a ) 15 

b ) 100

\(12,45\times x-0,45\times x+x=3,9.\)

\(\Leftrightarrow x\times\left(12,45-0,45+1\right)=3,9.\)

\(\Leftrightarrow x\times13=3,9.\)

\(\Leftrightarrow x=0,3.\)

Vậy \(x=0,3.\)

a) 15 b)100

giup mình với

theo đề bai ==>x thuộc ƯCLN(54,72,90)

Lại có ƯCLN(54,72,90)=18

==>x=18

Cảm ơn bn Việt Anh

a) 15

b) 100

a) 15

b) 100 

~HT~

k cho mik nha

1: 48-3(x+5)=24

=>3(x+5)=48-24=24

=>x+5=8

=>x=3

2: \(2x-2^0=3^5:3^3\)

=>\(2x-1=3^2=9\)

=>2x=9+1=10

=>\(x=\frac{10}{2}=5\)

3: \(1230:3\left(x-20\right)=10\)

=>3(x-20)=1230:10=123

=>x-20=41

=>x=41+20

=>x=61

4: 390-(x-7)=169:13

=>390-(x-7)=13

=>x-7=390-13=377

=>x=377+7

=>x=384

\(\text{a) 49 : x + 56 : x = 7 }\\ 105:2x=7\\ 2x=105:7\\ 2x=15\\ x=\dfrac{15}{2}\)

\(a.49:X+56:x=7\)                    \(b.\left(390:x-90:x\right)=3\)

\(\left(49+56\right):x=7\)                              \(\left(390-90\right):x=3\)

\(105:x=7\)                                        \(300:x=3\)

\(x=105:7=15\)                                 \(x=300:3=100\)

\(\left(x-3\right)\left(x^2+3x+9\right)+x\left(x+2\right)\left(2-x\right)=1\)

\(x^3-3^3+x\left(2^2-x^2\right)=1\)

\(x^3-27+4x-x^3=1\)

\(4x-27=1\)

\(4x=28\)

\(x=7\)

Vậy x = 7

\(\left(x-3\right)\left(x^2+3x+9\right)+x\left(x+2\right)\left(2-x\right)=1\)

\(\Rightarrow x^3-3^3+x\left(2^2-x^2\right)=1\)

\(\Rightarrow x^3-27+4x-x^3=1\)

\(\Rightarrow4x-27=1\)

\(\Rightarrow4x=28\)

\(\Rightarrow x=7\)

Vậy \(x=7\)