a: =>41-(2x-5)=720:40=18

=>2x-5=23

=>2x=28

=>x=14

b: =>100x+5050=5750

=>100x=700

=>x=7

a: =>41-(2x-5)=720:40=18

=>2x-5=23

=>2x=28

=>x=14

b: =>100x+5050=5750

=>100x=700

=>x=7

720 : [ 41 - ( 2x - 5 )] = 2³.5

720: [41-(2x-5)]=40

41-(2x-5)=720:40=18

2x-5=41-18=23

2x=23+5=28

x=28:2=14

tick nha có nhiều cái làm tắt á

720 : [ 41 - (2x - 5)] = 2³ . 5

=> 720 : [ 41 - ( 2x - 5)] = 40

=> 41 - (2x - 5) = 18

=> 2x - 5 = 23

=> 2x = 28

=> x = 14

Vậy x = 14

=> (41-2x-5)=720:40

=> (41-2x-5)=18

=> 41-2x=23

=> 2x=18=>x=9

......

Bài 1: Tìm x

a) Ta có: \(\left(7x-11\right)^3=2^5\cdot5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=32\cdot25+200=1000\)

\(\Leftrightarrow7x-11=10\)

\(\Leftrightarrow7x=21\)

hay x=3

Vậy: x=3

b) Ta có: \(720:\left(41-\left(2x-5\right)\right)=2^3\cdot5\)

\(\Leftrightarrow720:\left(41-2x+5\right)=8\cdot5=40\)

\(\Leftrightarrow-2x+46=18\)

\(\Leftrightarrow-2x=18-46=-28\)

hay x=14

Vậy: x=14

c) Ta có: \(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)

\(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}\)

\(\Leftrightarrow2\cdot3^x=18\cdot3^{12}\)

\(\Leftrightarrow3^x=\dfrac{18\cdot3^{12}}{2}=9\cdot3^{12}\)

\(\Leftrightarrow3^x=3^2\cdot3^{12}=3^{14}\)

hay x=14

Vậy: x=14

=> 41 - ( 2x - 5) = 720 : 160 = 6

=> 2x - 5 = 41 - 6 

=> 2x - 5 = 35

=>2x = 40 

=> x = 20

Vậy x = 20 

Ta co: 

720:[41-(2x-5)]=120

41-(2x-5)        = 720 : 120

41 - (2x-5)      = 6

 2x  - 5          = 41 -6

2x -5             = 35

2x                 = 35 +5

2x                 = 40

x                   = 40 :2

x                   =20

​Vậy x bằng 20 

1, (1+3+5+....+2007+2009+2011)(125125.127-127127.125)

=  (1+3+5+....+2007+2009+2011)(125.1001.127-127127127.125)

=  (1+3+5+....+2007+2009+2011)(125.127127-127127.125)

=  (1+3+5+....+2007+2009+2011)  . 0

=0 

còn bài 2 đề hình như thiếu nha bn 

chúc bn học tốt!

mình viết nhầm 720:[41-(2x-5)=120