giúp mình với, đi mà T.T

Sao đến bài này là ko ai giúp mình vậy T.T

`#hungg`

\(Q\left(x\right)=ax^5+2x^4-2x^5-x^2+6x-3+x^4\\ =\left(ax^5-2x^5\right)+\left(2x^4+x^4\right)-x^2+6x-3\\ =\left(a-2\right)x^5+3z^4-x^2+6x-3\)

Để `Q(x)` có bậc 4 thì \(a-2=0\Rightarrow a=2\)

3^2+4^2=5^2

9+16=25

MIK CẦN CÁCH LM MAK

(X - 1005) x (1 + 3 + 5+  7 + 9 + 11) = 1989 x 1990 x (70 - 35 x 2)

(X - 1005) x (11 + 1)[(11 - 1) : 2 + 1): 2] = 1989 x 1990 x 0

(X - 1005) x 36 = 0

X - 1005 = 0 : 36

X - 1005 = 0

X = 1005

( x - 1005 ) . ( 1 + 3 + 5 + 7 + 9 + 11 ) = 1989 . 1990 . ( 70 - 35 . 2 )

( x - 1005 ) . 36 = 1989 . 1990 . ( 70 - 70 )

( x - 1005 ) . 36 = 1989 . 1990 . 0

( x - 1005 ) . 36 = 0

x - 1005 = 0

x = 1005

x-1 = 18 hoac y+5= 18

x=19 hoac y=13

(x-1).(y+5)=1.18=2.9

TH1{ x-1=1=> x=2

       {y+5=18 => y=13

TH2{x-1=18=> x=19

       {y+5=1 => y=-4

TH3{ x-1=2 => x=3

      {y+5=9 => y=4

TH4{x-1=9 => x=10

      {y+5=2 => y=-3

KL:.....

\(x+7⋮x-3\\ \Rightarrow\left(x+7\right)-\left(x-3\right)⋮x-3\\ \Rightarrow10⋮x-3\\ \Rightarrow x-3\in\left\{\pm10;\pm5;\pm2;\pm1\right\}\\ \Rightarrow x\in\left\{13;-7;8;-2;5;1;4;2\right\}\)

...= ?????????

Giải thích các bước giải:

-1+3-5+7-...+x=1000

= (-1+3)+(-5+7)+...+x=1000

= 2+2+...+x=1000

= 2 x (x−22+1):2(x−22+1):2=1000

= (x−22+1)(x−22+1)=1000

= (x−22(x−22=999

= x-2=1998

⇒x = 2000

HT nha 

\(\frac{-5}{7}< \frac{x}{21}< \frac{-3}{7}\)

\(\Rightarrow\frac{-15}{21}< \frac{x}{21}< \frac{-9}{21}\)

=> -15 < x < -9

=> x = {-14;-13;-12;-11;-10}

-5/7<x/21,-3/7 -> x/21=-4/7 -> x= -12