\(=4^2+4^3+192=192+16+64=192+80=272\)

4⁹ : 4⁷ + 4 . 4² + 192

= 4² + 4³ + 192

= 16 + 64 + 192

= 272

\(54:3^1+6.5^2\)
\(=54:3+6.25\)
\(=18+150\)
\(=168\)
\(---------\)
\(11-13+15-17+19-21+23-25\)
\(=\left(11-13\right)+\left(15-17\right)+\left(19-21\right)+\left(23-25\right)\)
\(=\left(-2\right)+\left(-2\right)+\left(-2\right)+\left(-2\right)\)
\(=\left(-2\right).4\)
\(=-8\)

mn giúp min bài này vs ạ

Bạn nên viết đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để mọi người hiểu đề của bạn hơn nhé.

Ta có:

$\dfrac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}$

$=\dfrac{2^{10}\cdot2\cdot5\cdot5^6+5^{10}\cdot2^8}{2^8\cdot5^4+2^5\cdot5^7}$

$=\dfrac{2^{11}\cdot5^7+2^8\cdot5^{10}}{2^8\cdot5^4+2^5\cdot5^7}$

$=\dfrac{2^8\cdot5^7(2^3+5^3)}{2^5\cdot5^4(2^3+5^3)}$

$=\dfrac{2^3\cdot5^3}{1}$

$=8\cdot125$

$=1000.$

a/ 26176

b/ 8

c/472392

d/ Ko tính dc

Thấy mình đẳng cấp ko

Cho mình 10 k nhé

$\textbf{A)}$

$A=\dfrac{4^2\cdot36+64^4}{16^4\cdot100}$

$=\dfrac{576+2^{24}}{2^{16}\cdot2^2\cdot5^2}$

$=\dfrac{576+16777216}{1638400}$

$=\dfrac{16777792}{1638400}$

$=\dfrac{262153}{25600}.$

a) \(\frac{75^3.3^7}{81^4.5^6}=\frac{5^3.3^3.5^3.3^7}{\left(3^4\right)^4.5^6}=\frac{5^6.3^3.3^7}{3^{16}.5^6}=\frac{3^{10}}{3^{16}}=\frac{1}{3^6}=\frac{1}{729}\)
b) \(\frac{6^6.4^2}{3^{12}.2^8}=\frac{2^6.3^6.\left(2^2\right)^2}{3^{12}.2^8}=\frac{2^6.3^6.2^4}{3^{12}.2^8}=\frac{2^{10}.3^6}{3^{12}.2^8}=\frac{2^2.1}{3^6}=\frac{4}{729}\)
c) \(\frac{34^5.2^5}{2^{14}.17^5}=\frac{2^5.17^5.2^5}{2^{14}.17^5}=\frac{2^{10}}{2^{14}}=\frac{1}{2^4}=\frac{1}{16}\)

 1/2 x 2 mũ n cộng 4 x 2 mũ n = 9 x 2 mũ n