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a: \(-\frac{10}{3}+\frac{13}{10}-\frac16+\frac{7}{10}\)
\(=\left(-\frac{10}{3}-\frac16\right)+\left(\frac{13}{10}+\frac{7}{10}\right)\)
\(=-\frac{21}{6}+\frac{20}{10}=-\frac72+2=-\frac32\)
b: \(1-\frac{20}{6}+\frac{39}{30}-\frac{4}{24}+\frac{34}{50}\)
\(=1-\frac{20}{6}+\frac16+1,3+0,68\)
\(=1-\frac{19}{6}+1,98=2,98-\frac{19}{6}=\frac{298}{100}-\frac{19}{6}=\frac{-56}{300}=\frac{-14}{75}\)
c: \(\frac{15}{24}-\frac{6}{26}+\frac{28}{48}-\frac{30}{39}+\frac{10}{24}\)
\(=\left(\frac{15}{24}+\frac{10}{24}+\frac{28}{48}\right)-\left(\frac{3}{13}+\frac{10}{13}\right)\)
\(=\left(\frac{25}{24}+\frac{14}{24}\right)-1=\frac{39}{24}-1=\frac{15}{24}=\frac58\)
d: \(-\frac{5}{10}+\frac{12}{28}-\frac{3}{27}-\frac{7}{18}+\frac{20}{35}\)
\(=-\frac12+\frac37-\frac19-\frac{7}{18}+\frac47\)
\(=\left(-\frac12-\frac19-\frac{7}{18}\right)+\left(\frac37+\frac47\right)=-1+1=0\)
\(a,\\ 52^2+52.48=52.52+52.48=52.\left(52+48\right)=52.100=5200\\ b,\\ 39^2-39.29=39.39-39.29=39.\left(39-29\right)=39.10=390\\ c,\\ 99.5^3+125=99.125+125=125.\left(99+1\right)=125.100=12500\)
a) 52² + 52 . 48 = 2704 + 2496 = 5200
b) 39² - 39 . 29 = 1521 - 1131 = 390
c) 99 . 5³ + 125 = 99 . 125 + 125 = 12375 + 125 = 12400
= 929923859
HT