4/6x5/4
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\(x=\)\(\frac{-30}{11}nha\)\(bạn\)\(!!!!!!!!\)
\(tk\)\(mik\)\(nha\)\(!!!!!!!!!!!!!\)
(6x5:X)+15=4
30:X=4-15=-11
=>X=30:(-11)=-\(\frac{30}{11}\)
hihi, chúc bn hk tốt nha >,<
=(30+7-37)x(1+2+3+4+5+6+7+8+9+10)
=(37-37)x(1+2+3+4+5+6+7+8+9+10)
=0x(1+2+3+4+5+6+7+8+9+10)
=0
126 x 56 + 94
= (12 x 5)6 + 94
= 606 + 94
= 46656000000 + 6561
=46656006561
a, 25 \(\times\)66 + 33 \(\times\) 25 + 25
= 25 \(\times\) 66 + 33 \(\times\) 25 + 25 \(\times\)1
= 25 \(\times\) ( 66 + 33 + 1)
= 25 \(\times\) ( 66 + 34)
= 25\(\times\) 100
2500
\(\dfrac{2}{3}\) \(\times\) \(\dfrac{9}{7}\) + \(\dfrac{4}{6}\) \(\times\) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\)
= \(\dfrac{2}{3}\) \(\times\) \(\dfrac{9}{7}\) + \(\dfrac{2}{3}\) \(\times\) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\) \(\times\) 1
= \(\dfrac{2}{3}\) \(\times\) ( \(\dfrac{9}{7}\) + \(\dfrac{5}{7}\) - 1)
= \(\dfrac{2}{3}\) \(\times\) ( 2 - 1)
= \(\dfrac{2}{3}\) \(\times\) 1
= \(\dfrac{2}{3}\)
=(30+7-37)*(1+2+3+4+5+6+7+8+9+10)
=0*(1+2+3+4+5+6+7+8+9+10)
=0
( 6 x 5 + 7 - 37)x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 +9 + 10)
0 x 55 = 0
a: \(3^4=3^4;9^3=\left(3^2\right)^3=3^{2\cdot3}=3^6\)
mà \(3^4<3^6\)
nên \(3^4<9^3\)
b: \(A=1+2+2^2+\cdots+2^{2017}\)
=>\(2A=2+2^2+2^3+\cdots+2^{2018}\)
=>\(2A-A=2+2^2+2^3+\cdots+2^{2018}-1-2-2^2-\cdots-2^{2017}\)
=>\(A=2^{2018}-1\)
=>A=B
c: \(16^{19}=\left(2^4\right)^{19}=2^{4\cdot19}=2^{76};8^{25}=\left(2^3\right)^{25}=2^{3\cdot25}=2^{75}\)
mà \(2^{76}<2^{75}\)
nên \(16^{19}<8^{25}\)
d: \(5^{23}=5\cdot5^{22}<6\cdot5^{22}\)
e: \(5^{36}=\left(5^3\right)^{12}=125^{12}\)
\(11^{24}=\left(11^2\right)^{12}=121^{12}\)
mà 125>121
nên \(5^{36}>11^{24}\)
5 Đấy Bạn
4
\(\frac{20}{24}=\frac{5}{6}\)k nha