Cho m= 3/5 x (6/7 x 8/9 x 10/11 x ... x 32/33) và N = 5/6 x 7/8 x 9/10 x ... x 31/32
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a: \(8x\left(2023+x\right)-8x\left(x+2024\right)=56\)
=>\(8x\left(x+2023-x-2024\right)=56\)
=>-8x=56
=>\(x=\frac{56}{-8}=-7\) (nhận)
b: \(5-2025x=9-2026\left(x-1\right)\)
=>-2025x+5=9-2026x+2026
=>-2025x+5=-2026x+2035
=>x=2035-5=2030(nhận)
c: \(\left(-12\right)^2\cdot x=56+10\cdot13x\)
=>144x=56+130x
=>14x=56
=>x=4(nhận)
d: -(x-32+11)=(21-33-x+7)
=>-(x-21)=(-x-5)
=>-x+21=-x-5
=>21=-5(vô lý)
=>x∈∅
e: \(-2\left(x+6\right)+6\left(x+10\right)=8\)
=>-2x-12+6x+60=8
=>4x+52=8
=>4x=8-52=-44
=>\(x=-\frac{44}{4}=-11\) (nhận)
a;(18 - 9 x 2)x (2+ 4 + 6 + 8 + 10)
= (18 - 18)x (2+ 4 + 6+ 8 +10)
= 0 x (2+ 4+ 6+ 8 + 10)
= 0
b; (7 x 8 -56): (2+ 4 + 6 +8 + 112)
= (56 - 56) : (2 +4 +6+ 8+ 112)
= 0 : (2 + 4+ 6 + 8+ 112)
= 0
c; (2 + 125 + 6 + 145 + 112) x (42 - 6 x 7)
= (2+ 125+ 6 + 145+ 112) x (42 - 42)
= (2 + 125+ 6 + 145+ 112) x 0
= 0
Câu d:
(12 x 6 - 12 x 4 - 12 x 2) x (347 + 125)
= 12x(6 - 4 -2) x (347 + 125)
= 12 x (2 - 2) x (347 + 125)
= 12 x 0 x (347 + 125)
= 0 x (347 + 125)
= 0
98775 - 32 x 85
=98775 -2720
=96055
67500 - 24 x 236
= 67500 -5664
=61836
568 + 101598 : 287
= 568 +354
=922
6875 + 980 -180
=7855 -180
=7675
\(\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}\)
\(=\dfrac{7}{10}-\dfrac{1}{2}\)
= \(\dfrac{1}{5}\)
\(\dfrac{8}{11}+\dfrac{8}{33}x\dfrac{3}{4}\)
\(=\dfrac{8}{11}+\dfrac{2}{11}\)
\(=\dfrac{10}{11}\)
\(\dfrac{7}{9}x\dfrac{3}{14}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}x\dfrac{8}{5}\)
\(=\dfrac{8}{30}\)
\(=\dfrac{4}{15}\)
\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}\)
\(=\dfrac{5}{12}-\dfrac{7}{32}x\dfrac{16}{21}\)
\(=\dfrac{5}{12}-\dfrac{1}{6}\)
\(=\dfrac{5}{12}-\dfrac{2}{12}\)
\(=\dfrac{3}{12}=\dfrac{1}{4}\)
\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)
\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)
đề bài là làm gì vậy bạn?
Tính m x n nhé bạn