ai help mik lm dc ko
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Số số hạng từ 1 đến 2005 là : (2005 - 1 ) : 1 + 1 = 2005
Tổng của dãy là : [( 2005 + 1 ) x 2005 ] : 2 = 2011015
=> Tổng biểu thức trên là : 2011015 : 2006 = \(\frac{2005}{2}\)
= 1+2+3+...+2005/2006
Số lượng số hạng từ 1 -> 2005 là :
(2005 -1 ):1 + 1 = 2005 (số)
Tổng số các hạng từ 1 -> 2005 là :
(2005 + 1) x 2005 : 2 = 2011015.
= 2011015/2006 = 2005/2
Nếu như do mạng thì cái j mik cx ko vô dc chứ nhưng đàng này chỉ có hộp tin nhắn là mik ko vô dc tthui, còn các cái khác mik vẫn vô nình thường mà!
có chép bài đầy đủ ko bạn vì ai chép bài đầy đủ sẽ làm được
Where I was born and grew up in Hanoi. The city’s children is a growing modern city. Roads wander wide. The way the two buildings grow up san suicide. Hanoi’s most beautiful at night, then coats the city as a new coat. Where Where electric lighting as I am sa. They are the parents area for walking in the West Lake. In the air is cool and fresh. Lake blue, a cosmic giant carpet. Coastal lakes are found standing tilt touches down in their reflected nothing more of a young woman doing coast. I am very proud of themselves as citizens Hanoi. The people of Hanoi elegance and hospitality.
hok tốt
If you are weak in English as you said, and the teacher knows that you are weak in English, you cannot expect to turn in a paper that suddenly shows that you are really good in writing an essay, can you?Maybe some members will intentionally write a rather bad paper for you to reflect your true weakness. I think a smart teacher can always find out whether some students are truly doing their homework or just copy from other people’s work. That’s the reason why when some posters asked for help with their homework, I really hesitate to help because in the long run, I will do them no favor, and I could hurt them once the teachers find out that they could not do exercises that well in a closed exam in class.
\(ĐK:x\ne\pm2\\ 1,E=\dfrac{x^2+x^2-3x+2-x-2}{\left(x-2\right)\left(x+2\right)}=\dfrac{2x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{2x}{x+2}\\ 2,E=\dfrac{3}{4}\Leftrightarrow\dfrac{2x}{x+2}=\dfrac{3}{4}\Leftrightarrow3x+6=8x\Leftrightarrow x=\dfrac{6}{5}\left(tm\right)\\ 3,\left|x-4\right|=2\Leftrightarrow\left[{}\begin{matrix}x-4=2\\4-x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\left(tm\right)\\x=2\left(ktm\right)\end{matrix}\right.\Leftrightarrow x=6\\ \Leftrightarrow E=\dfrac{6\cdot2}{6+2}=\dfrac{12}{8}=\dfrac{3}{2}\)



a: \(=\dfrac{-1}{4}x^4y^5\)
Bậc là 9
b: \(=x^3y^6\)
Bậc là 9
\(a,-\dfrac{1}{5}x^3y^2\dfrac{5}{4}xy^3=\left(-\dfrac{1}{5}.\dfrac{5}{4}\right)\left(x^3.x\right)\left(y^2.y^3\right)=\dfrac{-1}{4}x^4y^5\)
Bậc là 9
\(b,-3xy^4\left(-\dfrac{1}{3}\right)x^2y^2=\left[\left(-3\right)\left(-\dfrac{1}{3}\right)\right]\left(x.x^2\right)\left(y^4.y^2\right)=x^3y^6\)
Bậc là 9