\(\dfrac{12-y}{24}=\dfrac{1}{4}\)
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a, 15/25 - 3/21 = 3/5 - 1/7 = 21/35 - 5/35 = 18/35
b, 24/36 - 6/12 = 2/3 - 1/2 = 4/6 - 3/6 = 1/6
ĐKXĐ: x<>0; x<>-1
a; \(D=\left(\frac{x+2}{3x}+\frac{2}{x+1}-3\right):\frac{2-4x}{x+1}-\frac{3x-x^2+1}{3x}\)
\(=\frac{\left(x+2\right)\left(x+1\right)+6x-3\cdot3x\left(x+1\right)}{3x\left(x+1\right)}\cdot\frac{x+1}{2-4x}+\frac{x^2-3x-1}{3x}\)
\(=\frac{x^2+3x+2+6x-9x^2-9x}{3x\left(2-4x\right)}+\frac{x^2-3x-1}{3x}\)
\(=\frac{-8x^2+2}{3x\left(-4x+2\right)}+\frac{x^2-3x-1}{3x}=\frac{8x^2-2}{3x\left(4x-2\right)}+\frac{x^2-3x-1}{3x}\)
\(=\frac{2\left(2x-1\right)\left(2x+1\right)}{3x\cdot2\cdot\left(2x-1\right)}+\frac{x^2-3x-1}{3x}=\frac{2x+1}{3x}+\frac{x^2-3x-1}{3x}=\frac{x^2-3x-1+2x+1}{3x}\)
\(=\frac{x^2-x}{3x}=\frac{x-1}{3}\)
b: Thay x=2010 vào D, ta được:
\(D=\frac{2010-1}{3}=\frac{2009}{3}\)
c: D<0
=>x-1<0
=>x<1
=>x<1 và x∉{0;-1}
d: \(\frac{1}{D}=\frac{3}{x-1}\)
1/D nguyên khi 3 ⋮x-1
=>x-1∈{1;-1;3;-3}
=>x∈{2;0;4;-2}
Kết hợp ĐKXĐ, ta được: x∈{2;4;-2}
\(\dfrac{5}{17}\times\dfrac{34}{25}=\dfrac{5\times17\times2}{17\times5\times5}=\dfrac{2}{5}\)
\(\dfrac{5}{17}\times\dfrac{34}{25}=\dfrac{5\times34}{17\times25}=\dfrac{170}{425}=\dfrac{2}{5}\)
Giải:
a) \(\dfrac{-1}{5}\le\dfrac{x}{8}\le\dfrac{1}{4}\)
\(\Rightarrow\dfrac{-8}{40}\le\dfrac{5x}{40}\le\dfrac{10}{40}\)
\(\Rightarrow5x\in\left\{0;\pm5;10\right\}\)
\(\Rightarrow x\in\left\{0;\pm1;2\right\}\)
b) \(\dfrac{4}{x-6}=\dfrac{y}{24}=\dfrac{-12}{18}\)
\(\Rightarrow\dfrac{4}{x-6}=\dfrac{-12}{18}\)
\(\Rightarrow-12.\left(x-6\right)=4.18\)
\(\Rightarrow-12x+72=72\)
\(\Rightarrow-12x=72-72\)
\(\Rightarrow-12x=0\)
\(\Rightarrow x=0:-12\)
\(\Rightarrow x=0\)
\(\Rightarrow\dfrac{y}{24}=\dfrac{-12}{18}\)
\(\Rightarrow y=\dfrac{-12.24}{18}=-16\)
c) \(\dfrac{x+46}{20}=x.\dfrac{2}{5}\)
\(\dfrac{x+46}{20}=\dfrac{2x}{5}\)
\(\Rightarrow5.\left(x+46\right)=2x.20\)
\(\Rightarrow5x+230=40x\)
\(\Rightarrow5x-40x=-230\)
\(\Rightarrow-35x=-230\)
\(\Rightarrow x=-230:-35\)
\(\Rightarrow x=\dfrac{46}{7}\)
Chúc bạn học tốt!
\(\dfrac{4}{x-6}=\dfrac{y}{24}=-\dfrac{12}{18}\)
\(x-6=\dfrac{4\cdot18}{-12}=-6\)
\(\Rightarrow x=0\)
\(y=\dfrac{24\cdot\left(-12\right)}{18}=-16\)
`4/(x-6)=(-12)/18`
`=>4/(x-6)=(-2)/3`
`=>2/(x-6)=-1/3`
`=>x-6=-6`
`=>x=0`
`y/24=(-12)/48=(-2)/3`
`=>3y=24=>y=8`
Vậy `x=0,y=8`
nhân chéo rồi tính ra thôi em :))
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