-2/3lxl + 1/4/7 = 11/14 Tìm x
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a/ \(78-5.|x-1|=-35+43.\)
\(78-5.|x-1|=8\)
\(5.|x-1|=78-8\)
\(5.|x-1|=70\)
\(|x-1|=70:5\)
\(|x-1|=14\)
\(\orbr{\begin{cases}x-1=14\\x-1=-14\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=15\\x=-13\end{cases}}\)Vậy :.....
b/ \(\left(3.|x|-2^4\right).7^3=2.7^4\)
\(\left(3.|x|-2^4\right)=2.7^4:7^3\)
\(3.|x|-2^4=2.7=14\)
\(3.|x|=14+2^4=14+16=30\)
\(|x|=30:3=10\)
\(\orbr{\begin{cases}x=10\\x=-10\end{cases}}\)Vậy : .....
Nhớ k cho mình nhé! Thank you!!!
\(a.\dfrac{1}{2}:3+x=\dfrac{14}{5}\)
\(\dfrac{1}{6}+x=\dfrac{14}{5}\)
\(=>x=\dfrac{79}{30}\)
\(b.\dfrac{8}{5}:x:\dfrac{7}{4}=\dfrac{11}{6}\)
\(\left(\dfrac{8}{5}\cdot\dfrac{4}{7}\right):x=\dfrac{11}{6}\)
\(\dfrac{32}{35}:x=\dfrac{11}{6}\)
\(x=\dfrac{192}{385}\)
\(c.\dfrac{24}{10}+x:\dfrac{3}{4}=\dfrac{11}{3}\)
\(x:\dfrac{3}{4}=\dfrac{11}{3}-\dfrac{24}{10}\)
\(x:\dfrac{3}{4}=\dfrac{38}{30}\)
\(=>x=\dfrac{19}{20}\)
\(a,\dfrac{1}{2}:3+x=\dfrac{14}{5}\\ \Leftrightarrow x+\dfrac{1}{6}=\dfrac{14}{5}\\ \Leftrightarrow x=\dfrac{79}{30}\\ b,\dfrac{8}{5}:x:\dfrac{7}{4}=\dfrac{11}{6}\\ \Leftrightarrow x=\dfrac{192}{385}\\ c,\dfrac{24}{10}+x:\dfrac{3}{4}=\dfrac{11}{3}\\ \Leftrightarrow\dfrac{4}{3}x=\dfrac{19}{15}\\ \Leftrightarrow x=\dfrac{19}{20}\)
\(x=\frac{19}{11}\cdot\frac{5}{14}+\frac{1}{11}\cdot\frac57-\sqrt{\frac{25}{4}}\cdot\frac{2}{11}\)
\(=\frac{5}{11}\cdot\frac{19}{14}+\frac{5}{11}\cdot\frac17-\frac52\cdot\frac{2}{11}\)
\(=\frac{5}{11}\left(\frac{19}{14}+\frac17-1\right)=\frac{5}{11}\left(\frac{19}{14}+\frac{2}{14}-\frac{14}{14}\right)=\frac{5}{11}\cdot\frac{7}{14}=\frac{5}{11}\cdot\frac12=\frac{5}{22}\)
a) \(\left|-\frac{2}{11}+\frac{3}{22}x\right|-\frac{1}{2}=\frac{5}{7}\)
=> \(\left|-\frac{2}{11}+\frac{3}{22}x\right|=\frac{17}{14}\)
=> \(\orbr{\begin{cases}-\frac{2}{11}+\frac{3}{22}x=\frac{17}{14}\\-\frac{2}{11}+\frac{3}{22}x=-\frac{17}{14}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{215}{21}\\x=-\frac{53}{7}\end{cases}}\)
b) \(-\frac{7}{8}x-5\frac{3}{4}=3\)
=> \(-\frac{7}{8}x-\frac{23}{4}=3\)
=> \(-\frac{7}{8}x=3+\frac{23}{4}=\frac{35}{4}\)
=> \(x=\frac{35}{4}:\left(-\frac{7}{8}\right)=\frac{35}{4}\cdot\left(-\frac{8}{7}\right)=-10\)
c) \(2x+\left(-\frac{2}{7}\right)-7=-11\)
=> \(2x-\frac{2}{7}-7=-11\)
=> \(2x=-11+7+\frac{2}{7}=-\frac{26}{7}\)
=> \(x=\left(-\frac{26}{7}\right):2=-\frac{13}{7}\)
d) \(\frac{3}{7}+x:\frac{14}{15}=\frac{1}{2}\)
=> \(x:\frac{14}{15}=\frac{1}{2}-\frac{3}{7}=\frac{1}{14}\)
=> \(x=\frac{1}{14}\cdot\frac{14}{15}=\frac{1}{15}\)

