(3/4.x-27/50) : (-2/9) = 12/25 - 3/4

(3/4.x-27/50) : (-2/9) = -27/100

3/4.x-27/50                 = -27/100 × (-2/9)

3/4.x-27/50                   = 3/50

3/4.x                               = 3/50 + 27/50

3/4.x                                  = 3/5

x                                       = 3/5 :3/4

x                                       = 4/5

Bạn thử lại đi  nhé mình làm vội nên k bít đúng k

\(\left(\frac{3}{4}\times x-0,54\right):\frac{2}{9}=\frac{3}{4}-0,48\)

\(\left(\frac{3}{4}\times x-0,54\right):\frac{2}{9}=0,27\)

       \(\left(\frac{3}{4}\times x-0,54\right)=0,27\times\frac{2}{9}\)

         \(\left(\frac{3}{4}\times x-0,54\right)=0,06\)

                              \(\frac{3}{4}\times x=0,06+0,54\)

                                \(\frac{3}{4}\times x=0,6\)

                                            \(x=0,6:\frac{3}{4}\)

                                             \(x=0,8\)

​(3/4 *x -0.54):2/9 = 3/4- 12/25

(3/4 *x- 27/50) :2/9 =27/100

3/4*x- 27/50 = 27/100* 2/9

3/4*x-27/50 = 3/50

3/4*x = 3/50+ 27/50

3/4*x =3/5

x= 3/5:3/4= 4/5

2(x⁴+3)-(9)=17

⇒2x⁴+6+9=17

⇒2x⁴+15=17

⇒ 2x⁴=2

⇒ x⁴=1

⇒ x=\(\pm1\)

b) 5x².x+1-3.4²=-47

⇒5x³+1-48=-47

⇒5x³-47=-47

⇒5x³=0

⇒x³=0

⇒x=0

a) \(2\left(x^4+3\right)-\left(-9\right)=17\)

              \(2x^4+6+9=17\)

                           \(2x^4=2\)

                             \(x^4=1\)

                       ⇒     \(x=1\)

Bài 4:

a: |x-2|=0

=>x-2=0

=>x=2

b: |x+3|=1

=>\(\left[\begin{array}{l}x+3=1\\ x+3=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=1-3=-2\\ x=-1-3=-4\end{array}\right.\)

c: \(-3\left|4-x\right|=-9\)

=>|4-x|=3

=>|x-4|=3

=>\(\left[\begin{array}{l}x-4=3\\ x-4=-3\end{array}\right.\Rightarrow\left[\begin{array}{l}x=7\\ x=1\end{array}\right.\)

d: |2x+1|=-2

mà -2<0<=|2x+1|

nên x∈∅

Bài 5:

a: \(\left(x+3\right)^2=36\)

=>\(\left[\begin{array}{l}x+3=6\\ x+3=-6\end{array}\right.\Rightarrow\left[\begin{array}{l}x=6-3=3\\ x=-6-3=-9\end{array}\right.\)

b: \(\left(x+5\right)^2=100\)

=>\(\left[\begin{array}{l}x+5=10\\ x+5=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x=10-5=5\\ x=-10-5=-15\end{array}\right.\)

c: \(\left(2x-4\right)^2=0\)

=>2x-4=0

=>2x=4

=>x=2

d: \(\left(x-1\right)^3=27\)

=>x-1=3

=>x=4

( 3/4 . x - 0,54 ) . 4/9 + 8/75 = 4/15

( 3/4 . x - 0,54 ) . 4/9 = 4/15 - 8/75

( 3/4 . x - 0,54 ) . 4/9 = 4/25

  3/4 . x - 0,54 = 4/25 : 4/9

 3/4 . x - 0,54 = 9/25

 3/4 . x = 9/25 + 0,54

 3/4 . x = 9/10

         x = 3/4 : 9/10

         x = 5/6

\(\left(\frac{3}{4}x-0,54\right)\frac{4}{9}+\frac{8}{75}=\frac{4}{15}\)

\(\left(\frac{3}{4}x-\frac{27}{50}\right)\frac{4}{9}=\frac{4}{15}-\frac{8}{15}=\frac{-4}{15}\)

\(\frac{3}{4}x-\frac{27}{50}=\frac{-4}{15}:\frac{4}{9}=\frac{-3}{5}\)

\(\frac{3}{4}x=\frac{-3}{5}+\frac{27}{50}=\frac{-3}{50}\)

\(x=\frac{-3}{50}:\frac{3}{4}\)

\(x=\frac{-2}{25}\)

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