left(-1\frac{14}{93}\right)\cdot\frac{31}{50}\)

\(=-\frac{25}{3}:\frac{107}{18}\cdot\frac{-107}{93}\cdot\frac{31}{50}\)

\(=\frac{25}{3}\cdot\frac{18}{107}\cdot\frac{107}{93}\cdot\frac{31}{50}=\frac{31}{93}\cdot\frac{25}{50}\cdot\frac{18}{3}=\frac13\cdot6\cdot\frac12=\frac{6}{2\cdot3}=1\)

sao m ngu thế